曲面方程的切平面方程问题 高数,求曲面在某点处的切平面方程

\u7b2c\u5341\u9898\u6c42\u8be6\u89e3\u8fc7\u7a0b\uff0c\u66f2\u9762\u5e73\u884c\u4e8e\u5e73\u9762\u7684\u5207\u5e73\u9762\u65b9\u7a0b\u3002\uff1f\uff1f\uff1f\uff1f


\u8bbe\u66f2\u9762\u65b9\u7a0b\u4e3a F\uff08X\uff0cY\uff0cZ\uff09\u3002

\u5176\u5bf9X Y Z\u7684\u504f\u5bfc\u5206\u522b\u4e3a Fx\uff08X\uff0cY\uff0cZ\uff09\uff0cFy\uff08X\uff0cY\uff0cZ\uff09 \uff0cFz\uff08X\uff0cY\uff0cZ\uff09\u3002

\u5c06\u70b9\uff08a\uff0cb\uff0cc\uff09\u4ee3\u5165\u5f97 n\uff1d\uff3bFx\uff0cFy\uff0cFz\uff3d \uff08\u5207\u5e73\u9762\u6cd5\u5411\u91cf\uff09\u3002

\u518d\u5c06\u5207\u70b9\uff08a\uff0cb\uff0cc\uff09\u4ee3\u5165\u5f97\u3002

\u5207\u5e73\u9762\u65b9\u7a0bFx\uff0a\uff08X\uff0da\uff09\uff0bFy\uff0a\uff08Y\uff0db\uff09\uff0bFz\uff08Z\uff0dc\uff09\uff1d0\u3002

\uff08\u6c42\u5207\u5e73\u9762\u65b9\u7a0b\u7684\u5173\u952e\u662f\u901a\u8fc7\u6c42\u504f\u5bfc\u6570\u5f97\u5230\u5207\u5e73\u9762\u6cd5\u5411\u91cf\uff09\u3002

\u6269\u5c55\u8d44\u6599\uff1a
\u5e73\u9762\u7684\u6cd5\u5411\u91cfN\uff0c N \uff1d \uff08A\uff0c B\uff0c C\uff09\uff0c M M\u7684\u4efb\u610f\u4e24\u70b9\u7684\u98de\u673a\uff0c\u6709N\u3002\u6beb\u7c73\uff1d 0\uff0cMM\u201d\uff1d \uff08x0 x \uff0d y \uff0d y0\uff0c z \uff0d z0\uff09\uff0c\u4e00\u4e9b\u6cd5\u56fd\u5e73\u9762\u65b9\u7a0b\uff1aB \uff08x \uff0d x0\uff09 \uff0b \uff08y \uff0d y0\uff09 \uff0b C \uff08z \uff0d z0\uff09 \uff1d 0\u3002

\u4e09\u4e2a\u70b9\u7ec4\u6210\u7684\u5e73\u9762\u53ef\u4ee5\u7528\u65b9\u5411\u7684\u4e58\u79ef\u6765\u5f52\u4e00\u5316\u3002

\u4efb\u4f55\u4e09\u5143\u7ebf\u6027\u65b9\u7a0b\u7684\u56fe\u5f62\u90fd\u662f\u4e00\u4e2a\u5e73\u9762\uff0c\u5176\u4e2dx\uff0cy\uff0c z\u7684\u7cfb\u6570\u90fd\u662f\u5e73\u9762\u6cd5\u5411\u91cf\u7684\u5750\u6807\u3002

\u5b83\u4eec\u76f8\u4e92\u5782\u76f4\u5b83\u4eec\u5c31\u7b49\u4e8eA1A2 \uff0b B1B2 \uff0b C1C2 \uff1d 0\u3002

\u5e73\u884c\u6216\u91cd\u53e0\u7684\u5e73\u9762\u4e5f\u5c31\u662fA1\uff0fA2\uff1dB1\uff0fB2\uff1dC1\uff0fC2\u3002

\u70b9\u5230\u5e73\u9762\u7684\u8ddd\u79bb\uff1dabs\uff08Ax0\uff0bBy0\uff0bCz0\uff0bD\uff09\uff0f\u221a\uff08A\u65b9\uff0bB\u65b9\uff0bC\u65b9\u3002
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u5e73\u9762\u65b9\u7a0b

令 f(x,y,z)=z-e^z+2xy-3 ,
则 f 对 x、y、z 的偏导数分别为 2y、2x、1-e^z ,
由此得点(1,2,0)处的切平面的法向量为 n=(4,2,0),
因此切平面方程为 4(x-1)+2(y-2)=0 ,即 2x+y-4=0 ,
法线方程为 (x-1)/4=(y-2)/2=(z-0)/0 。

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