用python语言将一组数9，8，7，1，2进行逆序输出。 用Python写一个 输入10个数，从大到小排序，并输出前五...
python\u91cc\u3002\u8f93\u516512678,\u8f93\u51fa,\u5012\u5e8f\u8f93\u51fa\u4e3a8,7,6,2,1X\uff1dlist (input())
for i in range(len(X)-1\uff0c-1\uff0c-1)\uff1a
print(X[i],end\uff1d'\uff0c')
a = input('\u8f93\u516510\u4e2a\u6570\u5b57(\u7528\u7a7a\u683c\u5206\u9694):')
b = sorted(a.split(),reverse=True)
c = sum(map(int,b[:5]))
print('\u524d\u4e94\u4e2a\u6570\u636e\u7684\u548c\u4e3a:{0}\n{1}'.format(c,b))
\u9009\u4e00\u4e2a\u5427
a=[9,8,7,1,2]
print(a[::-1])
print(sorted(a,key=lambda x:a.index(x),reverse=True))
a.reverse() #上面两行都不是原地改值，这一行reverse是原地改值，所有没有返回值。
print(a)
两种方法，一种是把数组逆排序以后，顺序输出，另一种就是直接从-1开始 -2 这样输出到0位。第一种的方法直接用［::-1］生成逆序。
a = []
for i in range(5): #5是数组长度
a.append(int(input())) #输入数组
for i in range(len(a)-1,-1,-1):
print(a[i])
非常简单
lis = [9,8,7,1,2]
for index in range(-1,-len(lis)-1,-1):
缩进 print(lis[index])
绛旓細a=[9,8,7,1,2]print(a[::-1])print(sorted(a,key=lambda x:a.index(x),reverse=True))a.reverse() #涓婇潰涓よ閮戒笉鏄師鍦版敼鍊硷紝杩欎竴琛宺everse鏄師鍦版敼鍊硷紝鎵鏈夋病鏈夎繑鍥炲笺俻rint(a)
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绛旓細鎴戝彧鍐欎竴涓嚱鏁帮細\x0d\x0a>>> def littleFunc():\x0d\x0a data =[] #鍒濆鍖栧垪琛╘x0d\x0a for i in range(9):#涓涓猣or寰幆\x0d\x0a num = int(raw_input("input a number please: "))#鎺у埗杈撳叆杞负int\x0d\x0a data.append(num)#鏀惧叆鍒楄〃\x0d\x0a data.sort(...
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绛旓細绛旓細鐢0鍒100涓鍏辨湁11涓暟鍙互闄や互涔濓紝瀹冧滑鍒嗗埆鏄0锛9锛18锛27锛36锛45锛54锛63锛72锛81锛90銆傚彲浠ョ敤涓嬮潰鐨python绋嬪簭鏉ユ眰瑙ｏ細count = 0 for i in range(101):if i % 9 == 0:count += 1 print(count)
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