python如何定义一个函数求列表各项数据平均值?

# coding = GBK

a =[1,2,3,4,5]

sum=0

b = len(a)

print("这个数组的长度为:",b)

for i  in a:

 sum =sum +i

print("这个数组之和为:",sum)

print("这个数组平均数为",sum/b)

import sys

sum = 0

cnt = 0

f = open('1.txt', 'r')

files = f.readline()

while (files ):

sum = sum + float(files .split(",")[0])

cnt = cnt + 1

files = f.readline()

print(sum / cnt)

f.close()

或者。

#!/usr/bin/env pythonimport timeimport numpy as np 

dd = np.random.randint(0, 20, size=(2*1000*1000))t_start = time.clock()avg_sum1 =

0.0BlockOffset = 0     while BlockOffset < len(dd):

if dd[BlockOffset + 1] <= 10:

avg_sum1 += dd[BlockOffset + 1] * 0.1

else:

avg_sum1 += dd[BlockOffset + 0] * 0.01

BlockOffset += 2print('Avg: ' + str(avg_sum1 / len(dd) / 2))    print('Exe time: ' +

str(time.clock() - t_start))

扩展资料:

python 实现求和、计数、最大最小值、平均值、中位数、标准偏差、百分比。

import sys  

class Stats:

def __init__(self, sequence):

# sequence of numbers we will process

# convert all items to floats for numerical processing

self.sequence = [float(item) for item in sequence]

def sum(self):

if len(self.sequence) < 1:

return None

else:

return sum(self.sequence)

def count(self):

return len(self.sequence)

def min(self):

if len(self.sequence) < 1:

return None

else:

return min(self.sequence)

def max(self):

if len(self.sequence) < 1:

return None

else:

return max(self.sequence)

def avg(self):

if len(self.sequence) < 1:

return None

else:

return sum(self.sequence) / len(self.sequence)   

def median(self):

if len(self.sequence) < 1:

return None

else:

self.sequence.sort()

return self.sequence[len(self.sequence) // 2]

def stdev(self):

if len(self.sequence) < 1:

return None

else:

avg = self.avg()

sdsq = sum([(i - avg) ** 2 for i in self.sequence])

stdev = (sdsq / (len(self.sequence) - 1)) ** .5

return stdev

def percentile(self, percentile):

if len(self.sequence) < 1:

value = None

elif (percentile >= 100):

sys.stderr.write('ERROR: percentile must be < 100.  you supplied: %s
'% percentile)

value = None

else:

element_idx = int(len(self.sequence) * (percentile / 100.0))

self.sequence.sort()

value = self.sequence[element_idx]

return value

参考资料来源:百度百科-python



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