下面的物理题求详细解答。谢谢了！ 物理题，求高手！！！ （要详细解答，谢谢！！）
\u6c42\u8fd93\u4e2a\u7269\u7406\u9898\u7684\u8be6\u7ec6\u89e3\u7b54\u8fc7\u7a0b\uff0c\u8c22\u8c22\uff01\uff083\uff09\uff1aF=\u03c1*a*b*c*g=2.2g/cm³*20cm*10cm*5cm*10N/Kg=22N
P\uff08\u6700\u5927)=10000F/\uff08bc\uff09=220000/\uff0810*5\uff09=4400Pa
P\uff08\u6700\u5c0f\uff09=10000F/\uff08ab\uff09=220000/\uff0820*10\uff09=1100Pa
\uff084): F=40000Kg*10N/Kg=400000N
P=F/S=400000N/5m²=8X10^4Pa\uff1c7X10^5Pa
\u6240\u4ee5\u53ef\u4ee5\u901a\u8fc7\u51b0\u51bb\u6cb3\u9762
\uff085\uff09\uff1aS=M/\u03c1=8.9Kg/(8.9X10^3Kg/m³)=0.001m³
F=Kg*g=8.9Kg*10N/Kg=89N
P=F/S=89N/0.001m³=8.9X10^4Pa
\u6c42\u91c7\u7eb3
1.\u98de\u884c\u5458\u5728\u7ad6\u76f4\u5e73\u9762\u5185\u505a\u5706\u5468\u8fd0\u52a8\u65f6\uff0c\u4e0d\u7ba1\u5728\u6700\u9ad8\u70b9\u8fd8\u662f\u6700\u4f4e\u70b9\u90fd\u662f\u53ea\u53d7\u91cd\u529b\u548c\u684c\u6905\u7ed9\u4ed6\u7684\u652f\u6301\u529b\uff0c\u6839\u636e\u725b\u987f\u7b2c3\u5b9a\u5f8b\uff0c\u98de\u884c\u5458\u53d7\u5230\u7684\u652f\u6301\u529b\u548c\u4ed6\u5bf9\u684c\u6905\u7684\u538b\u529b\u662f\u4e00\u5bf9\u76f8\u4e92\u4f5c\u7528\u529b\uff0c\u5927\u5c0f\u76f8\u7b49\u65b9\u5411\u76f8\u53cd\uff0c\u52a0\u4e0a\u672c\u8eab\u684c\u6905\u7684\u6570\u636e\u9898\u76ee\u90fd\u6ca1\u7ed9\u51fa\uff0c\u6240\u4ee5\u6211\u4eec\u6c42\u538b\u529b\u53ea\u8981\u6c42\u98de\u884c\u5458\u53d7\u5230\u7684\u652f\u6301\u529b\u5c31\u597d\u4e86\uff0c\u4e0b\u9762\u7ed9\u51fa\u8fc7\u7a0b\uff1a
\u5728\u6700\u9ad8\u70b9\uff0c\u91cd\u529b\u5411\u4e0b\uff0c\u652f\u6301\u529b\u5411\u4e0a\uff0c\u91cd\u529b\u6307\u5411\u5706\u5fc3\uff0c\u6240\u4ee5mg-F=mv^2/R,\u6240\u4ee5F=mg-mv^2/R\uff0c\u8fd9\u91cc\u7684F\u8868\u793a\u5728\u6700\u9ad8\u70b9\u7684\u652f\u6301\u529b\uff1b\u5728\u6700\u4f4e\u70b9\uff0c\u91cd\u529b\u5411\u4e0b\uff0c\u652f\u6301\u529b\u5411\u4e0a\uff0c\u652f\u6301\u529b\u6307\u5411\u5706\u5fc3\uff0c\u6240\u4ee5f-mg=mv^2/R\uff0cf\u8868\u793a\u6700\u4f4e\u70b9\u7684\u652f\u6301\u529b\u7684\u5927\u5c0f\uff0c\u5219f=mv^2/R+mg\uff0c\u6240\u4ee5f-F=mv^2/R+mg-\uff08mg-mv^2/R\uff09=2mv^2/R\u5373\u98de\u884c\u5458\u5728\u6700\u4f4e\u70b9\u5bf9\u684c\u6905\u7684\u538b\u529b\u6bd4\u5728\u6700\u9ad8\u70b9\u59272mv^2/R
2\u3002\u2460\u7531\u9898\u610f\uff0c\u7269\u4f53\u673a\u68b0\u80fd\u5b88\u6052\uff0c\u5219\u6709\u521d\u59cb\u673a\u68b0\u80fd\u4e3aE1=mgh+mv1^2/2\uff0c\u5728\u52a8\u80fd\u548c\u91cd\u529b\u52bf\u80fd\u76f8\u7b49\u5904\uff0c\u6709E2=mv2^2/2+mgH=2mgH,\u673a\u68b0\u80fd\u5b88\u6052\uff0c\u6240\u4ee5E1=E2\uff0c\u5e26\u5165\u5404\u5f0f\uff0c\u5f97H=30m
\u2461\u5f53\u91cd\u529b\u52bf\u80fd\u4e3a\u52a8\u80fd\u4e24\u500d\u65f6\uff0c\u540c\u2460\u89e3\u6cd5\u4e00\u6837\uff0c\u521d\u59cb\u673a\u68b0\u80fdE1=mgh+mv1^2/2\uff0c\u5f53\u91cd\u529b\u52bf\u80fd\u4e3a\u52a8\u80fd\u4e24\u500d\u65f6\u7684\u673a\u68b0\u80fdE2=mv2^2/2+mgH=mgH/2+mgH=3mgH/2,\u673a\u68b0\u80fd\u5b88\u6052\uff0c\u6240\u4ee5E1=E2\uff0c\u5e26\u5165\u5404\u5f0f\uff0c\u5f97H=40m\uff0c\u6240\u4ee5\u7269\u4f53\u5728\u5f53\u91cd\u529b\u52bf\u80fd\u4e3a\u52a8\u80fd\u4e24\u500d\u65f6\u7684\u9ad8\u5ea6\u4e3a40m\uff0c\u6574\u4e2a\u8fc7\u7a0b\u4f4d\u79fb\u4e3aH-h=40m-15m=25m\uff0c\u6839\u636eH-h=V0t+gt^2/2,\u56e0\u4e3a\u505a\u7684\u662f\u51cf\u901f\u8fd0\u52a8\uff0c\u6240\u4ee5g=-10m/s^2,\u5f97t=1s\u62165s\uff0c
3.\u5bf9\u4e8e\u5e73\u629b\u8fd0\u52a8\uff0c\u7ad6\u76f4\u5206\u4f4d\u79fbH=gt^2/2 \u6c34\u5e73\u5206\u4f4d\u79fbS=vt, H=S\uff0c\u6240\u4ee5gt^2/2=vt\uff0c\u6240\u4ee5t=2V/g,C\u9519
\u6b64\u65f6\u7684\u7ad6\u76f4\u5206\u901f\u5ea6V1=gt=g*2V/g=2v,\u6c34\u5e73\u5206\u901f\u5ea6\u4e0d\u53d8\u8fd8\u662fv\uff0c\u6240\u4ee5A\u9519\uff0c\u6b64\u65f6\u7684\u901f\u5ea6V2=\u221a\uff082V)^2+v^2=\u221a5V\u6240\u4ee5B\u6b63\u786e\uff0c\u6b64\u65f6\u7684\u4f4d\u79fbx=\u221aH^2+s^2=4V^2/g\uff0c\u6240\u4ee5D\u9519
4.\u7531\u9898\u610f\uff0c\u7532\u7684\u521d\u901f\u5ea6\u8be5\u662f\u4e59\u76842\u500d\uff0c\u8981\u60f3\u8fbe\u5230\u8981\u6c42\uff0c\u4e59\u7684\u843d\u5730\u65f6\u95f4\u8be5\u662f\u7532\u76842\u500d\uff0c\u636eH=gt^2/2,t\u53d8\u4e3a\u4e24\u500d\uff0c\u6240\u4ee5H\u53d8\u4e3a\u539f\u6765\u76844\u500d\uff0c\u5728\u7b2c3\u5c42\u7684\u629b\u51fa\u9ad8\u5ea6\u662f2\u5c42\u697c\u9ad8\uff0c\u6240\u4ee5\u6b64\u65f6\u4e59\u629b\u51fa\u7684\u9ad8\u5ea6\u5e94\u8be5\u662f\u5728\u7b2c9\u5c42\uff0c\u6b63\u597d\u662f8\u5c42\u697c\u9ad8\uff0c\u539f\u6765\u76844\u500d
5.\u9009D\uff0c\u03b8\u89d2\u5e94\u8be5\u7528\u4f4d\u79fb\u5173\u7cfb\u6c42\uff0ctan\u03b8=H/s,H=gt^2/2,s=v0t,\u6240\u4ee5tan\u03b8=gt/2v0,\uff0c\u5bf9\u4e8e\u89d2\u03b2\uff0c\u5e94\u8be5\u7528\u901f\u5ea6\u5173\u7cfb\u6c42\uff0c\u843d\u70b9\u7684\u7ad6\u76f4\u5206\u901f\u5ea6Vt=gt\uff0c\u6c34\u5e73\u5206\u901f\u5ea6\u4e3av0\uff0c\u6240\u4ee5tan\u03b2=Vt/v0=gt/v0,\u6240\u4ee5tan\u03b2=Vt/v0=gt/v0=2tan\u03b8
\u89e3\u5b8c\u6536\u5de5\uff0c\u53ef\u4ee5\u7684\u8bdd\u7ed9\u4e2a\u6700\u4f73\u554a\uff0c\u4f60\u61c2\u7684 \u563f\u563f
题目中的“弹簧形变产生的力”，注意，这里主语是“弹簧”。
对于你的疑问
①力的作用是相互的，按照不同的方向，弹簧可以是受力物体也可以是施力物体
②弹簧发生了形变，它想要回到原来的状态，所以手阻止了这个过程。
。
你要仔细看题，说的是弹簧形变，就产生了向内的拉力，所以弹簧是施力物体
手向弹簧施加了向外的拉力
首先要明确这是“弹簧产生的力”所以，施力物体是弹簧。所以选答案B。
而A与C的施力物体分别是手和墙，所以都不对。
力有一个作用物和被作用物吧，题目写的“弹簧形变产生的力”，那么力的产生着也就是作用物不就是弹簧么，所以被作用物就是手喽。
绛旓細娌℃瘺鐥咃紝鏂藉姏鐗╀綋鏄脊绨э紝鎵浠ユ槸B銆棰樼洰涓殑鈥滃脊绨у舰鍙樹骇鐢熺殑鍔涒濓紝娉ㄦ剰锛岃繖閲屼富璇槸鈥滃脊绨р濄傚浜庝綘鐨勭枒闂 鈶犲姏鐨勪綔鐢ㄦ槸鐩镐簰鐨勶紝鎸夌収涓嶅悓鐨勬柟鍚戯紝寮圭哀鍙互鏄彈鍔涚墿浣撲篃鍙互鏄柦鍔涚墿浣 鈶″脊绨у彂鐢熶簡褰㈠彉锛屽畠鎯宠鍥炲埌鍘熸潵鐨勭姸鎬侊紝鎵浠ユ墜闃绘浜嗚繖涓繃绋嬨
绛旓細锛3锛夛細F=蟻*a*b*c*g=2.2g/cm³*20cm*10cm*5cm*10N/Kg=22N P锛堟渶澶)=10000F/锛坆c锛=220000/锛10*5锛=4400Pa P锛堟渶灏忥級=10000F/锛坅b锛=220000/锛20*10锛=1100Pa 锛4): F=40000Kg*10N/Kg=400000N P=F/S=400000N/5m²=8X10^4Pa锛7X10^5Pa 鎵浠ュ彲浠ラ...
绛旓細瑙ｏ細鏈夊浘鍙煡鐗╀綋鐢3鑲＄怀瀛愭壙鎷咃紝1锛夋墍浠ョ怀瀛愯繍鍔ㄧ殑璺濈s=3h=3脳2m=6m 2锛夐摑鍧楃殑璐ㄩ噺涓簃=G1/g=8100N/10N/kg=810kg 閾濆潡鐨勪綋绉疺=m/蟻=810kg/(2.7脳10^3kg/m^3)=0.3 m3 閾濆潡鍙楀埌鐨勬诞鍔汧娴=蟻姘碫鎺抔=10^3kg/m 3脳0.3 m3脳10N/kg=3脳10^3 N 閾濆潡涓婃彁2m鍋氱殑鏈夌敤鍔焀鏈...
绛旓細鈭慚A=0 -2r.cos胃.2m.g+2r.sin胃.NB=0 (3) (A涓哄崐鐞冨渾蹇冿級鏈澶ч潤鎽╂摝鍏崇郴寮忥細 F=0.5NA (4)浠ヤ笂鍥涗釜鏂圭▼鑱旂珛姹傚緱锛 NB=F=1.5m.g 銆丯A=3m.g tan胃=4/3 L=2r.cos胃+r=2r.(3/5)+r=11r/5 *鍘熼鏃犳閫夐」锛
绛旓細1.椋炶鍛樺湪绔栫洿骞抽潰鍐呭仛鍦嗗懆杩愬姩鏃讹紝涓嶇鍦ㄦ渶楂樼偣杩樻槸鏈浣庣偣閮芥槸鍙彈閲嶅姏鍜屾妞呯粰浠栫殑鏀寔鍔涳紝鏍规嵁鐗涢】绗3瀹氬緥锛岄琛屽憳鍙楀埌鐨勬敮鎸佸姏鍜屼粬瀵规妞呯殑鍘嬪姏鏄竴瀵圭浉浜掍綔鐢ㄥ姏锛屽ぇ灏忕浉绛夋柟鍚戠浉鍙嶏紝鍔犱笂鏈韩妗屾鐨勬暟鎹棰樼洰閮芥病缁欏嚭锛屾墍浠ユ垜浠眰鍘嬪姏鍙姹傞琛屽憳鍙楀埌鐨勬敮鎸佸姏灏卞ソ浜嗭紝涓嬮潰缁欏嚭杩囩▼锛氬湪鏈楂樼偣锛...
绛旓細1瑙ｏ細R=蟻L/S 蟻鏄瘑搴鏄暱搴 鏄í鎴潰绉 浣撶НV=SL 鎶婂畠鎷変几鎴愮洿寰勪负d/10鐨勫潎鍖鐢甸樆涓濅箣鍚,妯埅闈㈢Н涓篠/100,闀垮害鍙樹负100L 鎵浠ョ數闃讳负10000R 2銆佽В1銆乂=蠅R=8.0rad/s脳0.5m=4m/S P=U^2/R=(220v)^2/20惟=2420W P=FV=2420W F=P/V=2420W/4m/S=605N 3鐢垫簮缁欑數鍔ㄦ満...
绛旓細锛1锛夌敱浜庝袱涓數闃讳覆鑱旀椂锛岀數鍘嬬浉鍔狅紝鐢垫祦鐩哥瓑锛岀數闃荤浉鍔狅紙R锛漅1+R2锛17娆у锛夛紝鎵浠モ3V0.6A鈥濆拰鈥6V0.5A鈥滐紝灏嗗畠浠覆鑱斿悗鎺ュ叆鐢佃矾涓娇鐢紝鍏佽閫氳繃鐨勭數娴佸彧鑳芥槸0.5A 鎵浠ユ牴鎹儴鍒嗙數璺濮嗗畾寰婭锛漊/R鍙煡 U锛滻R锛0.5*17锛8.5V 鍏佽鍔 鐨勭數婧愮數鍘嬫渶澶т负8.5V 锛2锛夌敱浜庝袱涓數闃诲苟鑱旀椂锛...
绛旓細棣栧厛锛岃冭檻鎬诲鍔涚殑骞宠 銆傚湪灏忕悆A涓婏紝鏈変笁涓姏锛氬紶鍔汧1銆侀噸鍔沵g鍜屽悜涓嬬殑寮圭哀鍔汧a銆傝繖鍙互琛ㄧず涓猴細F1 + mg - Fa = 0 鐢变簬棰樼洰涓粰鍑篎a=mg锛屾墍浠ヤ笂杩版柟绋嬪彉涓猴細F1 + mg - mg = 0 F1 = 0 杩欐剰鍛崇潃F1鐨勫ぇ灏忎负闆讹紝鎵浠ュ皬鐞傾涓婄殑寮犲姏F1涓嶅瓨鍦ㄣ傛帴涓嬫潵锛岃冭檻鎬诲鎵煩鐨勫钩琛°傚湪杩欎釜鎯呭喌涓嬶紝...
绛旓細瑙ｏ細鍥犱负锛歅1=P2 鍙團1:F2=9:4,鍗矴1:G2=9:4 锛屾墍浠ワ細m1:m2=9:4 鏁咃細P1=P2鍙帹鍑猴細m1*g/a1^2=m2*g/a2^2 浠庤岋細a1:a2=3:2 鑰屜1=m1/a1^3 蟻2=m2/a2^3 鎵浠ワ細蟻1 锛 蟻2=锛坢1/a1^3锛夛細 锛坢2/a2^3锛=2锛3 ...
绛旓細a1 =锛圙m * 渭锛/ m = 4 / 1 = 4 锛坢/s^2)a2 = (F - f ) / M = (28 - 4)/4 = 6 锛坢/s^2)鏍规嵁浣嶇Щ鍏紡鍙婇鎰忥細S2 - S1 = 1.4 鍗筹細(1/2 * a2 * t^2) - (1/2 * a1 * t^2) = 1.4 瑙ｄ箣寰楋細t = 鏍瑰彿涓1.4 = 1.18 s ...
