oracle中使用REGEXP oracle regexp_substr中正则表达式问题

oracle\u4e2d\u4f7f\u7528regexp_substr\u53d6\u503c\u3002\uff08\u6700\u597d\u7528\u6b63\u5219\uff09

select regexp_substr(regexp_substr('','a2=".*"'),'\w+',1,2) from dual
\u7ed3\u679c\uff1ab22222\uff0c\u5982\u65e0a2\u65f6\uff0c\u503cnull

[[:alpha:]] \u4efb\u4f55\u5b57\u6bcd\u3002
[[:digit:]] \u4efb\u4f55\u6570\u5b57\u3002
[[:alnum:]] \u4efb\u4f55\u5b57\u6bcd\u548c\u6570\u5b57\u3002
[[:space:]] \u4efb\u4f55\u767d\u5b57\u7b26\u3002
[[:upper:]] \u4efb\u4f55\u5927\u5199\u5b57\u6bcd\u3002
[[:lower:]] \u4efb\u4f55\u5c0f\u5199\u5b57\u6bcd\u3002
[[:punct:]] \u4efb\u4f55\u6807\u70b9\u7b26\u53f7\u3002

select distinct regexp_substr('020101:1:13,020101:1:175,020301:1:107+020401:1:140-020501:1:107,020301:1:107*020401:1:140/020501:1:107',
'[^,|+|*|/|-]+', 1, level) as str
from dual
connect by level <= regexp_count('020101:1:13,020101:1:175,020301:1:107+020401:1:140-020501:1:107,020301:1:107*020401:1:140/020501:1:107',
'[,|+|*|/|-]') + 1
order by str;

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