C语言:5个人3门课,求输出总成绩,平均成绩

C\u8bed\u8a00\u7f16\u7a0b\uff1a\u8f93\u51655\u540d\u5b66\u751f3\u95e8\u8bfe\u7a0b\u6210\u7ee9

\u697c\u4e0a\u8bf4\u7684\u662f...\u8fd8\u6709\uff1a
stdsco \u6ca1\u6709\u8d4b\u521d\u503c\u8bf6...

\u6240\u4ee5\u7cfb\u7edf\u7ed9\u4e86\u4e00\u4e2a\u5f88\u5c0f\u7684\u503c\uff0c\u4f60\u5728 stdsco += sco;

\u8fd9\u91cc\u5b9e\u9645\u4e0a\u6ca1\u591a\u5927\u7528...\u90a3\u4e2a\u503c\u592a\u5c0f\u4e86...

\u5efa\u8bae\u5566\uff1a\u4ee5\u540e\u5728\u65b0\u5efa\u53d8\u91cf\u7684\u65f6\u5019\u5c31\u7ed9\u4ed6\u4e00\u4e2a\u521d\u503c...

\u5b9e\u73b0\u5e73\u53f0 Linux
\u6ca1\u6709\u8c03\u7528\u4ec0\u4e48\u5e93 windows\u5e73\u53f0\u53ef\u4ee5\u5b9e\u73b0
\u4ee3\u7801\u6709\u70b9\u5570\u55e6
\u53ea\u5199\u4e86\u4e00\u4e2a\u5b66\u751f\u7684 \u4f60\u770b\u4e86\u4ee5\u540e\u81ea\u5df1\u5c31\u53ef\u4ee5\u5b9e\u73b0\u540e\u9762\u7684\u5b66\u751f\u4e86
\u4f60\u662f\u521d\u5b66\u8005\u5427 \u8bb0\u5f97\u6bcf\u5929\u4e00\u5b9a\u8981\u5199\u51fa 300\u884c\u4ee3\u7801

#include

int main(void)
{
int lr[3];
int lri, LR_lr = 0, i;

printf("\u8bf7\u8f93\u5165\u7b2c\u4e00\u4e2a\u5b66\u751f\u4e09\u95e8\u6210\u7ee9\n");
printf("\u6bcf\u8f93\u5165\u4e00\u4e2a\u6210\u7ee9\u56de\u8f66\u7ed3\u675f\n");
for(i = 0; i < 3; i++)
{
scanf("%d",&lri);
lr[i] = lri;
}
for (i = 0; i < 3; i++)
{
LR_lr += lr[i];
}
printf("\u7b2c\u4e00\u4e2a\u5b66\u751f\u7684\u603b\u6210\u7ee9\u4e3a:%d\n", LR_lr);
}

设5个人3门课,求输出总成绩与平均成绩#include <stdio.h> int main(){ float score = 0.0; float score_total = 0.0; float score_average = 0.0; int n1; int n2; for(n1=0;n1<5;n1++) { for(n2=0;n2<3;n2++) { printf("请输入第%d个人的第%d门成绩:", n1, n2); scanf("%f", &score); score_total = score_total + score; } } score_average = score_total/15; printf("总成绩=%f,平均成绩=%f\n", score_total, score_average); return 0;}

#include <stdio.h>
#include <string.h>typedef struct stud{
char name[50];
float chinese;
float math;
float english;
}student;void read(student *st,int n)
{
int i;
for(i=0;i<n;i++)
{
printf("输入第%d个学生的成绩\n",i+1);
printf("语文:");
scanf("%f",&st[i].chinese);
printf("数学:");
scanf("%f",&st[i].math);
printf("英语:");
scanf("%f",&st[i].english);
}
}student total(student *st,int n)
{
int i;
student s;
strcpy(s.name,"总成绩:\0");
s.chinese=0.0;
s.math=0.0;
s.english=0.0;
for(i=0;i<n;i++)
{
s.chinese += st[i].chinese;
s.math += st[i].math;
s.english += st[i].english;
}
return s;
}student average(student *st,int n)
{
student s;
student t = total(st,n);
strcpy(s.name,"平均成绩:\0");
s.chinese = t.chinese/n;
s.math = t.math/n;
s.english = t.english/n;
return s;
}int main()
{
int i;
student st[5];
student m,n;
read(st,5);
m = total(st,5);
n = average(st,5);
printf("%s 语文:%.2f;数学:%.2f;英语:%.2f\n ",m.name,m.chinese,m.math,m.english);
printf("%s 语文:%.2f;数学:%.2f;英语:%.2f\n ",n.name,n.chinese,n.math,n.english);
return 0;
}

输出5个人所有的成绩的品均值,还是单门课程的平均值?

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