(1-cosX)/X当X趋于0时的极限是多少 求当x趋于0时,1-cosx除以x²的极限

Cos1/x \u5f53x\u8d8b\u4e8e0\u65f6\uff0c\u6781\u9650\u4e3a\u591a\u5c11\uff1f

\u6574\u4f53\u7b80\u4ecb\uff1a
\u7814\u7a76\u51fd\u6570\u7684\u6781\u9650\u662f\u6574\u4e2a\u5fae\u79ef\u5206\u7684\u4e3b\u8981\u5185\u5bb9\uff0c\u4e8b\u5b9e\u4e0a\u6709\u5f88\u591a\u51fd\u6570\u5728\u67d0\u4e9b\u70b9\u4e8b\u4e0d\u8fde\u7eed\u7684\uff0c\u50cf\u8fd9\u4e2a\u51fd\u6570\u4e00\u6837\uff0c\u5728x->0\u7684\u65f6\u5019\u662f\u9707\u8361\u7684\u3002
\u4e3b\u8981\u65b9\u6cd5\uff1a\u5229\u7528\u5fae\u79ef\u5206\u4e2d\u6781\u9650\u5b58\u5728\u6027\u7406\u8bba
\u4e3b\u8981\u8fc7\u7a0b\uff1a

\u6ce8\u610f\u4e8b\u9879\uff1a
\u5224\u65ad\u4e00\u4e2a\u51fd\u6570\u5728\u67d0\u70b9\u7684\u6781\u9650\u5b58\u4e0d\u5b58\u5728\u5173\u952e\uff0c\u770b\u5728\u8fd9\u70b9\uff08\u65e0\u8bba\u4ee5\u4ec0\u4e48\u6837\u7684\u65b9\u5f0f\u8d8b\u8fd1\uff09\u6781\u9650\u662f\u5426\u4fdd\u5b58\u4e0d\u53d8\u3002
\u53c2\u8003\u6587\u732e\uff1a
\u590d\u65e6\u5927\u5b66\u300a\u6570\u5b66\u5206\u6790\u300b

\u5f53x~0\uff0c1-cosx~1/2x^2
\u6240\u4ee5\u7ed3\u679c\u4e3a1/2

cos x=1-2(sin x/2)^2
当X趋于0时, cos x=1-(x^2)/2
原式=x/2
最后结果 0

lim(x→0)(1-cosx)/x=lim(x→0)(1-cosx)'/x'=lim(x→0)sinx=0

0

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