酸+盐——新盐+新酸的方程式10个 急~
Na2S + 2HCl = 2NaCl + H2SCH3COONa + HCl =CH3COOH + NaCl
Na2CO3 + 2HCl = 2NaCl + H2O + CO2
NaClO + HCl = NaCl + HClO
Na2SiO3 + 2HCl = H2SiO3 + 2NaCl
NaCl + H2SO4 = NaHSO4 + HCl
3NaCl + H3PO4 = Na3PO4 + 3HCl
NaBr + H2SO4 = NaHSO4 + HBr
C6H5ONa + HCl = C6H5OH + NaCl
CaCO3 + 2HNO3 = Ca(NO3)2 + H2O + CO2
绛旓細(4)KNO3 + H2SO4 = KHSO4 + HNO3 ...
绛旓細閰稿姞鐩愮敓鎴愭柊閰稿拰鏂扮洂鐨勫寲瀛︽柟绋嬪紡濡備笅锛1銆丆aCO3+2HCl==CaCl2+H2O+CO2鈫 2銆丯a2CO3+2HCl==2NaCl+H2O+CO2鈫 3銆丠Cl+AgNO3==AgCl鈫+HNO3 4銆丠2SO4+BaCl2==BaSO4鈫+2HCl 鐩愮殑閫氭 鐩愬垎涓哄崟鐩愬拰鍚堢洂锛屽崟鐩愬垎涓烘鐩愩侀吀寮忕洂銆佺⒈寮忕洂锛屽悎鐩愬垎涓哄鐩愬拰缁滅洂銆傚叾涓吀寮忕洂闄ゅ惈鏈夐噾灞炵瀛愪笌閰告牴绂诲瓙澶...
绛旓細1銆丄gNO3+HCL=AgCL+HNO3 2銆丆aCO3+2HCL=CaCL2+CO2+H2O 3銆丯aHCO3+HCL=Na+CO2+H2O 4銆丅aCO3+H2SO4=BaSO4+CO2+H2O 5銆丆aCO3+H2SO4=CaSO4+CO2+H2O 6銆丅aCL2+H2SO4=BaSO4+2HCL 7銆H2SO4+Ba锛圢O3锛2=2HNO3+BaSO4
绛旓細NaHCO3+HCl==NaCl+H2O+CO2鈫
绛旓細1.H2SO4+BaCl2===2HCl+BaSO4锛堢櫧鑹叉矇娣锛2.AgNO3+HCl===HNO3+AgCl(鐧借壊娌夋穩锛3.H2SO4+Ba锛圢O3锛2===2HNO3+BaSO4锛堢櫧鑹叉矇娣锛
绛旓細渚嬪HCl+NaHCO3鈫扤aCl+CO2+H2O锛圕O2+H2O灏辨槸纰抽吀锛夛紝鍍忚繖绫鏂圭▼寮鏈夊緢澶氾紝涓鑸槸寮洪吀鍔犱笂閰稿紡鐩愶紙褰撶劧鏄急閰哥殑閰稿紡鐩愶紝鍍忕～閰告阿閽犲氨涓嶈浜嗭級锛岀敓鎴愪竴绉嶆鐩愬拰涓绉嶅急閰革紝甯屾湜鑳藉浣犳湁鎵甯姪銆傜浣犲涓氭湁鎴愶紒锛
绛旓細閰革紜鐩愨啋鏂扮洂锛嬫柊閰 CaCO3+2HCl==CaCl2+H2O+CO2鈫 Na2CO3+2HCl==2NaCl+H2O+CO2鈫 HCl+AgNO3==AgCl鈫+HNO3 H2SO4+BaCl2==BaSO4鈫+2HCl Ba(NO3)2+H2SO4==BaSO4鈫+2HNO3 NaHCO3+HCl==NaCl+H2O+CO2鈫 鐩愶紜纰扁啋鏂扮洂锛嬫柊纰 CuSO4+2NaOH==Cu(OH)2鈫+Na2SO4 FeCl3+3NaOH==Fe(OH...
绛旓細Na2CO3 + 2HCl = 2NaCl + H2O + CO2 NaClO + HCl = NaCl + HClO Na2SiO3 + 2HCl = H2SiO3 + 2NaCl NaCl + H2SO4 = NaHSO4 + HCl 3NaCl + H3PO4 = Na3PO4 + 3HCl NaBr + H2SO4 = NaHSO4 + HBr C6H5ONa + HCl = C6H5OH + NaCl CaCO3 + 2HNO3 = Ca(NO3)2 + H2O...
绛旓細2HCL + CaCO3 == CaCL2 + H2CO3 H2CO3涓嶇ǔ瀹氾紝H2CO3 == H2O + CO2鈫 鍏充簬閰+鐩愨斺旀柊鐩+鏂伴吀锛氭甯告儏鍐典笅鏄己閰哥疆鎹㈠急閰革紝浣嗕篃鏈夊叾浠栨儏鍐碉細鈶犻珮娌哥偣閰稿埗鍙栦綆娌哥偣閰革細2NaCl+H2SO4锛堟祿锛==Na2SO4+2HCl 鈫 鈶″鍒嗚В鍙嶅簲锛欻2S + CuCL2 == CuS + 2HCL鈫 鈽嗏寬_鈱掆槅 甯屾湜鍙互甯埌you...
绛旓細閰稿拰鐩愬弽搴旂殑鍖栧鏂圭▼寮鏄細HCl+Na2CO3鈺怤aCl+H2O+CO2鈫戙傞吀涓庣洂鍙嶅簲:缁撹:閰+鐩愨啋鏂扮洂+鏂伴吀渚嬪HCl+Na2CO3鈺怤aCl+H2O+CO2鈫戠粌涔:鍐欏嚭绋纭吀涓庣⒊閰搁挔鐨勫寲瀛︽柟绋嬪紡:Na2CO3+H2SO4鈺怤a2SO4+H2O+CO2鈫戦吀涓庣洂鍙嶅簲:缁撹锛岄吀鍔犵洂鍒版柊鐩愬姞鏂伴吀渚嬪HCl+Na2CO3鈺怤aCl+H2O+CO2鈫戙傜洂涓閰哥殑鍖哄埆 浜х墿涓嶅悓...
