对于正数ab规定一种新运算⊙,a⊙b,等于由a开始的连续b个正整数的积,例如2⊙3=
6⊙（1⊙2）=6⊙（1×2）=6⊙2=6×7=42绛旓細鍥燼 @ b = (鏍瑰彿涓ab)+a+b 鏁1 @ k =(鏍瑰彿涓1*k)+1+k =(鏍瑰彿涓媖锛+1+k < 3 浠=鏍瑰彿涓媖>=0 鍒欎负 t^2+t+1< 3 鍒 t^2+t-2< 0 鍒欎负 锛坱-1锛*锛坱+2锛<0 鍒 -2<t<1 鑰宼=鏍瑰彿涓媖>=0 鍒 鏍瑰彿涓媖<1 鍒-1<k<1 鍒橩鐨勫彇鍊艰寖鍥 涓 __-1<k<1 ___...
绛旓細锛1锛夛紙2*3锛*5=[2脳3-锛2-3锛塢*5=7*5=7脳5-锛7-5锛=33锛庯紙2锛夆埖|a|a+|b|b+|c|c+|d|d鐨勫兼槸-2锛屸埓a銆乥銆乧銆乨涓湁3涓槸璐熸暟锛1涓槸璐熸暟锛屼护a銆乥銆乧涓鸿礋鏁帮紝d涓姝ｆ暟锛鍒檤ab|ab+|bc|bc+|cd|cd+|ad|ad=1+1-1-1=0锛庯紙3锛墊a-c|+b+d=|20082-2脳20084-3...
绛旓細鍏堣绠楁嫭鍙峰唴锛1.2鈥0.75=[(2*1.2)骞虫柟-0.75]/2*1.2*0.75 = 2.78333 鐒跺悗鍐嶈绠1.25鈥伙紙2.78333锛=[(2*1.25)骞虫柟-2.78333]/2*1.25*2.78333 = 0.4982
绛旓細锛1锛+鈭烇級瑙ｏ細鈭礱⊗b=鈭ab+a+b锛坅锛0锛宐锛0锛夛紝鈭1*k=鈭歬+1+k=3锛岃В寰梜=1锛堣垗璐燂級锛屸埓f锛坸锛=k⊗x=鈭歺+1+x锛屸埖f锛坸锛夊湪鍖洪棿[0锛+鈭烇級涓婁负澧炲嚱鏁帮紝f锛0锛=1锛屸埓褰搙锛0鏃讹紝f锛坸锛夛紴f锛0锛夛紝鍗砯锛坸锛夛紴1锛屽嵆鍑芥暟鐨勫煎煙涓猴細锛1锛+鈭烇級锛屾晠绛旀涓猴細...
绛旓細涔拌偂绁ㄦ槸浜忥紝鍥犱负鐢茬鑲＄エ涔颁环浣庝簬1200锛屼箼绉嶈偂绁ㄤ拱浠烽珮浜1200鎵浠ュ悓鏍锋槸20锛呭疄闄呮槸浜忎簡锛
绛旓細杩欐槸涓涓畾鐞嗭紝鍗筹細(a+b)/2 鈮 鏍瑰彿ab 绠楁湳骞冲潎鏁颁笉灏忎簬鍑犱綍骞冲潎鏁 绗竴闂瓟妗堟槸 9/2 绗簩闂瘉鏄庤繃绋嬪涓嬶細浠绘剰瀹炴暟x銆亂锛屾湁 (x锛峺)^2 鈮 0 鑳藉寰楀埌 x^2 - 2xy + y^2 鈮 0 涓よ竟鍚屾椂鍔 4xy 锛屽嵆寰楀埌 x^2 + 2xy + y^2 鈮 4xy 鏁寸悊寰楀埌 (x+y)^2 鈮 4xy ...
绛旓細鍥犱负 x*y=3 鍗硏y-x-y=3 鏄剧劧x涓嶇瓑浜1 鎵浠 锛坸-1锛墆=x+3 鎵浠 y=锛坸+3锛/锛坸-1锛夋墍浠 xy=x锛坸+3锛/锛坸-1锛=锛坸-1锛+4/锛坸-1锛+5 浠=x-1 褰0<x<1 鏃 -1<t<0 姝ゆ椂 xy<-1+4/(-1)+5=0 鍗 xy<0 褰搙>1鏃 t>0 姝ゆ椂 褰搕=2鏃讹紝xy鍙栧緱鏈灏忓 xy>=2+...
绛旓細(1)璇曠敤鏂板悎閲戜腑绗涓绉鍚堥噾鐨勯噸閲忚〃绀虹浜岀鍚堥噾鐨勯噸閲; (2)姹傛柊鍚堥噾涓惈绗簩绉嶅悎閲戠殑閲嶉噺鑼冨洿; (3)姹傛柊鍚堥噾涓惈閿扮殑閲嶉噺鑼冨洿鍕捐偂瀹氱悊棰樼洰 鎮祻鍒:0 - 瑙ｅ喅鏃堕棿:2009-4-11 16:41 濡傚浘,鍦≧t鈻矨BC涓,鈭燙=90掳,AD銆丅E鍒嗗埆鏄竟BC銆丄C涓婄殑涓嚎,涓擜D=8,BE=6,姹AB銆
绛旓細鍥犱负鏈夎繖涓瓑寮忔垚绔:A骞虫柟+ B骞虫柟>=2*A*B锛堣繖閲岀殑A骞虫柟銆丅骞虫柟閮芥槸姝ｆ暟锛鐩稿綋浜庨鐩腑鐨勬鏁般傦級鍋氫竴涓唬鎹㈡湁锛歛+b>=2鏍瑰彿ab 锛堟牴鍙穉鐩稿綋浜庝笂闈㈢殑A锛屾牴鍙穊鐩稿綋浜庝笂闈㈢殑B锛夋墍浠ョ洿鎺ユ崲灏卞嚭鏉ヤ簡銆傜涓闂細鏍瑰彿ab鈮9/2銆傜浜岄棶锛氱収鐫闅忎究鍐欙紝鍙鍓嶆彁鏄痑,b鏄鏁板氨琛屻傜涓夐棶锛氶潪璐熸暟a...
绛旓細鍥犱负a*b=ab-a-b涓攛*y=3 鎵浠*y=xy-x-y 鍗硏y-x-y=3 鍥犱负xy-x-y=3 y(x-1)-x=3 婕斿彉鍑芥暟褰㈠紡锛 y=锛3+x)/(x-1)=(x-1+4)/(x-1)=(x-1)/(x-1)+4/(x-1锛=1+4(x-1)鏁寸悊寰楋細y=1+4/(x-1)鐢诲嚭y=1+4/(x-1)鐨勫嚱鏁板浘鍍 鎶妝=4/x鐨勫弻鏇茬嚎鍑芥暟鍥惧儚娌跨潃X...
