画爱心的python代码 求问怎样用python/python turtle画“心”
\u5982\u4f55\u7528python turtle\u753b\u5fc3\u662f\u8981\u8868\u767d\u4e48\uff0c\u563f\u563f\uff0c\u5e0c\u671b\u8fd9\u4e2a\u4ee3\u7801\u80fd\u5e2e\u5230\u4f60\u54e6~\uff08\u53c2\u6570\u4e0d\u6ee1\u610f\u53ef\u4ee5\u81ea\u5df1\u8c03\uff09
import turtleimport mathwn = turtle.Screen()wn.setworldcoordinates(-2, -2, 2, 2)alex = turtle.Turtle()alex.color("red")alex.pensize(2)alex.penup()alex.speed(0)walkStart = -1walkEnd = 1i = walkStartj = walkEndwhile i = 0: y1 = math.sqrt(1 - i * i) + (i * i) ** (1/3.0) y2 = -math.sqrt(1 - i * i) + (i * i) ** (1/3.0) y3 = math.sqrt(1 - j * j) + (j * j) ** (1/3.0) y4 = -math.sqrt(1 - j * j) + (j * j) ** (1/3.0) alex.setx(i) alex.sety(y1) alex.dot() alex.sety(y2) alex.dot() alex.setx(j) alex.sety(y3) alex.dot() alex.sety(y4) alex.dot() i += 0.01 j -= 0.01wn.exitonclick()
import turtlea = turtle.Turtle()def drawlove(): a.left(45) a.forward(30) a.right(45) a.forward(30) a.right(120) a.forward(110) a.penup() a.right(150) a.forward(75) a.pendown() a.left(45) a.forward(30) a.left(45) a.forward(30) a.left(120) a.forward(110) drawlove()\u8fd9\u662f\u6211\u505a\u7684\u6bd4\u8f83\u7c97\u7565\u7684\u4e00\u4e2a
\u4ee3\u7801\u7528\u7406\u89e3\u82f1\u8bed\u7684\u65b9\u5f0f\u7406\u89e3\u5c31\u597d\uff0c\u6539\u4e0b\u6570\u636e\u505a\u4e0b\u66f4\u7cbe\u5bc6\u7684\u6570\u5b66\u8ba1\u7b97\u5c31\u597d\u4e86
我已经很努力了,但是要真的很好看爱心可能有点困难(除了贴图,但这毕竟不好,对吧)。
以下为Python代码:
from turtle import *
speed(0)#速度,觉得太快可以调到1(1慢10快0最快)
tracer(2)#显示速度,觉得太快可以调到1(同上)
hideturtle()#隐藏画笔
setup(500,500)#500×500的正方形画面
up()#提笔
goto(-150,50)#去目标点
down()#落笔
color("red","red")#画笔填充均红色
seth(90)#方向改为向上
begin_fill()#开始填充
circle(-75,180)#往右画半圆
circle(75,-180)#往右画半圆
step = 4.06635
seth(270)#向下
for i in range(90):#画椭圆
forward(step)#走步长
step = step - 0.025#逐渐缩小步长
right(1)#右转1度
for i in range(90):
step = step + 0.025#逐渐增加步长
right(1)#右转1度
forward(step)#走步长
end_fill()
以下为运行效果:
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