1、输入一个自然数，判断它是奇数或是偶数并输出。 c语言编程： 输入一个整数，判断这个数是奇数还是偶数，如果是...
\u7f16\u5199\u7a0b\u5e8f\uff1a\u8f93\u5165\u63d0\u4e00\u4e2a\u6b63\u6574\u6570\uff0c\u5224\u65ad\u8be5\u6570\u662f\u5947\u6570\u8fd8\u662f\u5076\u6570\uff0c\u5e76\u8f93\u51fa\u7ed3\u679cvoid main()
{
int a;
scanf("%d",&a);
if (a%2==0)
{
printf("\u5076\u6570");
}
else
{
printf("\u5947\u6570");
}
}
program JO;
var
a:integer;
begin
read(a);
if a mod 2=0 then
writeln('\u5076\u6570')
else
writeln('\u5947\u6570');
end.
Dim A As Integer
Input A
If A Mod 2 = 0 Then
Print "\u5076\u6570"
Else
Print "\u5947\u6570"
End If
\u4ee5\u4e0a\u5206\u522b\u662fC\u3001Pascal\u548cBasic\u7684\u7a0b\u5e8f
void main()
{
int a;
scanf("%d",&a);
if (a%2==0)
{
printf("\u5076\u6570");
}
else
{
printf("\u5947\u6570");
}
}
program JO;
var
a:integer;
begin
read(a);
if a mod 2=0 then
writeln('\u5076\u6570')
else
writeln('\u5947\u6570');
end.
Dim A As Integer
Input A
If A Mod 2 = 0 Then
Print "\u5076\u6570"
Else
Print "\u5947\u6570"
End If
\u4ee5\u4e0a\u5206\u522b\u662fC\u3001Pascal\u548cBasic\u7684\u7a0b\u5e8f
void main()
{
int a;
scanf("%d",&a);
if (a%2==0)
{
printf("\u5076\u6570");
}
else
{
printf("\u5947\u6570");
}
}
program JO;
var
a:integer;
begin
read(a);
if a mod 2=0 then
writeln('\u5076\u6570')
else
writeln('\u5947\u6570');
end.
Dim A As Integer
Input A
If A Mod 2 = 0 Then
Print "\u5076\u6570"
Else
Print "\u5947\u6570"
End If
\u4ee5\u4e0a\u5206\u522b\u662fC\u3001Pascal\u548cBasic\u7684\u7a0b\u5e8f
void main()
{
int a;
scanf("%d",&a);
if (a%2==0)
{
printf("\u5076\u6570");
}
else
{
printf("\u5947\u6570");
}
}
program JO;
var
a:integer;
begin
read(a);
if a mod 2=0 then
writeln('\u5076\u6570')
else
writeln('\u5947\u6570');
end.
Dim A As Integer
Input A
If A Mod 2 = 0 Then
Print "\u5076\u6570"
Else
Print "\u5947\u6570"
End If
\u4ee5\u4e0a\u5206\u522b\u662fC\u3001Pascal\u548cBasic\u7684\u7a0b\u5e8f
#include "stdio.h"
main()
{
int x;
printf("\u8bf7\u8f93\u5165\u4e00\u4e2a\u6574\u6570");
scanf("%d",&x);
if(x%2 == 0) printf("%d\u662f\u5076\u6570\n",x);
else printf("%d\u662f\u5947\u6570\n",x);
}
if(n%2==1)则为奇数
否则为偶数
if(n%2==0)则为偶数
否则为奇数
printf("d%",n);
第二题
0.5+0.5*0.5+……+0.5的10方
0.5的10方
第一题用输入的数除以2，判断余数是0还是1，
第二题是一个循环语句，两个变量一个记录高度，一个记录高度和。当然用递归迭代也可以。
具体代码翻翻书吧。
估计不超过15行
在我刚开始学的时候做过。。
绛旓細if(n%2==1)鍒欎负濂囨暟 鍚﹀垯涓哄伓鏁 if(n%2==0)鍒欎负鍋舵暟 鍚﹀垯涓哄鏁 printf("d%",n);绗簩棰 0.5+0.5*0.5+鈥︹+0.5鐨10鏂 0.5鐨10鏂
绛旓細```num = int(input("璇疯緭鍏ヤ竴涓嚜鐒舵暟锛"))if num % 2 == :print(num, "鏄伓鏁")else:print(num, "鏄濂囨暟")```杩欎釜绠楁硶鐨勬濇兂鏄紝鍋舵暟鍙互琚2鏁撮櫎锛屽晢涓哄伓鏁帮紝浣欐暟涓猴紱濂囨暟闄や互2寰楀埌鐨勫晢涓哄鏁帮紝浣欐暟涓1銆傚洜姝ゆ垜浠氳繃鍙栬繖涓暟瀵2鐨勬ā杩愮畻锛屽氨鍙互鍒ゆ柇杩欎釜鏁版槸濂囨暟杩樻槸鍋舵暟銆
绛旓細num = int(input())if num % 2 == 1:print("odd")else:print("even")
绛旓細闄や簩涓篴锛岄櫎浜屽彇鏁翠负b锛宎=b鍋舵暟锛屽惁鍒濂囨暟銆傝繕鍙互鍔犱釜鍓嶆彁锛屽厛鍒ゆ柇杈撳叆鐨勬暟鏄惁澶т簬绛変簬0锛屽惁鍒欐姤閿欙紝鏄垯缁х画鍒ゆ柇杈撳叆鐨勬暟鍙栨暣鏄惁绛変簬杈撳叆鐨勬暟锛屽惁鍒欐姤閿欙紝鏄垯鍒ゆ柇濂囧伓銆
绛旓細<math> if(a%2==0)b=pow(a,0.5);else b=pow(a,1/3);cout<<b<<endl;return 0;鎴栵細鏍稿績浠ｇ爜 Scanner s = new Scanner(System.in);double result;while(s.hasNextInt()){ int i = s.nextInt();if(i/2==1){ result = Math.sqrt(i);}else{ result = Math.log(i);...
绛旓細鍋舵暟鏄寚鑳藉琚2鎵鏁撮櫎鐨勬暣鏁帮紝姝ｅ伓鏁颁篃绉板弻鏁般傚鏋滄煇涓暟鏄2鐨勫嶆暟锛岄偅涔堝畠灏辨槸鍋舵暟锛屽彲浠ヨ〃绀轰负2n锛涘弽涔嬶紝瀹冨氨鏄鏁帮紝鍙互琛ㄧず涓2n+1锛坣涓烘暣鏁帮級锛屽嵆濂囨暟闄や互浜岀殑浣鏁版槸涓銆傚叧浜庡伓鏁板拰濂囨暟锛屾湁涓嬮潰鐨勬ц川锛1銆佷袱涓繛缁暣鏁颁腑蹇呮槸涓涓鏁颁竴涓鍋舵暟锛2銆佸鏁颁笌濂囨暟鐨勫拰鎴栧樊鏄伓鏁帮紱鍋舵暟涓...
绛旓細include <stdio.h>void main(){ int n; printf("璇杈撳叆涓涓鏁存暟:\n"); scanf("%d", &n); if (n%2 == 0) printf("%d 鏄伓鏁癨n", n); else printf("%d 鏄鏁癨n", n);}
绛旓細aaa=0 2,2 say '璇杈撳叆涓涓嚜鐒舵暟锛' get aaa READ if MOD(aaa,2)=0 ??'鍋舵暟'else ??'濂囨暟'endif
绛旓細 function chk(){ var numb = document.getElementById('num').value;if(numb%2 == 0){ return 0;}else{ return 1;} }
绛旓細def summ(n): if n%2: m=1 else: m=2 return round(sum([1/x for x in range(m,n+1,2)]),2)print(summ(5))
