用C语言表示从键盘输入一个十进制整数,如果大于60,则在屏幕上输出“成功”,否则在屏幕上输出“失败”。

\u6c47\u7f16\u8bed\u8a00\u7a0b\u5e8f\u8bbe\u8ba1 (\u4ece\u952e\u76d8\u8f93\u5165\u4e24\u4e2a\u4e00\u4f4d\u5341\u8fdb\u5236\u6570\uff0c\u8ba1\u7b97\u8fd9\u4e24\u4e2a\u6570\u4e4b\u548c\uff0c\u5e76\u5c06\u7ed3\u679c\u5728\u5c4f\u5e55\u4e0a\u663e\u793a\uff09

code segment
assume cs:code
start:
mov cx,2
mov bl,0
next:
mov ah,1
int 21h
sub al,30h
jc next
cmp al,9h
ja next
add al,bl
daa
mov bl,al
mov dl,13
mov ah,2
int 21h
mov dl,10
int 21h
loop next

mov cl,4
mov dh,2
next1:
rol bl,cl
mov dl,bl
and dl,0fh
add dl,30h
mov ah,2
int 21h
dec dh
jnz next1
mov ah,1
int 21h
mov ah,4ch
int 21h
code ends
end start

#include"stdio.h"
#define N 10
void main()
{
int i,j,tmp,a[N];
printf("please input %d number:",N);
for(i=0;i<N;i++)
{
scanf("%d",&a[i]);
}
for(i=0;i<N;i++)
{
for(j=i+1;j<N;j++)
{
if(a[i]<a[j])
{
tmp=a[i];
a[i]=a[j];
a[j]=tmp;
}
}
}
printf("now a:");
for(i=0;i<N;i++)
printf("%d ",a[i]);
}
\u001a

#include "stdio.h"
main()
{
int n;
printf("输入一个十进制整数:\n");
scanf("%d",&n);
if(n>60)
printf("成功!");
else
printf("失败!");

}

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