编程实现以上二叉树中序遍历操作,输出遍历序列,求写代码~~ 用C语言编程实现二叉树的中序遍历算法

\u6c42\u95ee\u4e2aC\u8bed\u8a00\u95ee\u9898 \u5df2\u77e5\u4e8c\u53c9\u6811\u904d\u5386\u7684\u4e2d\u5e8f\u5e8f\u5217\u548c\u540e\u5e8f\u5e8f\u5217 \u8f93\u51fa\u5148\u5e8f\u5e8f\u5217 \u6c42\u4ee3\u7801

#include
#include
#define MAX 50
using namespace std;
typedef char Elem_Type;
typedef struct BiTree
{
Elem_Type data;//\u6570\u636e
struct BiTree *Lchild;//\u5de6\u5b69\u5b50
struct BiTree *Rchild;//\u53f3\u5b69\u5b50
}BiTree;
//\u8981\u67e5\u627e\u7684\u5143\u7d20 \u67e5\u627e\u7684\u5730\u65b9 \u6570\u7ec4\u7684\u957f\u5ea6
int Search_Num(Elem_Type num, Elem_Type *array, int len)
{
for (int i = 0; i<len; i++)
if (array[i] == num)
return i;
//return -1;//\u6ca1\u6709\u627e\u5230
} //\u524d\u5e8f\u7ed3\u679c\u6570\u7ec4 \u4e2d\u5e8f\u7ed3\u679c\u6570\u7ec4 \u6570\u7ec4\u957f\u5ea6

//\u6839\u636e\u4e2d\u540e\u5e8f\u751f\u6210\u4e8c\u6811
BiTree *Resume_BiTree(Elem_Type *post, Elem_Type *center, int len)
{
if (len <= 0)
return NULL;
BiTree *temp = new BiTree;
temp->data = post[len - 1];//\u540e\u5e8f\u6700\u540e\u4e00\u4e2a\u5143\u7d20\u5373\u4e3a\u6839\u5143\u7d20
int index = Search_Num(temp->data, center, len);
//\u904d\u5386\u5de6\u5b69\u5b50 \uff08\u540e\u5e8f\u7ed3\u679c\u4e2d\uff0c\u4ece\u7b2c0\u4e2a\u5143\u7d20\u5f00\u59cb\u5230\u7b2cindex-1\u4e2a\u5143\u7d20\u90fd\u662f\u5de6\u5b50\u6811\uff09
temp->Lchild = Resume_BiTree(post, center, index);
//\u904d\u5386\u53f3\u5b69\u5b50 \uff08\u540e\u5e8f\u7ed3\u679c\u4e2d\uff0c\u4ece\u7b2cindex\u4e2a\u5143\u7d20\u5f00\u59cb\u5230\u7b2cLen-2\u4e2a\u5143\u7d20\u90fd\u662f\u53f3\u5b50\u6811(\u4ece0\u8ba1\u6570)\uff09
temp->Rchild = Resume_BiTree(post + index, center + index + 1, len - index - 1);
return temp;
}

void PreOrderTraverse(BiTree *root)//\u524d\u5e8f\u904d\u5386\u8f93\u51fa
{
if (root != NULL)
{
cout data;
PreOrderTraverse(root->Lchild);
PreOrderTraverse(root->Rchild);
}
}

int main(void)
{
Elem_Type *postorder = new Elem_Type[MAX];//\u540e\u5e8f\u6570\u7ec4
Elem_Type *inorder = new Elem_Type[MAX];//\u4e2d\u5e8f\u524d\u5e8f\u6570\u7ec4
cin >> postorder; //\u5148\u8f93\u5165\u540e\u5e8f
cin >> inorder; //\u518d\u8f93\u5165\u524d\u5e8f
BiTree * root = Resume_BiTree(postorder, inorder, strlen(inorder));//\u7531\u4e8e\u672c\u4f8b\u7ed3\u6784\u5143\u7d20\u4e3achar\uff0c\u6240\u4ee5\u53ef\u4ee5\u7528strlen\u6765\u83b7\u5143\u7d20\u4e2a\u6570\uff0c\u5176\u4ed6\u60c5\u51b5\u53ef\u673a\u53d8
PreOrderTraverse(root);
cout << endl;
delete[] postorder;//\u91ca\u653e\u5185\u5b58
delete[] inorder;
return 0;
}

#include
#include
struct BiTNode *stack[100];
struct BiTNode//\u5b9a\u4e49\u7ed3\u6784\u4f53
{
char data;
struct BiTNode *lchild,*rchild;
};
void later(struct BiTNode *&p) //\u524d\u5e8f\u521b\u5efa\u6811
{
char ch;
scanf("%c",&ch);
if(ch==' ')
p=NULL;
else
{
p=(struct BiTNode *)malloc(sizeof(struct BiTNode));
p->data=ch;
later(p->lchild);
later(p->rchild);
}
}
void print(struct BiTNode *p) //\u524d\u5e8f\u904d\u5386\uff08\u8f93\u51fa\u4e8c\u53c9\u6811\uff09
{
int i=-1;
while(1)
{
while(p!=NULL)
{
stack[++i]=p->rchild;/*printf("ok\uff1f\n");*/
printf("%c",p->data);
p=p->lchild;
}
if(i!=-1)
{
p=stack[i];
i--;
}
else
return;
}
}
void main()//\u4e3b\u51fd\u6570
{
struct BiTNode *p,*t;
later(p);
print(p);
}

#include<stdio.h>
#include <stdlib.h>
#include <malloc.h>

#define OK  1
#define ERROR  0
#define OVERFLOW  0

typedef char TElemType;
typedef int Status;
typedef struct BiTNode
{
 TElemType data;
 struct BiTNode *lchild,*rchild;
}BiTNode,*BiTree;
typedef enum {Link,Thread} PointerTag;
typedef struct BiThrNode
{
 TElemType data;
 struct BiThrNode *lchild,*rchild;
 PointerTag LTag,RTag;
}BiThrNode;
typedef BiThrNode *BiThrTree;

BiTree CreateBiTree(BiTree T)    //先序遍历构造二叉树
{
 char ch;
 scanf("%c",&ch);
 if(ch=='#')    //#代表空指针
  T=NULL;
 else
 {
  T=(BiTNode *)malloc(sizeof(BiTNode));    //申请结点
  if(!T)
   exit(OVERFLOW);
  T->data=ch;    //生成根结点
  T->lchild=CreateBiTree(T->lchild);    //构造左子树
  T->rchild=CreateBiTree(T->rchild);    //构造右子树
 }
 return T;
}

Status InOrderTraverse(BiTree T,Status(*visit)(TElemType))
{//中序遍历二叉树
 if(T)
 {
  if(InOrderTraverse(T->lchild,visit))
   if(visit(T->data))
    if(InOrderTraverse(T->rchild,visit))
     return OK;
  return ERROR;
 }
 else
  return OK;
}

Status PrintElement(TElemType e)
{
 printf("%-2c",e);
 return OK;
}

void main()
{
 BiTree T=NULL;
 printf("请输入构造二叉树的字符序列:");
 T=CreateBiTree(T);
 if(T)
  printf("二叉树建立成功!
");
 else
  printf("二叉树构造失败!!!
");
 printf("中序遍历二叉树:");
 InOrderTraverse(T,PrintElement);
 printf("
");
}



#include <iostream>
#define MAXSIZE 100
using namespace std;
typedef char TElemType;
typedef struct BiTNode {
TElemType data;
struct BiTNode *lchild,*rchild;
} BiTNode,*BiTree;
bool InOrderTraverse1(BiTree T) {
if(T) {
cout<<T->data;
InOrderTraverse1(T->lchild);
InOrderTraverse1(T->rchild);
}
}
bool InOrderTraverse2(BiTree T) {
if(T) {
InOrderTraverse2(T->lchild);
cout<<T->data;
InOrderTraverse2(T->rchild);
}
}
bool InOrderTraverse3(BiTree T) {
if(T) {
InOrderTraverse3(T->lchild);
InOrderTraverse3(T->rchild);
cout<<T->data;
}
}
bool CreateBiTree(BiTree &T) {
char ch;
cin>>ch;
if(ch=='#')
T=NULL;
else {
T=new BiTNode;
T->data=ch;
CreateBiTree(T->lchild);
CreateBiTree(T->rchild);
}
}
int Depth(BiTree T) {
int n,m;
if(T==NULL)
return 0;
else {
m=Depth(T->lchild);
n=Depth(T->rchild);
if(m>n)
return(m+1);
else
return(n+1);
}
}
int NodeCount(BiTree T) {
if(T==NULL)
return 0;
else
return NodeCount(T->lchild)+NodeCount(T->rchild)+1;
}
int main()
{
BiTree a;
int height,num;
cout<<"请输入二叉树的元素:\n";
CreateBiTree(a);
cout<<"先序遍历法输出:\n";
InOrderTraverse1(a);
cout<<"\n中序遍历法输出:\n";
InOrderTraverse2(a);
cout<<"\n后序遍历法输出:\n";
InOrderTraverse3(a);
height=Depth(a);
num=NodeCount(a);
cout<<"\n该二叉树深度为:";
cout<<height<<endl;
cout<<"该二叉树结点数为:";
cout<<num;
return 0;
}

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