若x+y-1的绝对值+(y+3)的平方=0,则x-y的值是?

\u82e5x-1\u7684\u7edd\u5bf9\u503c+\uff08y+3\uff09\u7684\u5e73\u65b9=0\uff0c\u6c421-xy-xy\u7684\u5e73\u65b9\u7684\u503c

x-1\u7684\u7edd\u5bf9\u503c+\uff08y+3\uff09\u7684\u5e73\u65b9=0
\u4e24\u4e2a\u975e\u8d1f\u6570\u7684\u548c\u4e3a0 \u90a3\u4e48\u4ed6\u4eec\u90fd\u4e3a0
\u6240\u4ee5 x-1=0 y+3=0
\u89e3\u5f97 x=1 y=-3
\u6240\u4ee5
1-xy-xy²
=1-1\u00d7(-3)-1\u00d7(-3)²
=1+3-9
=-5
\u4e0d\u61c2\u53ef\u8ffd\u95ee \u6709\u5e2e\u52a9\u8bf7\u91c7\u7eb3 \u795d\u4f60\u5b66\u4e60\u8fdb\u6b65 \u8c22\u8c22

\u56e0\u4e3a\ufe31x+y\ufe31-(1+y+3)^2=0
\u6240\u4ee5\ufe31x+y\ufe31=0,(1+y+3)^2=0
\u7531,(1+y+3)^2=0,\u5f97y=-4,
\u4ee3\u5165,\ufe31x+y\ufe31=0,\u5f97x=4,
\u6240\u4ee5,x-y=4-(-4)=8

x+y-1的绝对值+(y+3)的平方=0
x+y-1的绝对值=0,(y+3)的平方=0
x+y-1的绝对值=0,y=-3
x+(-3)-1的绝对值=0
x-4的绝对值=0
x=4

x-y
=4-(-3)
=4+3
=7

7

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