若x一1的绝对值加(y十3)的平方加x十y十z的平方根等于0,求x十y一2的值为 已知x减一的绝对值加y减2的平方加z 3的平方根等于0求xy...

\u5df2\u77e5x\u51cf1\u7684\u7edd\u5bf9\u503c\u52a0y\u52a03\u7684\u5e73\u65b9\u52a0x\u52a0y\u52a0z\u7684\u5e73\u65b9\u6839\u7b49\u4e8e0\u6c42x\uff0cy\uff0cz

|x-1| + (y-2)^2 + \u221a(z+3) = 0
\u7531\u4e8e\u7edd\u5bf9\u503c\u3001\u5e73\u65b9\u3001\u6839\u53f7\u4e0d\u80fd\u662f\u8d1f\u6570\uff0c\u800c\u4e09\u8005\u7684\u548c\u662f0\uff0c\u6240\u4ee5
|x-1| = (y-2)^2 = \u221a(z+3) = 0
\u6240\u4ee5x = 1\uff0cy=2\uff0cz = -3
\u6240\u4ee5\u221a(xy+z²) = \u221a11

\u5df2\u77e5x\u51cf\u4e00\u7684\u7edd\u5bf9\u503c\u52a0y\u51cf2\u7684\u5e73\u65b9\u52a0z 3\u7684\u5e73\u65b9\u6839\u7b49\u4e8e0\u6c42xy z
x-1=y-2=z-3=0;
\u6240\u4ee5x=1\uff1by=2\uff1bz=3\uff1b

\u8bf7\u91c7\u7eb3

\u5982\u679c\u4f60\u8ba4\u53ef\u6211\u7684\u56de\u7b54\uff0c\u656c\u8bf7\u53ca\u65f6\u91c7\u7eb3\uff0c
~\u5982\u679c\u4f60\u8ba4\u53ef\u6211\u7684\u56de\u7b54\uff0c\u8bf7\u53ca\u65f6\u70b9\u51fb\u3010\u91c7\u7eb3\u4e3a\u6ee1\u610f\u56de\u7b54\u3011\u6309\u94ae
~~\u624b\u673a\u63d0\u95ee\u7684\u670b\u53cb\u5728\u5ba2\u6237\u7aef\u53f3\u4e0a\u89d2\u8bc4\u4ef7\u70b9\u3010\u6ee1\u610f\u3011\u5373\u53ef\u3002
~\u4f60\u7684\u91c7\u7eb3\u662f\u6211\u524d\u8fdb\u7684\u52a8\u529b
~~O(\u2229_\u2229)O\uff0c\u8bb0\u5f97\u597d\u8bc4\u548c\u91c7\u7eb3\uff0c\u4e92\u76f8\u5e2e\u52a9

简单，
x一1的绝对值是大于或者等于0
(y十3)的平方大于或者等于0
x十y十z的平方根大于或者等于0
那么只有一个可能，x一1=0，(y十3)=0，x十y十z=0
那么X=1，Y=-3，Z=2
X+Y-2=-4

鑻-1鐨勭粷瀵瑰+(y+3)²+鏍瑰彿x+y+z=0,姹倄,y,z鐨勫笺
绛旓細|x-1|=0,锛坹+3锛²=0,x+y+z=0 鎵浠=1,y=-3锛寊=2

鑻+1鐨勭粷瀵瑰+(y+3鐨缁濆鍊)=0,鍒檡-x-2鍒嗕箣涓鐨勫间负( )
绛旓細|x+1|+|y+3|=0 鈭 x=-1 y=-3 1/(y-x-2)=1/(-3+1-2)=-1/4

鑻+y-1鐨勭粷瀵瑰+(y+3)鐨骞虫柟=0,鍒檟-y鐨勫兼槸?
绛旓細x+y-1鐨勭粷瀵瑰+锛坹+3锛夌殑骞虫柟=0 x+y-1鐨勭粷瀵瑰=0,锛坹+3锛夌殑骞虫柟=0 x+y-1鐨勭粷瀵瑰=0,y=-3 x+(-3)-1鐨勭粷瀵瑰=0 x-4鐨勭粷瀵瑰=0 x=4 x-y =4-(-3)=4+3 =7

鑻-1鐨勭粷瀵瑰+[y-3]⊃2;=0,璁＄畻,[xy-X⊃2;]闄や互X⊃2;-2xy+y...
绛旓細x=1 y=3 [xy-X²]/X²-2xy+y²/xy*x-y/X²=2-6 +3-3=-4

宸茬煡瀹炴暟X,y婊¤冻鏍瑰彿X-1鍔爕鍗3鐨勭粷瀵瑰绛変簬0,姹X鍗y鐨勫
绛旓細鐢辨潯浠跺彲鐭 x-1=0 y+3=0 鍗硏=1 y=-3 x+y=1-3=-2

鑻-2鐨勭粷瀵瑰+(y+3)鐨2娆℃柟=0 闂甔+Y绛変簬澶氬皯
绛旓細x-2鐨勭粷瀵瑰+锛坹+3锛夌殑2娆℃柟=0 鍥犱负x-2鐨勭粷瀵瑰>=0锛岋紙y+3锛夌殑2娆℃柟>=0鎵浠 x-2鐨勭粷瀵瑰=0锛岋紙y+3锛夌殑2娆℃柟=0鎵浠 x=2锛寉=-3鎵浠 x+y=-1

鑻-1鐨勭粷瀵瑰+y-3鐨缁濆鍊=0,姹倄鐨2009娆℃柟+y骞虫柟+2xy鐨勫
绛旓細缁濆鍊閮芥槸闈炶礋鐨勶紝鎵浠ヨ繖涓や釜缁濆鍊奸兘涓0鎵嶈兘鍜屼负0銆亁-1=0 y-3=0 鎵浠=1..y=3 x鐨2009娆℃柟+y骞虫柟+2xy=1+9+6=16 璁板緱閲囩撼鍟

x鍗亂涓1鐨勭粷瀵瑰煎崄鎷彿y+3鍙鎷彿鐨骞虫柟绛変簬0,鍒檟鍑弝鐨勫间负澶氬皯?
绛旓細锝X+Y-1锝+锛圷+3锛^=0 X+Y-1=0 Y+3=0 y=-3 x=4 X-Y=7

鑻-1鐨勭粷瀵瑰煎姞涓奩 +2鐨勭粷瀵瑰肩瓑浜庨浂鍒橷 + Y绛変簬
绛旓細瑙ｏ細缁濆鍊椤规亽闈炶礋锛屼袱闈炶礋椤逛箣鍜岀瓑浜0锛屼袱闈炶礋椤瑰潎绛変簬0 x-1=0锛y+2=0 瑙ｅ緱x=1锛寉=-2 x+y=1+(-2)=-1 x+y鐨勫间负-1

鑻-1鐨勭粷瀵瑰+(y+2)²=0,鍒(x+y)= (濉暟鍊)銆(n涓烘鏁存暟)
绛旓細x-1=0涓y+2=0 鎵浠 x=1 y=-2 鎵浠 x+y=-1

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