怎么用js提取字符串中的某一段字符 js 正则表达式提取某一段字符
\u5982\u4f55\u7528js\u63d0\u53d6\u5b57\u7b26\u4e32\u4e2d(url)\u7684\u67d0\u4e00\u6bb5\u5b57\u7b26\u5176\u5b9e\u6bd4\u8f83\u7b80\u5355\uff0c\u5206\u4eab\u4e00\u6bb5\u6211\u4e4b\u524d\u5199\u7684js\u63d0\u53d6URL\u53c2\u6570\u7684\u51fd\u6570\u5427
function UrlParamHash(url) { var params = [], h; var hash = url.slice(url.indexOf("?") + 1).split('&'); for (var i = 0; i < hash.length; i++) { h = hash[i].split("="); params.push(h[0]); params[h[0]] = h[1]; } return params;}// \u5982\u4e0b\u4f7f\u7528, b\u5c31\u662f\u4f60\u7684URL\u5b57\u7b26\u4e32var params = UrlParamHash(b), id = params['id'];\u4e0d\u8fc7\u5199\u5b8c\u53d1\u73b0\u4f60\u7684URL\u4e0d\u662f\u5f88\u6807\u51c6\uff0c\u56e0\u4e3a\u4e00\u822c\u5730\u5740\u548c\u53c2\u6570\u76f4\u63a5\u662f\u7528"?"\u5206\u5272\u7684\uff0c\u5982\u679c\u4f60\u7684\u4e0d\u662f\u7684\u8bdd
\u4f60\u53ef\u4ee5\u628a\u51fd\u6570\u91ccindexOf("?")\u6839\u636e\u4f60\u7684\u57df\u540d\u6362\u6210indexOf("com/")\u4e4b\u7c7b\u7684
\u4e5f\u53ef\u4ee5\u6839\u636e\u4f60\u5177\u4f53\u7684URL\u89c4\u5219\u4fee\u6539\u6574\u4e2a\u51fd\u6570\uff0c\u53cd\u6b63\u539f\u7406\u5c31\u5728\u8fd9\u91cc
var str = "BEGIN CONST a,b=10,c END IF a>10 && (a+cc) THEN RETURN true END ELSE RETURN false END END END";str=str.replace(/\s/g,"");//\u53d6\u6389\u7a7a\u683cstr=str.match(/IF(\S*)THEN/)[1];//\u6b63\u5219\u53d6\u51faIF\u548cTHEN\u4e4b\u95f4\u7684\u5b57\u7b26\u4e32str=str.split("&&");//\u6309\u7167&&\u5206\u7ec4var str_end=str[0].split('>'); //\u6309\u7167>\u5206\u7ec4alert(str_end);//\u6700\u7ec8\u7ed3\u679c\u4e3astr_end[0]=a str_end[1]=10 ;
String.prototype.getQuery = function(name){
var reg = new RegExp("(^|&)"+ name +"=([^&]*)(&|$)");
var r = this.substr(this.indexOf("\?")+1).match(reg);
if (r!=null) return unescape(r[2]); return null;
}
var s = "web1.aspx?status=item&mode=edit";
alert(s.getQuery("status"));
alert(s.getQuery("mode"));
String.prototype.getQuery = function(name)
的意思是为String对象增加一个getQuery(name)方法.
var url ='?id=632573?id=79323&ed=7947';
var str = url.substr(1);
strs = str.split("?");
var theRequest = new Object();
theRequest[strs[0].split("=")[0]]=unescape(strs[0].split("=")[1]);
var id = theRequest['id']; //取得ID
alert(id);
以上仅解决你这个例子的情况，以为大多数情况下URL参数的键名都不是一样的
而且开头一个?中间都是& 所以实际可以一次性获取全部的参数的
//这个是正常的URL注意id和id2键名不一样中间都是&间隔
var url ='?id=632573&id2=79323&ed=7947';
var str = url.substr(1); //去掉第一个?
strs = str.split("&");//以&分割
var theRequest = new Object();
//取得全部并赋值
for(var i = 0; i < strs.length; i ++) {
theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
}
//输出
var id = theRequest['id']; //取得ID
var id2 = theRequest['id2']; //取得ID2
var ed = theRequest['ed']; //取得ed
alert(id);
alert(id2);
alert(ed);
答案一："?id=632573&id=79323?ed=7947".replace(/^.*?id=(\d+).*$/,'$1')
答案二："?id=632573&id=79323?ed=7947".replace(/^.*?(\d+).*$/,'$1')
测试通过的~请采纳~不明白的可以继续追问~
看到楼上好多人都写了，我也写了一个，希望能帮到你：
var b = "rwewerwer?id=632573&id=79323?ed=7947".match(/(\d+)/g)[0];
var str = "?id=632573&id=79323?ed=7947";
var s = str.indexOf('=')+1;//第一个=出现的位置
var e = str.indexOf('&');//第一个&出现的位置
var re = str.substring(s,e);//返回的值
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