求高中数学计算题一百道。纯计算的
\u9ad8\u4e2d\u6570\u5b66\u8ba1\u7b97\u98981.\u76f4\u7ebfl\u622a\u5706x2+y2-2y=0\u6240\u5f97\u5f26AB\u7684\u4e2d\u70b9\u662f(-1/2,3/2),\u6c42\u76f4\u7ebfl\u7684\u65b9\u7a0b.
\u89e3\uff1a\u5047\u8bbe\u76f4\u7ebf\u65b9\u7a0b\u4e3a y = kx + b, \u5e26\u5165 x^2 + y^2 - 2y = 0, \u5f97
x^2 + (kx+b)^2 - 2(kx + b) = 0
x^2 + k^2 * x^2 + 2kbx + b^2 - 2kx -2b = 0
(k^2 + 1)x^2 + 2k(b - 1)x + b^2 - 2b = 0 ------------------------\uff081\uff09
\u5f26AB\u7684\u4e2d\u70b9\u662f(-1/2,3/2), \u6240\u4ee5\u65b9\u7a0b\uff081\uff09\u7684\u4e24\u4e2a\u89e3\u7684\u548c\u4e3a 2 * (-1/2) = -1 = - 2k(b - 1)/[2(k^2 + 1)] = - k(b - 1)/(k^2 + 1)
k(b - 1)/(k^2 + 1) = 1 ------------- (2)
y1 + y2 = k(x1 + x2) + b, 2 * (3/2) = k * (-1) + b, 3 = b - k ----------- (3)
(2)(3) \u8054\u5408 \u6c42\u5f97
k(2+k) = k^2+1, 2k = 1, k = 1/2
b = 3 + k = 7/2
\u6240\u4ee5\u76f4\u7ebf\u4e3a y = 7x/2 + 1/2
---------------------------------------------------------------------
2.\u6c42\u548c\u76f4\u7ebf3x-4y+4=0\u5782\u76f4\u4e14\u4e0e\u5706x2-2x+y2-3=0\u76f8\u5207\u7684\u76f4\u7ebf\u65b9\u7a0b.
\u89e3\uff1a
3x-4y+4=0\uff0c y = 3x/4 + 1, \u659c\u7387\u4e3a 3/4
\u90a3\u4e48\u4e0e\u5b83\u5782\u76f4\u7684\u76f4\u7ebf\u7684\u659c\u7387\u4e3a - 1/(3/4) = -4/3
\u5047\u8bbe\u5b83\u4e3a y = -4x/3 + b, \u5e26\u5165\u5706\u65b9\u7a0b x^2 - 2x + y^2 - 3 = 0\uff0c \u5f97
x^2 - 2x + (-4x/3 + b)^2 - 3 = 0
x^2 - 2x + 16x^2/9 - 8bx/3 + b^2 - 3 = 0
25x^2/9 - (2 + 8b/3)x + b^2 - 3 = 0 ---------- (1)
\u56e0\u4e3a\u76f8\u5207\uff0c \u6240\u4ee5\u53ea\u6709\u4e00\u4e2a\u4ea4\u70b9\uff0c\u90a3\u4e48\u65b9\u7a0b(1)\u53ea\u6709\u552f\u4e00\u89e3\uff0c\u5b83\u7684\u5224\u522b\u5f0f=0\uff0c\u5373
(2 + 8b/3)^2 - 4 * 25/9 * (b^2 - 3) = 0
4 * (1 +16b^2 / 9 + 8b/3) - 100b^2/9 + 100/3 = 0
9 +16b^2 + 24b - 25b^2 + 75 = 0
-9b^2 + 24b + 84 = 0
3b^2 - 8b - 28 = 0
(3b - 14)(b + 2 ) = 0
b = 14/3 \u6216\u8005 -2
\u6240\u4ee5\u76f4\u7ebf\u65b9\u7a0b\u4e3a y = -4x/3 + 14/3 \u6216\u8005y = -4x/3 - 2
-------------------------------------------------------------------------
3.\u4e0e\u53cc\u66f2\u7ebfx2/9-y2/16=1\u6709\u5171\u540c\u7684\u6e10\u7ebf,\u4e14\u7ecf\u8fc7\u70b9(3,-4\u221a2),\u6c42\u53cc\u66f2\u7ebf\u65b9\u7a0b
\u89e3\uff1a
x^2/9 - y^2/16 = 1 \u7684\u6e10\u8fd1\u7ebf\u4e3a x/3 +- y/4 = 0, y = +- 4x/3
\u5047\u8bbe\u6240\u6c42\u4e3a x^2/a^2 - y^2/b^2 = -1,
\u6e10\u8fd1\u7ebf\u4e3a x^2/a^2 - y^2/b^2 = 0, y/b = +- x/a, y = +- b/a * x
\u6e10\u8fd1\u7ebf\u76f8\u540c\uff0c \u6240\u4ee5 4/3 = b/a --------------- (1)
\u7ecf\u8fc7\u70b9(3,-4\u221a2)\uff0c \u6240\u4ee5
9/a^2 - 32/b^2 = -1 ----------- (2)
(1)(2)\u8054\u5408\u5f97
9/a^2 - 32 / [16a^2 / 9] = -1
9 - 32*9/16 = -a^2
9 - 2*9 = -a^2
a = 3
b = 4
\u6240\u6c42\u4e3a x^2/9 - y^2/16 = -1,
------------------------------------------------------------------------------
4.\u8bbef(x)=2(logX)^2+2a log(1/x)+b,\u5df1\u77e5\u5f53x=1/2\u65f6,f(x)\u53d6\u5f97\u6700\u5c0f\u503c\u4e3a-8,\u6c42a-b
\u89e3\uff1af(1/2) = 2 * (-1)^2 + 2a * 1 + b = 2 + 2a + b = -8, 2a + b = -10 -------------- (1)
f(x) = 2 (lnx / ln2)^2 + 2a (ln(1/x) / ln2) + b
= 2 (lnx)^2 / (ln2)^2 - 2a (lnx / ln2) + b
f'(x) = 2/(ln2)^2 * 2lnx * 1/x - 2a/ln2 * 1/x = 0
2/(ln2) * lnx - a = 0
x = 1/2
-2 - a = 0, a = -2, \u5e26\u5165(1)\u5f97
b = -6
a - b = -2 - (-6) = 4
------------------------------------------------------------------
5.\u8981\u5f97\u5230\u51fd\u6570y=3sin(2x-\u03c0/3)\u7684\u56fe\u50cf,\u53ea\u9700\u5c06\u51fd\u6570y=3sin2x\u7684\u56fe\u50cf
A.\u5411\u5de6\u5e73\u52a8\u03c0/3\u4e2a\u5355\u4f4d B. \u5411\u53f3\u5e73\u52a8\u03c0/3\u4e2a\u5355\u4f4d C. \u5411\u5de6\u5e73\u52a8\u03c0/6\u4e2a\u5355\u4f4dD. \u5411\u53f3\u5e73\u52a8\u03c0/3\u4e2a\u5355\u4f4d
\u89e3\uff1a
y=3sin(2x-\u03c0/3) = 3 * sin[2(x - \u03c0/6)]
x = m + \u03c0/6 \u5373 m = x - \u03c0/6 \u7684\u65f6\u5019
y = 3sin(2m) = 3sin(2x)
\u6240\u4ee5 x \u9700\u8981\u5411\u5de6\u5e73\u52a8 \u03c0/6, \u7b54\u6848\u4e3a C
\u9ad8\u4e2d\u6570\u5b66\u5408\u96c6\u767e\u5ea6\u7f51\u76d8\u4e0b\u8f7d
\u94fe\u63a5\uff1ahttps://pan.baidu.com/s/1znmI8mJTas01m1m03zCRfQ
?pwd=1234
\u63d0\u53d6\u7801\uff1a1234
\u7b80\u4ecb\uff1a\u9ad8\u4e2d\u6570\u5b66\u4f18\u8d28\u8d44\u6599\u4e0b\u8f7d\uff0c\u5305\u62ec\uff1a\u8bd5\u9898\u8bd5\u5377\u3001\u8bfe\u4ef6\u3001\u6559\u6750\u3001\u89c6\u9891\u3001\u5404\u5927\u540d\u5e08\u7f51\u6821\u5408\u96c6\u3002
75÷〔138÷（100-54）〕 85×(95－1440÷24)
80400－(4300＋870÷15) 240×78÷（154-115）
1437×27＋27×563 〔75-（12+18）〕÷15
2160÷〔（83-79）×18〕 280＋840÷24×5
325÷13×(266－250) 85×(95－1440÷24)
58870÷(105＋20×2) 1437×27＋27×563
81432÷(13×52＋78) [37.85-（7.85+6.4）] ×30
156×[(17.7-7.2)÷3] （947－599）＋76×64
36×(913－276÷23) [192－（54＋38）]×67
[（7.1-5.6）×0.9-1.15]÷2.5 81432÷(13×52＋78)
5.4÷[2.6×（3.7-2.9）+0.62] （947－599）＋76×64 60－(9.5＋28.9)]÷0.18 2.881÷0.43－0.24×3.5 20×[(2.44－1.8)÷0.4＋0.15] 28-(3.4 1.25×2.4) 0.8×〔15.5-(3.21 5.79)〕 （31.8 3.2×4）÷5 194－64.8÷1.8×0.9 36.72÷4.25×9.9 3.416÷（0.016×35） 0.8×[(10－6.76)÷1.2]
（136+64）×（65-345÷23） (6.8-6.8×0.55)÷8.5
0.12× 4.8÷0.12×4.8 （58+37）÷（64-9×5）
812-700÷（9+31×11） （3.2×1.5+2.5）÷1.6
85+14×（14+208÷26） 120-36×4÷18+35
（284+16）×（512-8208÷18） 9.72×1.6-18.305÷7
4/7÷[1/3×（3/5-3/10）] （4/5+1/4）÷7/3+7/10
12.78－0÷（ 13.4＋156.6 ） 37.812-700÷（9+31×11） （136+64）×（65-345÷23） 3.2×（1.5+2.5）÷1.6
85+14×（14+208÷26） （58+37）÷（64-9×5）
(6.8-6.8×0.55)÷8.5 （284+16）×（512-8208÷18）
0.12× 4.8÷0.12×4.8 （3.2×1.5+2.5）÷1.6
120-36×4÷18+35 10.15-10.75×0.4-5.7
5.8×（3.87-0.13）+4.2×3.74 347+45×2-4160÷52
32.52-（6+9.728÷3.2）×2.5 87（58+37）÷（64-9×5）
[（7.1-5.6）×0.9-1.15] ÷2.5 （3.2×1.5+2.5）÷1.6
5.4÷[2.6×（3.7-2.9）+0.62] 12×6÷（12-7.2）-6
3.2×6+（1.5+2.5）÷1.6 （3.2×1.5+2.5）÷1.6
5.8×（3.87-0.13）+4.2×3.74
33.02－（148.4－90.85）÷2.5
建议你不如把近三年的天历三十八套全买了！不止提高计数题！
绛旓細鍥
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绛旓細=鏍瑰彿xy*(鏍瑰彿y+鏍瑰彿x)/[y(鏍瑰彿x+鏍瑰彿y)(鏍瑰彿x-鏍瑰彿y)]-(x+鏍瑰彿xy+y)/[x^3/2-y^3/2)=鏍瑰彿xy/[y(鏍瑰彿x-鏍瑰彿y)-(x+鏍瑰彿xy+y)/[(鏍瑰彿x-鏍瑰彿y)*(x+鏍瑰彿xy+y)]=鏍瑰彿xy/[y(鏍瑰彿x-鏍瑰彿y)]-1/(鏍瑰彿x-鏍瑰彿y)=[鏍瑰彿xy-y]/[y(鏍瑰彿x-鏍瑰彿y)]=鏍瑰彿y(鏍瑰彿x-鏍瑰彿y)/[y...
绛旓細1.鐩寸嚎l鎴渾x2+y2-2y=0鎵寰楀鸡AB鐨勪腑鐐规槸(-1/2,3/2),姹傜洿绾縧鐨勬柟绋.瑙ｏ細鍋囪鐩寸嚎鏂圭▼涓 y = kx + b,甯﹀叆 x^2 + y^2 - 2y = 0,寰 x^2 + (kx+b)^2 - 2(kx + b)= 0 x^2 + k^2 x^2 + 2kbx + b^2 - 2kx -2b = 0 (k^2 + 1)x^2 + 2k(b - 1)...
绛旓細楂樹腑鏁板銆璁＄畻棰銆傜畝鍗 鎴戞潵绛 1涓洖绛 #鐑# 浣犺杩囧摢浜涘洜涓鸿佹澘浣滄瀵艰嚧鍊掗棴鐨勫叕鍙?gys1962515 2016-05-23 路 TA鑾峰緱瓒呰繃1.5涓囦釜璧 鐭ラ亾澶ф湁鍙负绛斾富 鍥炵瓟閲:1.6涓 閲囩撼鐜:62% 甯姪鐨勪汉:1338涓 鎴戜篃鍘荤瓟棰樿闂釜浜洪〉 鍏虫敞 灞曞紑鍏ㄩ儴 鏈洖绛旂敱鎻愰棶鑰呮帹鑽 宸茶禐杩 宸茶俯杩< 浣犲杩欎釜...
绛旓細12涔15=180锛堝紶锛2涔14=28锛堝紶锛180+28=208锛堝紶锛夌瓟锛氳繖涓樁姊暀瀹や竴鍏辨湁208寮犺妗
绛旓細C4锛4锛夛紜C3锛4锛+C3锛5锛夛紜C3锛6锛夆︼紜C3锛50锛=C4(5)+锛+C3锛5锛夛紜C3锛6锛夆︼紜C3锛50锛=C4(6)锛婥3锛6锛夆︼紜C3锛50锛=C4(50)+C3锛50锛=C4(51)鍏紡Cm(n)+Cm-1(n)=Cm(n+1)
