设.x1,x2是方程x的平方减x减2015等于0的两实数跟,则x1的三次方加2016x2减201 设x1,x2是方程x的平方减x减2013等于0的两实数跟,求...

\u8bbex1,x2\u662f\u65b9\u7a0bx\u7684\u5e73\u65b9-x-2015=0\u7684\u4e24\u4e2a\u5b9e\u6570\u6839,\u6c42x1\u7684\u7acb\u65b9 2016x2-2015


x1\u548cx2\u662f\u65b9\u7a0bx^2-x-2013=0\u7684\u6839
\u6839\u636e\u97e6\u8fbe\u5b9a\u7406\u6709\uff1ax1+x2=1
x1*x2=-2013
x1^3+2014x2-2013
=(x1+2013)x1+2014x2-2013
=x1^2+2013x1+2014x2-2013
=x1+2013+2013x1+2014x2-2013
=2014(x1+x2)
=2014

∵ x1^2-x1-2015=0、x1+x2=1
所以 x1^3+2016x2-201=x1(x1+2015)+2016x2-201
=x1^2+2015x1+2016x2-201
=x1+2015+2015x1+2016x2-201
=2016(x1+x2)+2015-201
=4031-201
=3830
【若201是2015之误,则=2016 ;若201是2016之误 ,则 =2015】

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