c语言,输出由数字组成的菱形图形。求如何编写。谢谢! C语言编程打印菱形的数字图表

\u7528C\u8bed\u8a00\u7f16\u7a0b\u8f93\u51fa\u83f1\u5f62 \u56fe\u6848

#include void main() { int i,j,k; for(i=1;i<=4;i++) //\u5148\u6253\u5370\u4e0a\u8fb9\u7684\u56db\u884c { for(j=1;j<=4-i;j++) //\u63a7\u5236\u8981\u6253\u5370\u7684\u7a7a\u683c\u6570\u91cf printf(" "); for(k=1;k<=2*i-1;k++) //\u63a7\u5236\u8981\u6253\u5370\u7684\u661f\u53f7\u6570 printf("*"); printf("\n"); } for(i=1;i<=3;i++) { for(j=1;j<=i;j++) //\u63a7\u5236\u8981\u6253\u5370\u7684\u7a7a\u683c\u6570 printf(" "); for(k=1;k<=7-2*i;k++) //\u63a7\u5236\u8981\u6253\u5370\u7684\u661f\u53f7\u6570 printf("*"); printf("\n"); } }

\u6269\u5c55\u8d44\u6599\uff1a
for\u5faa\u73af
for\u5faa\u73af\u7ed3\u6784\u662fc\u8bed\u8a00\u4e2d\u6700\u5177\u6709\u7279\u8272\u7684\u5faa\u73af\u8bed\u53e5\uff0c\u4f7f\u7528\u6700\u4e3a\u7075\u6d3b\u65b9\u4fbf\uff0c\u5b83\u7684\u4e00\u822c\u5f62\u5f0f\u4e3a\uff1a
for\uff08\u8868\u8fbe\u5f0f1;\u8868\u8fbe\u5f0f2;\u8868\u8fbe\u5f0f3\uff09\u5faa\u73af\u4f53\u8bed\u53e5 \u3002\uff08\u5176\u4e2d\uff1b\u4e0d\u80fd\u7701\u7565\uff09
\u8868\u8fbe\u5f0f
\u8868\u8fbe\u5f0f1\u4e3a\u521d\u503c\u8868\u8fbe\u5f0f\uff0c\u7528\u4e8e\u5728\u5faa\u73af\u5f00\u59cb\u524d\u4e3a\u5faa\u73af\u53d8\u91cf\u8d4b\u521d\u503c\u3002
\u8868\u8fbe\u5f0f2\u662f\u5faa\u73af\u63a7\u5236\u903b\u8f91\u8868\u8fbe\u5f0f\uff0c\u5b83\u63a7\u5236\u5faa\u73af\u6267\u884c\u7684\u6761\u4ef6\uff0c\u51b3\u5b9a\u5faa\u73af\u7684\u6b21\u6570\u3002
\u8868\u8fbe\u5f0f3\u4e3a\u5faa\u73af\u63a7\u5236\u53d8\u91cf\u4fee\u6539\u8868\u8fbe\u5f0f\uff0c\u5b83\u4f7ffor\u5faa\u73af\u8d8b\u5411\u7ed3\u675f\u3002
\u5faa\u73af\u4f53\u8bed\u53e5\u662f\u5728\u5faa\u73af\u63a7\u5236\u6761\u4ef6\u6210\u7acb\u7684\u60c5\u51b5\u4e0b\u88ab\u53cd\u590d\u6267\u884c\u7684\u8bed\u53e5\u3002
\u4f46\u662f\u5728\u6574\u4e2afor\u5faa\u73af\u8fc7\u7a0b\u4e2d\uff0c\u8868\u8fbe\u5f0f1\u53ea\u8ba1\u7b97\u4e00\u6b21\uff0c\u8868\u8fbe\u5f0f2\u548c\u8868\u8fbe\u5f0f3\u5219\u53ef\u80fd\u8ba1\u7b97\u591a\u6b21\uff0c\u4e5f\u53ef\u80fd\u4e00\u6b21\u4e5f\u4e0d\u8ba1\u7b97\u3002\u5faa\u73af\u4f53\u53ef\u80fd\u591a\u6b21\u6267\u884c\uff0c\u4e5f\u53ef\u80fd\u4e00\u6b21\u90fd\u4e0d\u6267\u884c\u3002
\u5148\u6267\u884c\u8868\u8fbe\u5f0f2\uff0c\u7136\u540e\u6267\u884c\u5faa\u73af\u7ed3\u6784\uff0c\u6700\u540e\u8868\u8fbe\u5f0f3\uff0c\u4e00\u76f4\u8fd9\u6837\u5faa\u73af\u4e0b\u53bb\u3002
for\u5faa\u73af\u8bed\u53e5\u662fc\u8bed\u8a00\u79cd\u529f\u80fd\u6700\u4e3a\u5f3a\u5927\u7684\u8bed\u53e5\uff0c\u751a\u81f3\u5728\u4e00\u5b9a\u7a0b\u5ea6\u4e0a\u53ef\u4ee5\u4ee3\u66ff\u5176\u4ed6\u7684\u5faa\u73af\u8bed\u53e5\u3002
do
do\u5faa\u73af\u7ed3\u6784\uff0cdo 1 while\u2475\uff1b\u7684\u6267\u884c\u987a\u5e8f\u662f1->2->1...\u5faa\u73af\uff0c2\u4e3a\u5faa\u73af\u6761\u4ef6\u3002
while
while\u5faa\u73af\u7ed3\u6784\uff0cwhile(1) 2; \u7684\u6267\u884c\u987a\u5e8f\u662f1->2->1...\u5faa\u73af\uff0c1\u4e3a\u5faa\u73af\u6761\u4ef6
\u4ee5\u4e0a\u5faa\u73af\u8bed\u53e5\uff0c\u5f53\u5faa\u73af\u6761\u4ef6\u8868\u8fbe\u5f0f\u4e3a\u771f\u5219\u7ee7\u7eed\u5faa\u73af\uff0c\u4e3a\u5047\u5219\u8df3\u51fa\u5faa\u73af\u3002
\u53c2\u8003\u8d44\u6599\uff1aC\u8bed\u8a00-\u767e\u5ea6\u767e\u79d1

#include "stdio.h"
int main() {
int n,i,j;
while(scanf("%d",&n)) {
for(i=1; i<=n; i++) {
for(j=1; j<=n-i; j++) //\u753b\u7a7a\u683c
printf(" ");
for(j=1; j<=i; j++)
printf("%d",j);//\u8f93\u51fa\u4ece1\u5230n
for(j=i-1; j>=1; j--)
printf("%d",j);//\u8f93\u51fa\u4ecen-1\u52301
printf("\n");
}
for(i=n-1; i>=1; i--) {
for(j=1; j<=n-i; j++) //\u753b\u7a7a\u683c
printf(" ");
for(j=1; j<=i; j++)
printf("%d",j);//\u8f93\u51fa\u4ece1\u5230n
for(j=i-1; j>=1; j--)
printf("%d",j);//\u8f93\u51fa\u4ecen-1\u52301
printf("\n");
}
}
return 0;
}

\u6269\u5c55\u8d44\u6599\uff1a
\u4e66\u5199\u89c4\u5219
1\u3001\u4e00\u4e2a\u8bf4\u660e\u6216\u4e00\u4e2a\u8bed\u53e5\u5360\u4e00\u884c\u3002
2\u3001\u7528{} \u62ec\u8d77\u6765\u7684\u90e8\u5206\uff0c\u901a\u5e38\u8868\u793a\u4e86\u7a0b\u5e8f\u7684\u67d0\u4e00\u5c42\u6b21\u7ed3\u6784\u3002{}\u4e00\u822c\u4e0e\u8be5\u7ed3\u6784\u8bed\u53e5\u7684\u7b2c\u4e00\u4e2a\u5b57\u6bcd\u5bf9\u9f50\uff0c\u5e76\u5355\u72ec\u5360\u4e00\u884c\u3002
3\u3001\u4f4e\u4e00\u5c42\u6b21\u7684\u8bed\u53e5\u6216\u8bf4\u660e\u53ef\u6bd4\u9ad8\u4e00\u5c42\u6b21\u7684\u8bed\u53e5\u6216\u8bf4\u660e\u7f29\u8fdb\u82e5\u5e72\u683c\u540e\u4e66\u5199\u3002\u4ee5\u4fbf\u770b\u8d77\u6765\u66f4\u52a0\u6e05\u6670\uff0c\u589e\u52a0\u7a0b\u5e8f\u7684\u53ef\u8bfb\u6027\u3002\u5728\u7f16\u7a0b\u65f6\u5e94\u529b\u6c42\u9075\u5faa\u8fd9\u4e9b\u89c4\u5219\uff0c\u4ee5\u517b\u6210\u826f\u597d\u7684\u7f16\u7a0b\u98ce\u683c\u3002
\u53c2\u8003\u8d44\u6599\uff1a
\u767e\u5ea6\u767e\u79d1-c\u8bed\u8a00

#include<stdio.h>
#include<stdlib.h> 
#include<math.h>
int main()
{
    int i=0;
int j=0;
int n;
while(scanf("%d",&n) != EOF)
{
    for(i=1;i<=n;i++)
{
    for(j=1;j<=n-i;j++)
{
    printf(" ");
}
    for(j=1;j<=2*i-1;j++)
{
    printf("%d",i);
}
    for(j=0;j<abs(n/2-i);j++)
{
    printf(" ");
}
    printf("
");
}

for(i=n-1;i>0;i--)
{
    for(j=1;j<=n-i;j++)
{
    printf(" ");
}
    for(j=1;j<=2*i-1;j++)
{
    printf("%d",i);
}
    for(j=0;j<abs(n/2-i);j++)
{
    printf(" ");
}
    printf("
");
}
}
    return 0;
}






package mainjava;

import java.util.Scanner;

public class lingxing {

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int num = sc.nextInt();

for(int i=1;i<=num;i++)//控制行数
{
for(int k=num-1;k>=i;k--)//打印空格
{
System.out.print(" ");
}
for(int j=1;j<=2*i-1;j++)//打印*
{
System.out.print(i);
}

System.out.println();
}
for (int i = num-1; i > 0; i--) // 输出菱形的下半部分
{

for (int j = 1; j <= num - i; j++)
System.out.print(" ");
for (int k = 1; k <= i; k++)
System.out.print(i);
for (int m = i - 1; m > 0; m--)
System.out.print(i);

System.out.println();
}
}
}
我这是用java语言写的,你只需要改写一下输入输出语句就行,如能帮到你望采纳。有什么不懂,可继续追问 谢谢

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