3相电流已知问用多大电缆 三相四线供电每相30kw电热负载问用多大电缆
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三相电流基本平衡，取品平均值90A， vv22--3*25+2*16 在空气中载流量为115A ，直埋土壤中126A ，铠装电缆的表示符号是 22 此型号完全够负载用（60 KW左右）用4*35的电缆，你要考虑余量的。铠装电缆用YJV22来表示,地埋电缆过流量要少一些，考虑散热等原因
用3*70+1*35的电缆，你要考虑富余量的。经验计算一个平方两个电流。铠装电缆用YJV22来表示
绛旓細涓夌浉鐢垫祦鍩烘湰骞宠 锛屽彇鍝佸钩鍧囧90A锛 vv22--3*25+2*16 鍦ㄧ┖姘斾腑杞芥祦閲忎负115A 锛岀洿鍩嬪湡澹や腑126A 锛岄摖瑁鐢电紗鐨勮〃绀虹鍙锋槸 22 姝ゅ瀷鍙峰畬鍏ㄥ璐熻浇鐢紙60 KW宸﹀彸锛
绛旓細閫夌敤瀹夊叏鐢垫祦瀹归噺涓55A鐨16骞虫柟閾滃绾銆20KW锛3鐩380V锛屽姛鐜囧洜鏁颁负0.9锛屽垯璐熻浇鐢垫祦涓33.8A銆備緷鎹數宸ユ硶瑙勮瀹氾紝浣滀负鐢靛櫒涔嬬數璺澶囧閲忥紝闇鏈125%鐨勫閲忓畨鍏ㄧ郴鏁帮紝鍥犳闇浠(33.8*125%)=42.3A浣滀负璁捐渚濇嵁銆16骞虫柟鐨勫鑲￠摐绾跨數缂嗐備笁鐩哥數琛紝50A绌哄紑瓒冲鐢 ...
绛旓細300A鐢垫祦闇瑕佺敤115mm²鐨勯摑鐢电紗锛70mm²鐨勯摐鐢电紗銆傜敱涓夌浉鐢垫満鍏紡寰楋細P=1.732UIcos桅銆傛墍浠ュ姛鐜嘝=1.732*0.8*0.38*300=158鍗冪摝锛宑os桅涓0.8銆傜數鍘嬩负380V銆傛牴鎹數娴300A锛屾煡鐢电紗鎵嬪唽YJV鐭ワ紝鐢115mm²鐨勯摑鐢电紗锛70mm²鐨勯摐鐢电紗銆傜數缂嗚浇娴侀噺鍙ｅ喅锛氫簩鐐逛簲涓嬩箻浠ヤ節锛屽線涓...
绛旓細涓鑸潵璇达紝3鐩380浼70kw搴旈50骞虫柟鐨勭數缂锛屼緷鎹數娴佸叕寮廔=P梅锛1.732Ucos桅锛夛紝鍏朵腑cos桅澶氭寜0.8璁＄畻锛屽彲浠ュ緱鍑虹數鍣ㄧ數娴佸ぇ绾︽槸133A宸﹀彸锛屽悓鏃惰繕瑕佸姞涓婄櫨鍒嗕箣浜屽崄宸﹀彸鐨勫瘜浣欓噺锛岃繖鏍峰氨鍙互灏嗙數缂嗙數娴佺畻浣160A锛屽湪鐢电嚎鐢垫祦鍙傜収琛ㄤ腑锛50骞虫柟瀵瑰簲鐨勭數缂嗙數娴佷负165A锛屽彲绗﹀悎浣跨敤闇姹傘傚ぇ瀹跺湪閫夎喘鐢电嚎鐢电紗鏃...
绛旓細棰濆畾鍔熺巼=30kW锛屼笁鐩哥數鍘=380V锛屽姛鐜囧洜鏁=0.85锛岄瀹鐢垫祦=53.7A锛屽彲閫鐢电紗锛10mm² PVC濉戞枡缁濈紭 鍗曡姱閾滅嚎锛屾帹鑽愯浇娴侀噺65A锛岀浉搴斿姛鐜36.4kW锛岀數缂嗘弧璐熻嵎鏃5%鐢靛帇鎹熷け璺濈涓159.1m锛6mm² PE濉戞枡缁濈紭 鍗曡姱閾滅嚎锛屾帹鑽愯浇娴侀噺60A锛岀浉搴斿姛鐜33.6kW锛岀數缂嗘弧璐熻嵎鏃5%鐢靛帇鎹熷け璺濈涓103.4m锛1...
绛旓細1.5鍗冪摝浠ヤ笅鐨勪笁鐩哥數鏈猴紝鐢垫祦绾︿负3瀹夊煿锛屽彲浠浣跨敤1骞虫柟姣背鐨勯摐鐢电紗銆1.5鑷7鍗冪摝鐨勪笁鐩哥數鏈猴紝鐢垫祦绾︿负6瀹夊煿锛屽彲浠ヤ娇鐢2骞虫柟姣背鐨勯摐鐢电紗銆7.5鑷20鍗冪摝鐨勪笁鐩哥數鏈猴紝鐢垫祦绾︿负12瀹夊煿锛屽彲浠ヤ娇鐢4骞虫柟姣背鐨勯摐鐢电紗銆20鑷50鍗冪摝鐨勪笁鐩哥數鏈猴紝鐢垫祦绾︿负24瀹夊煿锛屽彲浠ヤ娇鐢6骞虫柟姣背鐨勯摐鐢电紗銆50鑷100鍗冪摝鐨勪笁鐩...
绛旓細涓夌浉380V50HZ浜ゆ祦鐢 P=1.732x380xIx0.85 I=P梅锛1.732x380x0.85锛夋埅闈㈢НS=P梅锛1.732x380x0.85锛壝6锛堝钩鏂规绫筹級锛圫琛ㄧず鎴潰绉紝鍗曚綅骞虫柟姣背锛孭琛ㄧず鍔熺巼锛屽崟浣嶇摝锛6琛ㄧず鐢垫祦瀵嗗害锛屽崟浣岮/mm²锛変互10鍗冪摝锛屼笁鐩380V50HZ浜ゆ祦鐢典负渚嬶細鎴潰绉疭=P梅锛1.732x380x0.85锛壝6=10000梅...
绛旓細30鍗冪摝鐨勭數鏈洪瀹氳繍琛鐢垫祦鍦54A宸﹀彸锛16骞虫柟閾鐢电紗闀挎湡杩炵画璐熻嵎鍏佽鐢垫祦鍦60A锛25骞虫柟閾滅數缂嗛暱鏈熻繛缁礋鑽峰厑璁哥數娴佸湪77A锛岃冭檻鍒板惎鍔ㄧ數娴佸拰闈炴甯歌繍琛屾儏鍐碉紙鐢垫満鏁呴殰锛夛紝搴旈25骞虫柟閾滅數缂嗐傚鏋滄槸380V鐨勭數鍘嬶紝3000/380/1.732=45.58A锛岀敤16骞虫柟鐨勬湁鐐瑰皬浜嗭紝寤鸿鐢25骞虫柟鐨勭數绾锛涘鏋滄槸220V鐨勭數鍘嬶紝30000/...
绛旓細3. 鍦ㄨ绠椾腑锛屾垜浠氬父鍙朿os蠄涓0.8锛屼互绗﹀悎涓鑸伐涓氬簲鐢ㄧ殑鍔熺巼鍥犳暟銆4. 鏍规嵁涓婅堪鍏紡锛屾垜浠彲浠ヨ绠楀嚭鎵闇鐨鐢垫祦I銆5. 鐢垫祦I=P/鈭3*U*cos蠄=300000/(1.732脳380脳0.8)鈮570A銆6. 鎺ヤ笅鏉ワ紝鎴戜滑闇瑕佸弬鑰鐢电紗鐨勫畨鍏ㄥ伐浣滅數娴侊紝浠ョ‘瀹氭墍闇鐨勭數缂嗘埅闈㈢Н銆7. 閫氬父鎯呭喌涓嬶紝姣忓钩鏂规绫崇殑閾滆姱绾...
绛旓細1銆佸崟鐩哥數锛屼篃灏220V 銆備緷鎹濮嗗畾寰嬶細P=UI7000=220I I=32A锛屽缓璁敤4骞虫柟閾滆姱绾裤2銆佸彟涓绉嶆槸 7KW鐨勪笁鐩哥數鏈猴紝涔熺О鍋(涓夌浉鎰熸ц礋鑽)渚濇嵁鍔熺巼寮忥細P=1.732UI*0.757000=1.732*380*I*0.75 I=14.2A,寤鸿鐢2.5骞虫柟閾滆姱绾裤傚洜涓鐢电嚎璐ㄩ噺锛堝浗鏍囨垨闈炲浗鏍囷級锛岀┛绾挎潯浠讹紙鏄庢暦鎴栨殫绌跨锛夛紝瀹為檯...
