第三题的第一部到第二步的分母是如何化简的？ 根号二分之三怎样化简.讲一下过程，最好让这类的题我都懂。谢谢
\u4e3a\u4e0b\u5217\u5404\u5f0f\u5206\u6bcd\u6709\u7406\u5316\u6216\u5316\u7b80\uff1a\uff081\uff09\u30011/2\u221a(3x-1)\uff081\uff09\u30011/2\u221a(3x-1)
=[\u221a(3x-1)]/2\u221a(3x-1)*\u221a(3x-1)=[\u221a(3x-1)]/2(3x-1)
\uff082\uff09\u30012\u221a6/\uff08\u221a2+\u221a3+\u221a5\uff09
=2\u221a6*[\uff08\u221a2+\u221a3)-\u221a5]/[\uff08\u221a2+\u221a3)+\u221a5]*[\uff08\u221a2+\u221a3)-\u221a5]
=2\u221a6*[\uff08\u221a2+\u221a3)-\u221a5]/2\u221a6
=\u221a2+\u221a3-\u221a5
(3)1/\uff08\u221a5-2\uff09-1/\uff08\u221a5+2\uff09
=\uff08\u221a5+2\uff09/\uff08\u221a5-3)
=\uff08\u221a5+2\uff09*\uff08\u221a5+3)/[\uff08\u221a5-3)*\uff08\u221a5+3)]
=\uff08\u221a5+2\uff09*\uff08\u221a5+3)/(-4)
=\uff0d(11+5\u221a5)/4
\u6839\u53f7\u4e8c\u5206\u4e4b\u4e09\u5316\u7b80\u540e\u5f97\u221a6/2\u3002
\u89e3\uff1a\u221a(3/2)
=\u221a((3*2)/(2*2))
=\u221a(3*2)/\u221a(2*2)
=\u221a(3*2)/2
=\u221a6/2
\u5373\u221a(3/2)\u5316\u7b80\u7684\u7ed3\u679c\u7b49\u4e8e\u221a6/2\u3002
\u6269\u5c55\u8d44\u6599\uff1a
1\u3001\u6700\u7b80\u6839\u5f0f\u7684\u6761\u4ef6
\uff081\uff09\u88ab\u5f00\u65b9\u6570\u6307\u6570\u548c\u6839\u6307\u6570\u4e92\u8d28\uff1b
\uff082\uff09\u88ab\u5f00\u65b9\u6570\u7684\u6bcf\u4e00\u56e0\u5f0f\u7684\u6307\u6570\u90fd\u5c0f\u4e8e\u6839\u6307\u6570\uff1b
\uff083\uff09\u88ab\u5f00\u65b9\u6570\u4e0d\u542b\u5206\u6bcd\u3002
2\u3001\u6839\u5f0f\u7684\u6027\u8d28
\u5f53a\uff1e0\uff0cb\uff1e0\u65f6\uff0c\u221a(ab)=\u221aa*\u221ab\u3002
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u6700\u7b80\u6839\u5f0f
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