初二物理计算题 30道初二上学期物理计算题及答案
\u521d\u4e8c\u7269\u740620\u9053\u5173\u4e8e\u6c42\u901f\u5ea6\u7684\u8ba1\u7b97\u9898\u53ca\u7b54\u6848~~~~~~1.\u4e00\u5217\u957f200\u7c73\u7684\u706b\u8f66\u4e0054\u5343\u7c73/\u65f6\u7684\u901f\u5ea6\u901a\u8fc7\u4e00\u4e2a\u957f700\u7c73\u7684\u5c71\u4e1c\u9700\u8981\u591a\u5c11\u65f6\u95f4?
\u7b54 4km/h=15m/s
t=s/v=(200+700)/15=60s
2.\u8774\u8776\u98de\u7fd4\u7684\u901f\u5ea6\u662f5\u7c73/\u79d2,\u8981\u975e\u5230\u8ddd\u51fa\u53d1\u70b90.6\u5343\u7c73\u7684\u82b1\u56ed,\u5b83\u8981\u82b1\u591a\u5c11\u65f6\u95f4?
\u7b54 t=s/v=600/5=120s
3.\u7532\u3001\u4e59\u4e24\u8f66\u5728\u540c\u4e00\u5e73\u76f4\u516c\u8def\u4e0a\u540c\u5411\u5f62\u5f0f,\u7532\u8f66\u901f\u5ea6\u4e3a10\u5343\u7c73/\u5c0f\u65f6,\u4e59\u8f66\u7684\u901f\u5ea6\u662f30\u5343\u7c73/\u5c0f\u65f6,\u4e59\u8f66\u53d1\u73b0\u5230\u8ffd\u4e0a\u7532\u8f66\u5f62\u5f0f\u4e8615\u5343\u7c73,\u6c42\u4e59\u8f66\u53d1\u73b0\u7532\u8f66\u65f6\u4e24\u8f66\u76f8\u8ddd\u591a\u5c11\u5343\u7c73
\u7b54 \u8bbe\u76f8\u8dddX.
t=15/10=1.5s
30*1.5=10*1.5+X
4.\u7532\u4e59\u4e24\u62b5\u76f8\u8ddd70\u5343\u7c73,\u4e00\u8f86\u6c7d\u8f66\u4ece\u7532\u5730\u5411\u4e59\u5730\u5f00\u51fa,\u901f\u5ea6\u662f15\u7c73/\u79d2,\u4e00\u8f86\u81ea\u884c\u8f66\u540c\u65f6\u4ece\u4e59\u5730\u51fa\u53d1\u9a76\u5411\u7532\u5730,\u4ed6\u4eec\u5728\u79bb\u7532\u573054\u5343\u7c73\u5904\u76f8\u9047.\u6c42\u81ea\u884c\u8f66\u7684\u901f\u5ea6\u662f\u591a\u5c11\u5343\u7c73/\u65f6
\u7b54 15m/s=54km/h
t=54/54=1h
v=s/t=(70-54)/1=16m/s
5.\u4e00\u8258\u5de1\u6d0b\u8230\u752870\u5343\u7c73/\u5c0f\u65f6\u7684\u901f\u5ea6\u8ffd\u8d76\u5728\u5b83\u524d\u976210\u5343\u7c73\u7684\u4e00\u8258\u6218\u6597\u8230,\u5de1\u6d0b\u8230\u8ffd\u4e86210\u5343\u7c73,\u6070\u597d\u8d76\u4e0a\u6218\u6597\u8230,\u6c42\u6218\u6597\u8230\u7684\u901f\u5ea6.
\u7b54 t=s/v=210/70=3h
\u8bbe\u901f\u5ea6\u4e3aV
210=3*V+10
6 \u7528\u4e00\u53ea\u73bb\u7483\u676f\u3001\u6c34\u548c\u5929\u5e73\u6d4b\u5b9a\u77f3\u5b50\u5bc6\u5ea6\uff0c\u5b9e\u9a8c\u8bb0\u5f55\u5982\u4e0b\uff1a\u676f\u5b50\u88c5\u6ee1\u6c34\u540e\u7684\u603b\u8d28\u91cfm1\uff1d200g\uff0c\u653e\u5165\u77f3\u5b50\u540e\uff0c\u676f\u5b50\u3001\u6c34\u3001\u77f3\u5b50\u603b\u8d28\u91cfm2\uff1d215g\uff0c\u53d6\u51fa\u77f3\u5b50\u540e\uff0c\u676f\u5b50\u548c\u6c34\u7684\u603b\u8d28\u91cf\u4e3am3\uff1d190g\uff0c\u6c42\u77f3\u5b50\u5bc6\u5ea6\u3002
\u7b54 m\u77f3=m2-m3=215g-190g=25g
v\u77f3=v\u6c34=\u5012\u51fa\u6c34\u7684\u8d28\u91cf/\u5012\u51fa\u6c34\u7684\u5bc6\u5ea6=200g-190g/1g/cm3=2.5g/cm3
7 \u7532\u4e59\u4e24\u540c\u5b66\u5206\u522b\u5728\u4e00\u8ddf\u94c1\u7ba12\u4fa7\uff0c\u94c1\u7ba1\u957f153\u7c73\uff0c\u7532\u5728\u5176\u4e00\u7aef\u6572\u51fb\u4e86\u4e00\u4e0b\uff0c\u4e59\u540c\u5b66\u542c\u89c1\u4e86\u4e24\u6b21\u58f0\u97f3\u3002\u5df2\u77e5\u542c\u5230\u4e24\u6b21\u58f0\u97f3\u7684\u95f4\u9694\u4e3a0.42\u79d2\u3002\u6c42\u58f0\u97f3\u5728\u94c1\u7ba1\u4e2d\u4f20\u64ad\u7684\u901f\u5ea6\u3002
\u89e3\uff1aT\u7a7a=S\u7a7a\u00f7V\u7a7a=153M\u00f7340M/S=0.45S
T\u94c1=T\u7a7a-0.42S=0.45S-0.42S=0.03S
V\u94c1=S\u00f7T\u94c1=153M\u00f70.03S=5100M/S
\u7b54\uff1a\u58f0\u97f3\u5728\u94c1\u7ba1\u4e2d\u4f20\u64ad\u901f\u5ea6\u4e3a5100\u7c73/\u79d2\u3002
8 \u9898\u76ee\uff1a\u6709\u4e00\u5c71\u5ce1\u5bbd1200\u7c73\uff0c\u4e24\u65c1\u90fd\u662f\u7ad6\u76f4\u5f92\u58c1\uff0c\u6709\u4e00\u4eba\u5728\u5c71\u5ce1\u5185\u653e\u4e00\u67aa\uff0c\u5934\u4e24\u6b21\u56de\u58f0\u95f4\u96945\u79d2\uff0c\u5219\u4eba\u79bb\u4e24\u58c1\u7684\u8ddd\u79bb\u662f\u591a\u5c11\uff1f\uff08\u8bbe\u58f0\u901fv\uff1d340\u7c73\uff0f\u79d2\uff09
\u7b54\u6848\uff1a1025\u7c73\uff0c175\u7c73\u3002
\u89e3\uff1a\u8bbe\u8ddd\u79bb\u4e3as,1200-s
s/340-(1200-s)/340=1200
s=1025
9 \u6709\u4e00\u5c71\u5ce1\u5bbd1200\u7c73\uff0c\u4e24\u65c1\u90fd\u662f\u5ced\u58c1\u3002\u6709\u4eba\u5728\u5c71\u5ce1\u5185\u653e\u4e00\u67aa\uff0c\u4ed6\u542c\u5230\u5934\u4e24\u6b21\u56de\u58f0\u95f4\u96945\u79d2\uff0c\u6c42\u8fd9\u4e2a\u4eba\u79bb\u4e24\u5ced\u58c1\u7684\u8ddd\u79bb\u3002\uff08\u7a7a\u6c14\u4e2d\u58f0\u901f\u4e3a340m/s\uff09
\u89e3\uff1a\u8bbe\u4eba\u79bb\u4e00\u5ced\u58c1\u7684\u8ddd\u79bb\u4e3ax,\u79bb\u53e6\u4e00\u5ced\u58c1\u7684\u8ddd\u79bb\u4e3a1200-x
\u5219\u58f0\u97f3\u5230\u4e24\u5ced\u58c1\u5e76\u8fd4\u56de\u7684\u65f6\u95f4\u5206\u522b\u4e3a\uff1a2x/340,2(1200-x)/340.
\u7531\u9898\u610f\uff0c2x/340-2(1200-x)/340=5
\u89e3\u5f97x=1025,1200-x=175
\u6240\u4ee5\u4eba\u79bb\u4e24\u5ced\u58c1\u7684\u8ddd\u79bb\u5206\u522b\u4e3a1025\u7c73\u548c175\u7c73\u3002
10 \u4e00\u95e8\u53cd\u5766\u514b\u70ae\u7784\u51c6\u4e00\u8f86\u5766\u514b\uff0c\u5f00\u70ae\u540e\u7ecf\u8fc70.6s\u770b\u5230\u70ae\u5f39\u5728\u5766\u514b\u4e0a\u7206\u70b8\uff0c\u7ecf\u8fc72.1s\u542c\u5230\u7206\u70b8\u7684\u58f0\u97f3\uff0c\u6c42\u5927\u70ae\u8ddd\u5766\u514b\u591a\u5143\uff1f\u70ae\u5f39\u7684\u98de\u884c\u901f\u5ea6\u591a\u5927\uff1f
\u8ddd\u79bbS\uff1d2.1*340m=714m
\u7b54 \u98de\u884c\u901f\u5ea6\uff1av=S/t=714/0.6=1190m/s
1.\u5f20\u660e\u4e0e\u674e\u7ea2\u4e24\u540d\u540c\u5b66\u6b32\u6d4b\u4e00\u6bb5\u94c1\u8def\u957f\uff0c\u4f46\u6ca1\u6709\u5408\u9002\u7684\u76f4\u5c3a\u3002\u4ed6\u4eec\u77e5\u9053\u58f0\u97f3\u5728\u7a7a\u6c14\u4e2d\u4e0e\u5728\u94a2\u94c1\u4e2d\u4f20\u64ad\u7684\u901f\u5ea6\u5206\u522b\u4e3a340m/s\u548c5000m/s\u3002\u4e8e\u662f\u5f20\u660e\u7ad9\u5728\u6b32\u6d4b\u94c1\u8def\u7684\u4e00\u7aef\uff0c\u674e\u7ea2\u7ad9\u5728\u53e6\u4e00\u7aef\uff0c\u5f20\u660e\u7528\u9524\u5b50\u6572\u51fb\u4e00\u4e0b\u94c1\u8f68\uff0c\u674e\u7ea2\u542c\u5230\u4e24\u6b21\u54cd\u58f0\u7684\u65f6\u95f4\u76f8\u5dee2s\u3002\u95ee\uff1a\u8fd9\u6bb5\u94c1\u8def\u957f\u6709\u591a\u5c11\uff1f
\u5148\u542c\u5230\u7684\u80af\u5b9a\u662f\u4ece\u94c1\u8f68\u4e0a\u4f20\u6765\u7684\uff0c\u518d\u542c\u5230\u7a7a\u6c14\u4e2d\u4f20\u6765\u7684\uff0c
\u8bbe\u8def\u7a0b\u4e3aS
S\uff0f340 -S\uff0f5000\uff1d2
\u89e3\u5f97S\uff1d729.6m
1\u3001 \u4e00\u4e2a\u7269\u4f53\u505a\u5300\u901f\u76f4\u7ebf\u8fd0\u52a8\uff0c8\u79d2\u5185\u901a\u8fc7\u7684\u8def\u7a0b\u4e3a16m\uff0c\u95ee\u6700\u521d3s\u5185\u7684\u8fd0\u52a8\u901f\u5ea6\u662f\u591a\u5c11\uff1f
2\u3001 \u6c7d\u8f66\u4eceA\u7ad9\u51fa\u53d1\uff0c\u4ee590Km/h\u7684\u901f\u5ea6\u884c\u9a76\u4e8620min\u540e\u5230\u8fbeB\u7ad9\uff0c\u53c8\u4ee560Km/h\u7684\u901f\u5ea6\u884c\u9a76\u4e8610min\u5230\u8fbeC\u7ad9\uff0c\u95ee\uff081\uff09\u4e24\u7ad9\u76f8\u8ddd\u591a\u8fdc\uff1f\uff082\uff09\u6c7d\u8f66\u4eceA\u7ad9\u5230C\u7ad9\u7684\u5e73\u5747\u901f\u5ea6\uff1f
3\u3001 \u4e00\u53ea\u8239\u5728\u6d77\u4e0a\u884c\u9a76\uff0c\u8239\u4e0a\u53d1\u51fa\u4e00\u9e23\u7b1b\u58f0\uff0c\u65c5\u5ba2\u57284s\u540e\u542c\u5230\u524d\u65b9\u60ac\u5d16\u53cd\u5c04\u56de\u6765\u7684\u58f0\u97f3\uff0c\u95ee\uff081\uff09\u5982\u679c\u8239\u9e23\u7b1b\u540e\u9a6c\u4e0a\u505c\u6b62\u884c\u9a76\uff0c\u6c42\u60ac\u5d16\u4e0e\u8239\u7684\u8ddd\u79bb\u3002\uff082\uff09\u82e5\u9e23\u7b1b\u540e\u8239\u4ee520m/s\u7684\u901f\u5ea6\u7ee7\u7eed\u5411\u524d\u884c\u9a76\uff0c\u6c42\u60ac\u5d16\u4e0e\u65c5\u5ba2\u542c\u5230\u56de\u58f0\u5904\u7684\u8ddd\u79bb\uff1f
1\u3001\u5df2\u77e5\u58f0\u97f3\u5728\u7a7a\u6c14\u4e2d\u4f20\u64ad\u7684\u901f\u5ea6\u4e3aV1\uff0c\u5728\u94a2\u7ba1\u4e2d\u4f20\u64ad\u7684\u901f\u5ea6\u4e3aV2\uff0c\u7532\u5728\u94a2\u7ba1\u7684\u4e00\u7aef\u6572\u51fb\u4e00\u6b21\uff0c\u4e59\u5728\u94a2\u7ba1\u7684\u53e6\u4e00\u7aef\u542c\u5230\u4e24\u6b21\u54cd\u58f0\u4e4b\u95f4\u76f8\u9694\u4e86t\uff0c\u5219\u94a2\u7ba1\u7684\u957f\u7ea6\u4e3a\u591a\u5c11\uff1f
2.\u7ad9\u5728\u767e\u7c73\u8dd1\u9053\u7ec8\u70b9\u8ba1\u65f6\u53f0\u4e0a\u7684\u7532\u4e59\u4e24\u540d\u8ba1\u65f6\u5458\uff0c\u4e3a\u540c\u4e00\u8dd1\u9053\u4e0a\u7684\u8fd0\u52a8\u5458\u8ba1\u65f6\uff0c\u7532\u770b\u5230\u8d77\u8dd1\u53d1\u4ee4\u67aa\u5192\u70df\u65f6\u5f00\u59cb\u8ba1\u65f6\uff0c\u800c\u4e59\u5219\u542c\u5230\u53d1\u4ee4\u67aa\u58f0\u624d\u5f00\u59cb\u8ba1\u65f6\uff0c\u5219\uff1a
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TAXI \u8f66\u8d39\u53d1\u7968
\u8f66\u53f7\u7801
\u5dddF-71238
\u65e5\u671f 05-09-28
\u4e0a\u8f66 10\u223600
\u4e0b\u8f66 10\u223605
\u5355\u4ef7 2.00\u5143
\u91cc\u7a0b 6.0km
\u91d1\u989d 16.00\u5143
\u67d0\u4eba\u4e58\u5750\u51fa\u79df\u8f66\u5728\u5e73\u76f4\u516c\u8def\u4e0a\u5300\u901f\u884c\u9a76\uff0c\u53f3\u4e3a\u4ed6\u4e58\u8f66\u5230\u8fbe\u76ee\u7684\u5730\u65f6\u7684\u8f66\u8d39\u53d1\u7968\u3002\u6c42\uff1a
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1. \u58f0\u97f3\u5728\u7a7a\u4e2d\u7684\u4f20\u64ad\u901f\u5ea6\u662f335\u7c73/\u79d2.\u4e00\u67b6\u57282680\u7c73\u9ad8\u7a7a\u98de\u884c\u7684\u98de\u673a\u53d1\u51fa\u6765\u7684\u58f0\u97f3,\u4f20\u5230\u5730\u9762\u6240\u7528\u7684\u6700\u77ed\u65f6\u95f4\u662f\u591a\u5c11
2. \u7528\u56de\u58f0\u53ef\u4ee5\u5e2e\u52a9\u8239\u53ea\u6d4b\u91cf\u6c34\u6df1,\u56e0\u6b64\u5728\u6d77\u6d0b\u548c\u6c5f\u6cb3\u7684\u8003\u5bdf\u8239\u4e0a\u90fd\u88c5\u7f6e\u6709\u58f0\u7eb3.\u5982\u679c\u58f0\u97f3\u5728\u6c34\u4e2d\u7684\u4f20\u64ad\u901f\u5ea6\u4e3a1500\u7c73/\u79d2,\u5728\u8003\u5bdf\u65f6\u53d1\u51fa\u58f0\u97f30.8\u79d2\u949f\u540e\u63a5\u6536\u5230\u4e86\u56de\u58f0,\u8fd9\u91cc\u7684\u6c34\u6df1\u4e3a\u591a\u5c11
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(1)202\u6b21\u5217\u8f66\u8fd0\u884c\u5168\u7a0b\u7684\u65f6\u95f4\u662f h\uff0e
(2)\u5217\u8f66\u8fd0\u884c\u5168\u7a0b\u7684\u5e73\u5747\u901f\u5ea6\u662f\u591a\u5c11?
2005\u5e745\u670815\u65e5\uff0c\u5357\u4eac\u4eba\u7ec8\u4e8e\u5750\u4e0a\u4e86\u671f\u76fc\u5df2\u4e45\u7684\u5730\u94c1\uff0c\u76ee\u524d\u5f00\u901a\u7684\u5730\u94c1\u4e00\u53f7\u7ebf\u5728\u5965\u4f53\u4e2d\u5fc3\u548c\u8fc8\u768b\u6865\u4e4b\u95f4\u884c\u9a76\uff0e\u5217\u8f66\u4ece\u5965\u4f53\u4e2d\u5fc3\u884c\u9a76\u5230\u8fc8\u768b\u6865\u5927\u7ea6\u970024min\u7684\u65f6\u95f4\uff0c\u8fd0\u884c\u7684\u5e73\u5747\u901f\u5ea6\u4e3a55km\uff0fh\uff0e\u6c42\uff1a
(1)\u5730\u94c1\u4ece\u5965\u4f53\u4e2d\u5fc3\u5230\u8fc8\u768b\u6865\u901a\u8fc7\u7684\u8def\u7a0b\u5927\u7ea6\u662f\u591a\u5c11\u5343\u7c73?
(2)\u82e5\u91c7\u7528\u78c1\u60ac\u6d6e\u5217\u8f66\u901f\u5ea6\u53ef\u4ee5\u8fbe\u5230400km/h,\u5219\u7531\u5965\u4f53\u4e2d\u5fc3\u8fd0\u884c\u5230\u8fc8\u768b\u6865\u91c7\u7528\u78c1\u60ac\u6d6e\u6280\u672f\u7684\u5217\u8f66\u6bd4\u5730\u94c1\u5217\u8f66\u8fd0\u884c\u7684\u65f6\u95f4\u53ef\u4ee5\u8282\u7ea6\u591a\u5c11\u5206\u949f?
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1)水的质量即冰融化而来的，所以其质量即为冰的质量，所以：m水=m冰=ρ冰*v冰=0.9 g/cm^3* 200 cm^3=180 g=0.18 kg
2)水的体积为：
v水= m水/ρ水=180 g/ 1.0 g/cm^3= 180 cm^3 (cm^3 表示立方厘米，其它相似)
3)此时水的深度为：
h= v水/s底=180 cm^3/ 30 cm^2= 6 cm=0.06 m
所以：
P=ρ水*g*h=1.0 *10^3 kg/m^3* 10N/kg*0.06 m= 600 Pa
4) 当水平B管内吹气时，A管内的水位会上升，原理是：A管上方的空气流动大，压强小，造成水位的上升。
（1）m水=m冰=200*0.9=180g
（2）V水=m水/p水=180/1=180cm^3
（3）P=F/S=G/S=mg/S=0.18*10/0.003=600Pa
（4）A管中的液面上升；气体流速越大，压强越小
19.（1）m冰=ρ冰V冰=0.9g/cm^3*200cm^3=180g
∴m水=m冰=180g
(2)V水=m水/ρ水=180g/1gcm^3=180cm^3
（3）h=V水/S=180cm^3/30cm^2=6cm
∴P水=ρ水gh=1g/cm^3*10N/kg*6cm=600Pa
（4）看到水面上升（或水成雾状喷出）
因为在流体中，流速大的位置压强小，流速小的位置压强大
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绛旓細1.瑙ｏ細10*3=30锛堢背锛340绫/绉*3=1020锛堢背锛夌畻姹借溅鍚埌鍥炲０鏃惰窛灞卞礀鐨勮窛绂伙細锛1020-30锛/2=495锛堢背锛495+30=525锛堢背锛2.瑙ｏ細4*340绫/绉=1360锛堢背锛1360-700=660锛堢背锛夛紙700-660锛/4=10绫/绉 3.x/340-x/5200=8 4.瑙ｏ細1/2=0.5锛堢锛1.5脳103m/s脳0.5=0.75脳103m/s 5....
绛旓細1锛夊綋AB鏀惧湪姘村钩妗岄潰涓婃椂锛屽畠浠妗岄潰鐨勫帇鍔汧=G锛屾牴鎹甈=F/S鏈塅=PS锛孏A=PASA锛汫B=PBSB锛孏A/GB=PASA/PBSB锛孭A/PB=1/2锛 GA/GB=SA/2SB 锛1锛夌敱浜庡畠浠殑瀵嗗害鐩稿悓锛屽張鏄寑鍧囩墿浣擄紝鎵浠ュ畠浠妗岄潰鐨勫帇寮篜=hpg锛孭A=hApg锛孭B=hBpg锛孭A/PB=hA/Hb=1/2锛岄偅涔堝畠浠殑搴曢潰绉疭A/SB=ha^2/...
绛旓細1 銆佹煇璇炬湰璐ㄩ噺涓 200 鍏嬶紝骞虫斁鍦ㄦ闈笂锛屼笌妗岄潰鐨勬帴瑙﹂潰绉槸 5 脳 10 -2 銕★紝姹傚畠瀵 妗岄潰鐨勫帇寮猴紵2 銆佸皬鑾夊悓瀛︾殑璐ㄩ噺涓 45 銕忥紝濂规瘡鍙瀷涓庡湴闈㈢殑鎺ヨЕ闈㈢Н鏄 1.5 脳 10 -2 銕★紝姹傚ス绔欑珛 鏃跺鍦伴潰鐨勫帇寮猴紵3 銆佷竴鍧楅暱鏂瑰舰鐨勬鐨川閲忎负 30 鍏嬶紝渚ф斁鍦ㄦ按骞虫闈笂锛屽畠涓庢闈㈢殑鎺ヨЕ闈㈢Н涓...
绛旓細瑙ｏ細L=1/2 脳S=1/2 脳vt=1/2脳1500m/s脳2.4s=1800m t'=s鈥櫭穠脳2=300m梅1500m/s脳2=0.4s 绛旓細娴锋按鐨勬繁搴﹀ぇ绾︽槸1800m锛涘０鍛愬彲浠ュ湪0.4s鐨勬椂闂村悗鎺ユ敹鍒颁粠娼滆墖鍙嶅皠鍥炴潵鐨勪俊鍙枫
绛旓細1銆佷竴鍒楃伀杞﹂暱200m锛屼互20m/s鐨勯熷害鍖閫熼氳繃涓搴1.8km鐨勫ぇ妗ラ渶瑕佸闀挎椂闂达紵2銆佸悜鏈堢悆鍙戝嚭鐨勬棤绾跨數娉㈠埌杈炬湀鐞冨悗鍐嶈繑鍥炲湴闈㈠叡闇2.56s锛屾棤绾跨數娉㈢殑浼犳挱閫熷害鏄3脳105km/s锛屾眰鍦扮悆鍒版湀鐞冪殑璺濈銆3銆1m3鐨勫啺鐔斿寲鎴愬悗姘翠綋绉湁澶氬ぇ锛4銆佸浣曠敤閲忕瓛閲忓嚭1000g閰掔簿锛5銆佷竴涓摱瀛愯兘瑁2kg姘达紝瀹冩渶澶氬彲瑁呭灏...
绛旓細1)姘寸殑璐ㄩ噺鍗冲啺铻嶅寲鑰屾潵鐨勶紝鎵浠ュ叾璐ㄩ噺鍗充负鍐扮殑璐ㄩ噺锛屾墍浠ワ細m姘=m鍐=蟻鍐*v鍐=0.9 g/cm^3* 200 cm^3=180 g=0.18 kg 2)姘寸殑浣撶Н涓猴細v姘= m姘/蟻姘=180 g/ 1.0 g/cm^3= 180 cm^3 (cm^3 琛ㄧず绔嬫柟鍘樼背锛屽叾瀹冪浉浼)3)姝ゆ椂姘寸殑娣卞害涓猴細h= v姘/s搴=180 cm^3/ 30 cm...
绛旓細绛旀锛1锛庢瘡鑺傛补缃愯溅鐨勫绉负50m3锛屼粠娌圭綈涓彇鍑20cm3鐨勬补锛岃川閲忎负17鍏嬶紝涓婊＄綈鐨勬补鐨勮川閲忔槸澶氬皯鍚?p=m/v m=17g=0.017kg,v=20cm^3=20*10^(-6)m^3 閭ｄ箞娌圭殑瀵嗗害鏄痯=0.017/[20*10^(-6)]=0.85*10^3kg/m^3 V=50m^3 鍗虫荤殑璐ㄩ噺鏄細m=pV=0.85*10^3*50=42.5*10^3kg...
绛旓細锛1锛夌煶鏂欏鍩哄骇鐨勫帇寮 鐢盤=F/S F1=G1=mg=2.0x10^5N P1=F1/S1=1.67x10^5pa 锛2锛夊熀搴у鍦伴潰鐨勫帇寮 F2=G1+G2 G2=蟻gv2 v2=2x1x0.4=0.8m^3 G2=16000N P2=f2/s2=2.16x10^5N/2=1.08x10^5pa
