求一个c语言程序代码，可以把16进制数串转ascll码 c语言ascii码转换为十进制的数值
C\u8bed\u8a00\u7f16\u7a0b\u8f93\u5165\u5b57\u7b26\u8f93\u51fa\u5b57\u7b26\u7684ascll\u7801unsigned char HexToChar(unsigned char bChar){if((bChar>=0x30)&&(bChar=0x41)&&(bChar=0x61)&&(bChar<=0x66))//\u5c0f\u5199\u5b57\u6bcdbChar -= 0x57;else bChar = 0xff;return \u201cThe ASCII of ch\u201d&& bChar\u3002
C\u8bed\u8a00\u5e38\u7528\u8f6c\u4e49\u5b57\u7b26
\u5b57\u7b26\u5e38\u91cf\u4e2d\u4f7f\u7528\u5355\u5f15\u53f7\u548c\u53cd\u659c\u6760\u4ee5\u53ca\u5b57\u7b26\u5e38\u91cf\u4e2d\u4f7f\u7528\u53cc\u5f15\u53f7\u548c\u53cd\u659c\u6760\u65f6\uff0c\u90fd\u5fc5\u987b\u4f7f\u7528\u8f6c\u4e49\u5b57\u7b26\u8868\u793a\uff0c\u5373\u5728\u8fd9\u4e9b\u5b57\u7b26\u524d\u52a0\u4e0a\u53cd\u659c\u6760\u3002
\u5728C\u7a0b\u5e8f\u4e2d\u4f7f\u7528\u8f6c\u4e49\u5b57\u7b26\ d d d\u6216\u8005\ x h h\u53ef\u4ee5\u65b9\u4fbf\u7075\u6d3b\u5730\u8868\u793a\u4efb\u610f\u5b57\u7b26\u3002\ d d d\u4e3a\u659c\u6760\u540e\u9762\u8ddf\u4e09\u4f4d\u516b\u8fdb\u5236\u6570\uff0c\u8be5\u4e09\u4f4d\u516b\u8fdb\u5236\u6570\u7684\u503c\u5373\u4e3a\u5bf9\u5e94\u7684\u516b\u8fdb\u5236A S C I I\u7801\u503c\u3002\ x\u540e\u9762\u8ddf\u4e24\u4f4d\u5341\u516d\u8fdb\u5236\u6570\uff0c\u8be5\u4e24\u4f4d\u5341\u516d\u8fdb\u5236\u6570\u4e3a\u5bf9\u5e94\u5b57\u7b26\u7684\u5341\u516d\u8fdb\u5236A S C I I\u7801\u503c\u3002
\u4f7f\u7528\u8f6c\u4e49\u5b57\u7b26\u65f6\u9700\u8981\u6ce8\u610f\u4ee5\u4e0b\u95ee\u9898\uff1a
\u8f6c\u4e49\u5b57\u7b26\u4e2d\u53ea\u80fd\u4f7f\u7528\u5c0f\u5199\u5b57\u6bcd\uff0c\u6bcf\u4e2a\u8f6c\u4e49\u5b57\u7b26\u53ea\u80fd\u770b\u4f5c\u4e00\u4e2a\u5b57\u7b26\u3002
\v\u5782\u76f4\u5236\u8868\u548c\f\u6362\u9875\u7b26\u5bf9\u5c4f\u5e55\u6ca1\u6709\u4efb\u4f55\u5f71\u54cd\uff0c\u4f46\u4f1a\u5f71\u54cd\u6253\u5370\u673a\u6267\u884c\u54cd\u5e94\u64cd\u4f5c\u3002
\u5728C\u7a0b\u5e8f\u4e2d\uff0c\u4f7f\u7528\u4e0d\u53ef\u6253\u5370\u5b57\u7b26\u65f6\uff0c\u901a\u5e38\u7528\u8f6c\u4e49\u5b57\u7b26\u8868\u793a\u3002
\u603b\u4e4b\uff1a
\v\u5782\u76f4\u5236\u8868\u548c\f\u6362\u9875\u7b26\u5bf9\u5c4f\u5e55\u6ca1\u6709\u4efb\u4f55\u5f71\u54cd\uff0c\u4f46\u4f1a\u5f71\u54cd\u6253\u5370\u673a\u6267\u884c\u54cd\u5e94\u64cd\u4f5c\u3002\n\u5176\u5b9e\u5e94\u8be5\u53eb\u56de\u8f66\u6362\u884c\u3002\u6362\u884c\u53ea\u662f\u6362\u4e00\u884c\uff0c\u4e0d\u6539\u53d8\u5149\u6807\u7684\u6a2a\u5750\u6807\uff1b\u56de\u8f66\u53ea\u662f\u56de\u5230\u884c\u9996\uff0c\u4e0d\u6539\u53d8\u5149\u6807\u7684\u7eb5\u5750\u6807\u3002\t\u5149\u6807\u5411\u524d\u79fb\u52a8\u56db\u683c\u6216\u516b\u683c\uff0c\u53ef\u4ee5\u5728\u7f16\u8bd1\u5668\u91cc\u8bbe\u7f6e\u3002\'\u5728\u5b57\u7b26\u91cc\uff08\u5373\u5355\u5f15\u53f7\u91cc\uff09\u4f7f\u7528\u3002\u5728\u5b57\u7b26\u4e32\u91cc(\u5373\u53cc\u5f15\u53f7\u91cc)\u4e0d\u9700\u8981\uff0c\u53ea\u8981\u7528'\u5373\u53ef\u3002\?\u5176\u5b9e\u4e0d\u5fc5\u8981\u3002\u53ea\u8981\u7528?\u5c31\u53ef\u4ee5\u4e86\u3002
#include int main() {int arr[] = {'a','p','Q','oi','\0X89','\077'};int i,n = sizeof(arr)/sizeof(arr[0]);for(i = 0; i < n; ++i)printf("%8d\to%-8o\t0X%-8X\n",arr[i],arr[i],arr[i]);return 0;}
分析题目，61刚好是a的ascii十六进制值，因此，只需要将‘6’‘1’转换成数值0x61就可以了，以下采用移位方法来转换
#include<stdio.h>
int main()
{
int i;
char str[128],ch=0;
gets(str);
for( i=0;str[i];i++ )
{
if ( str[i]>='0' && str[i] <= '9' )
{
ch <<= 4 ; //先左移四位 6放到前四位,1放到后四位
ch |= str[i]-'0'; //把当前数并到ch中
}
else
{
printf("%c", ch );
}
}
printf("%c
", ch );
return 0;
}
#include<stdio.h>
void main()
{
char str[100],str1[50];
int i=0,data=0,j=0;
gets(str);
while(str[i]!='\0')
{
data=16*data+str[i]-'0';
if(str[i]==' ')
{
data = (data-str[i]+'0')/16;
str1[j++]=(char)data;
data=0;
}
i++;
if(str[i]=='\0')
{
str1[j++]=(char)data;
data=0;
}
}
str1[j]='\0';
printf("%s
",str1);
}
绛旓細绗竴閮ㄥ垎锛歩nclude "stdio.h"int main(){ int sum = 0,n = 1;while (5*n+4 <= 1001){ sum += 5*n+4;n++;} printf("%d\n",sum);return 0;} 绗簩閮ㄥ垎锛歩nclude "stdio.h"int main(){ int n;printf("please input the number n:");while (scanf("%d",&n)&& n != 0...
绛旓細include<stdio.h> void main(){ int i,sum=0;for(i=1;i<=100;i++){ sum+=i;} printf("%d\n",sum);}
绛旓細str[128],ch=0;gets(str);for( i=0;str[i];i++ ){if ( str[i]>='0' && str[i] <= '9' ){ch <<= 4 ; //鍏堝乏绉诲洓浣 6鏀惧埌鍓嶅洓浣,1鏀惧埌鍚庡洓浣峜h |= str[i]-'0'; //鎶婂綋鍓嶆暟骞跺埌ch涓瓆else{printf("%c", ch );}}printf("%c\n", ch );return 0;} ...
绛旓細void F1(int n){ double result = 0;for(double i=1;i<=n;i++)result += 1/i;for(int i=1;i<n;i++){ printf("1/%d + ", i);} printf("1/%d = %f\r\n", n, result);}
绛旓細/*鎶婁竴寮犱竴鍏冪殑閽炵エ锛屾崲鎴愪竴鍒嗭紝浜屽垎锛屽拰浜斿垎鐨勭‖甯侊紝姣忕鑷冲皯浜旀灇锛岄棶鏈夊灏戠鏂规*/#include <stdio.h> int main() { int n1, n2, n5; for (n1 = 5; n1 <= 65; n1++) //鍥犱负2鍜5鑷冲皯5鏋氾紝鎵浠1鑷冲鏈65 for (n2 = 5; n2 <= 35; n2++) //鍚岀悊1鍜5...
绛旓細鍒氱紪浜嗕竴涓細鎶12鏋氶摱甯佺紪鍙锛1,2,3,...12锛屾瘡娆＄О閲嶇殑鏃跺欙紝鎸夌収绋嬪簭鎻愮ず杩涜锛岃緭鍏ョО閲嶇粨鏋滐紝灏卞彲浠ヤ簡銆傝繍琛岀粨鏋滐細5銆6銆7銆8 姣 1銆2銆3銆4:(杈撳叆:0绛,1杞,2閲)?2 3銆4銆6 姣 1銆2銆5:(杈撳叆0绛,1杞,2閲)?1 5銆4 姣 11銆12 (杈撳叆0:绛,1杞,2閲)?2 鍋囧竵5閲 婧愮▼搴...
绛旓細杈撳叆鍙寘鍚0鍜1 鐨勫瓧绗︿覆锛屽啀鎶 杩欎竴涓瓧绗︿覆鐨勬瘡涓涓瓧绗﹁浆鎹㈡垚瀵瑰簲鐨勫崄杩涘埗鏁 鐩稿姞锛屾眰寰楄緭鍏ヤ簩杩涘埗鏁扮殑鍗佽繘鍒舵暟锛岀劧鍚庣敤printf()鍑芥暟杈撳嚭锛宲rintf()鍑芥暟鍙鐢ㄤ笉鍚岀殑鍙傛暟灏卞彲浠ヨ緭鍑轰笉鍚岃繘鍒剁殑褰㈠紡锛屽叏閮浠ｇ爜濡備笅锛歩nclude <stdio.h> include <conio.h> include <math.h> include <string.h> ...
绛旓細main(){ int i;for (i=1;i<=100;i++) if (i%2 && i%3 && i%4) printf("%d\t",i);} 浠ヤ笂绋嬪簭瀹炵幇姣忚10涓殑鍔炴硶鏄氳繃\t锛屾棤闇鍏跺畠浠讳綍浠ｇ爜锛杈撳嚭鐨勭粨鏋滆嚜鐒舵瘡琛10涓紝骞朵笖宸﹁竟瀵归綈銆
绛旓細int main(){ int num, i, j;printf("璇疯緭鍏ヤ竴涓暟:");num = scanf("%d", &num);puts("杩欐牱鐨5涓暟涓:");for(i = num + 1, j = 0; j < 5; i++){ if(isPrime(i)){ printf("%d,", i);j++;} } return 0;} int isPrime(int n){ int i;for(i = 2; i <= (...
绛旓細鐪嬬湅 main(){ int i,n;scanf("%d",&n);for(i=1;i<=10;i++){ printf("%d\t", i*n);if (i%2==1) printf("\n");} return 0;}
