初三数学因式分解大神们帮忙啊
\u521d\u4e09\u6570\u5b66\u56e0\u5f0f\u5206\u89e3\u5927\u795e\u5e2e\u5e2e\u5fd9\u554a!\u539f\u5f0f=(5x²+2xy)-(15x+6y)
=x(5x+2y)-3(5x+2y)
=(5x+2y)(x-3)
4004与分子约分结果为1/8
2）每个都用平方差公式结果为
（1-1/2)（1+1/2) (1-1/3)（1+1/3)……(1-1/100)（1+1/100)
=1/2 ×3/2 ×2/3×4/3× 3/4×5/4……99/100×101/100
=1/2 ×（3/2 ×2/3）×（4/3× 3/4）×（5/4……99/100）×101/100
=1/2×101/100
=101/200
绛旓細=2(x+2)(x+1)
绛旓細绗竴棰樺埄鐢ㄥ钩鏂瑰樊鍏紡锛岄鍏堟妸9鍜16杞寲涓3²鍜4²鐒跺悗浠ｅ叆寮忓瓙锛屽氨浼氬彉鎴愶紙6x-3y锛²-锛4x+8y锛²锛岀劧鍚庝娇鐢ㄥ钩鏂瑰樊鍏紡灏辫浜嗐傦紙a+b锛夛紙a-b锛=a²-b²銆傛渶鍚庡緱鍒帮紙10x+5y锛夛紙2x-11y锛=5锛2x+y锛夛紙2x-11y锛夈傜浜岄锛屾敞鎰忓埌x锛2-x锛夊氨鏄-锛坸...
绛旓細鍒濅笁鏁板 鍒嗚В鍥犲紡娉 鎶婁竴涓椤瑰紡鍖栦负鍑犱釜鏈绠鏁村紡鐨勭Н鐨勫舰寮忥紝杩欑鍙樺舰鍙仛鎶婅繖涓椤瑰紡鍥犲紡鍒嗚В锛屼篃鍙綔鍒嗚В鍥犲紡 姣斿锛 ax+ay+bx+by =a(x+y)+b(x+y) =(a+b)(x+y) 5ax+5bx+3ay+3by =5x(a+b)+3y(a+b) =(5x+3y)(a+b) 鐭ラ亾鏇村 鐐归夌櫨绉 :baike.baidu./...
绛旓細鍒濅笁鏁板鍥犲紡鍒嗚В娉 绡1 璁稿鏁板闂鐨勬湁鍔涘伐鍏枫傚洜寮忓垎瑙ｆ柟娉曠伒娲,鎶宸фу己,瀛︿範杩欎簺鏂规硶涓庢妧宸,涓嶄粎鏄帉鎻″洜寮忓垎瑙ｅ唴瀹规墍蹇呴渶鐨,鑰屼笖瀵逛簬鍩瑰吇瀛︾敓鐨勮В棰樻妧鑳,鍙戝睍瀛︾敓鐨勬濈淮鑳藉姏,閮芥湁鐫鍗佸垎鐙壒鐨勪綔鐢ㄣ傚垵涓暟瀛︽暀鏉愪腑涓昏浠嬬粛浜嗘彁鍙栧叕鍥犲紡娉曘佽繍鐢ㄥ叕寮忔硶銆佸垎缁勫垎瑙ｆ硶鍜屽崄瀛楃浉涔樻硶銆傝屽湪绔炶禌涓,鍙堟湁鎷嗛」鍜屾坊椤规硶,...
绛旓細鍘熷紡=[4锛坸-y锛塢²-[5(x+y)]²=[4锛坸-y锛+5(x+y)][4锛坸-y锛-5(x+y)]=(9x+y)(-x-9y)=-(9x+y)(x+9y)鍘熷紡=(x-y)(x+y)-(x-y)²=(x-y)(x+y-(x-y))=(x-y)路2y =2y(x-y)
绛旓細鎴栬厁=14 锛2x-1+3-x)(2x-1-3+x)=0 (2x-2)(3x-4)=0 x=1,鎴栬厁=4/35 (3x-2)(2x+1)=0 3x-2=0,鎴栬2x+1=0 閭ｄ箞锛寈=2/3,鎴栬厁=-1/26 (x-4+5-2x)(x-4-5+2x)=0 (1-x)(3x-8)=0 x=1,鎴栬厁=8/3 ...
绛旓細鍥炵瓟锛(1) =x*y*(x+y)=96 (2) =(x+y)^2-3*x*y=64-36=28 (3) =((x+y)^2-4*x*y)^0.5=(64-48)^0.5=4
绛旓細瑙 x²+6x+5 =(x²+6x+9)-9+5 =(x+3)²-4 =(x+3-2)(x+3+2)=(x+1)(x+5)m²-12mn-28n²=(m²-12mn+36n²)-36n²-28n²=(m-6n)²-64n²=(m-6n-8n)(m-6n+8n)=(m-14n)(m+2n)...
绛旓細1.(x-y)²-x²=(x-y-x)(x-y+x)=-y(2x-y)2.4(x-y)²-4z(x-y)+z²=(2x-2y-z)²3.(1-1/2²)(1-1/3²)...(1-1/10²).=(1-1/2)(1+1/2)(1-1/3)(1+1/3)(1-1/4)(1+1/4)...(1-1/10)(1+1/10)=1...
绛旓細1銆佹鐤慳-2b涓巃+2b鎼為敊浜嗐傚鏋滈兘鏄痑-2b鎴栬呴兘鏄痑+2b銆傚氨鍙涓簒.x²-7x-44=(x-11)(x+4)2銆乵+n=x 鈫 x²-3x+2=(x-1)(x-2)3銆乸-q=x 鈫 x²+x-20=(x-4)(x+5)4銆佸悓鏍风殑鏂规硶 x²-7x-8=(x-8)(x+1)5銆乤(a²-4b²)-(a-...
