求偏导数:(1)z=sin(xy)+cos(x+y)(2)z=(1+xy)的y次方 sin(x+z)=cos(y+z)一阶偏导数

\u6c42z=sin(xy)+cos^2(xy)\u7684y\u7684\u504f\u5bfc

Zy=ycos\uff08xy\uff09+2cos\uff08xy\uff09*[-sin\uff08xy\uff09]*x
=ycos\uff08xy\uff09-xsin\uff082xy\uff09

\u3000\u3000\u6c42\u5fae\u5206\uff0c\u6709
\u3000\u3000\u3000\u3000cos(x+z)*(dx+dz) = -sin(y+z)*(dy+dz)\uff0c
\u6574\u7406\u6210
\u3000\u3000\u3000\u3000dz = ----dx+----dy\uff0c
\u4e24\u4e2a\u504f\u5bfc\u6570\u5c31\u51fa\u6765\u4e86\u3002



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