python怎么用递归输出列表中x的个数
1、首先打开JUPYTER NOTEBOOK,新建一个空白的PY文档。2、其次list = [1 , 88, 322, 0, 5] 这里有一个列表、一共有5个元素但是需要用PYTHON计算出来。
3、最后list = [1 , 88, 322, 0, 5] sum = 0 for i in list: sum += 1 print(sum)。
绛旓細1銆侀鍏堟墦寮JUPYTER NOTEBOOK锛屾柊寤轰竴涓┖鐧界殑PY鏂囨。銆2銆佸叾娆ist = [1 锛 88锛 322锛 0锛 5] 杩欓噷鏈変竴涓鍒楄〃銆佷竴鍏辨湁5涓厓绱犱絾鏄渶瑕佺敤PYTHON璁$畻鍑烘潵銆3銆佹渶鍚巐ist = [1 锛 88锛 322锛 0锛 5] sum = 0 for i in list: sum += 1 print(sum)銆
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