根据要求填空：（1）写出下列有机物的键线式： 根据要求填空：（1）写出CH3CH2CH2COOH的键线式：...
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（1）键线式以线表示化学键，线的交点与端点处代表碳原子，C、H原子不必标记出来，并用氢原子数补足四价，官能团中的C原子应标出，杂原子及杂原子上的H原子需标出．故键线式为；CH3CH2CH2COOH键线式为，故答案为：；；
（2）属于烃，线的交点与端点处代表碳原子，并用氢原子数补足四价，结构简式为（CH3）2CHCH（CH3）CH（C2H5）CH（CH3）CH2CH3，
故答案为：（CH3）2CHCH（CH3）CH（C2H5）CH（CH3）CH2CH3；
（3）A在水中溶解度较大，A为极性分子，即正负电荷重心不重合，NH3和Cl在四边形的4个角上的分布是不对称的，故A的几何构型为；B在CCl4中溶解度较大，B为非极性分子，即正负电荷重心重合，NH3和Cl分别对称分布在四边形的4个角上，故B的几何构型为，
答：A的构型为；B的构型为．
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