求化学高手帮忙解答~谢谢~ 《1》、化学求助:请高手帮忙,谢谢大家了~~
\u6c42\u7535\u8111\u9ad8\u624b\u5e2e\u5fd9\u89e3\u7b54\uff01\u8c22\u8c221\u3001\u6253\u5f00\u7535\u8111\u7ba1\u5bb6\uff0c\u70b9\u51fb\u6253\u5f00\u5de5\u5177\u7bb1;
2\u3001\u70b9\u51fb\u6253\u5f00\u7535\u8111\u8bca\u6240;
3\u3001\u627e\u5230\u201c\u56fe\u6807\u663e\u793a\u5f02\u5e38\u201d\u6216\u201c\u5feb\u6377\u65b9\u5f0f\u53d8\u6210\u672a\u77e5\u56fe\u6807\u201d;
4\u3001\u70b9\u51fb\u7acb\u5373\u4fee\u590d;
5\u3001\u7b49\u5f85\u4fee\u590d;
6\u3001\u4fee\u590d\u5b8c\u6210\u540e\uff0c\u8fd4\u56de\u684c\u9762\uff0c\u67e5\u770b\u56fe\u6807\u662f\u5426\u6b63\u5e38\u3002
\uff081\uff09\u767d\u8272\uff0c\u56fa\u4f53\uff0c\u6613\uff0c\u70ed\u91cf
\uff082\uff09\u5438\u6536\uff0c\u6f6e\u89e3\uff0c\u5e72\u71e5\u5242
\uff083\uff09\u8150\u8680\u6027\uff0c\u706b\u78b1\uff0c\u70e7\u78b1\uff0c\u82db\u6027\u94a0
2\u3001\uff081\uff09\u767d\u8272\uff0c\u56fa\u4f53\uff0c\u5fae\uff0c\u77f3\u7070\u77f3
\uff082\uff09\u719f\u77f3\u7070\uff0c\u77f3\u7070\u4e73\uff0c\u751f\u77f3\u7070\u6eb6\u4e8e\u6c34
\u4e8c\u3001\u6c22\u6c27\u6839 \u84dd\u8272\uff0c\u7ea2\u8272
\u76d0\u548c\u6c34 \u5269\u4e0b\u5f88\u7b80\u5355\uff0c\u81ea\u5df1\u5199\u5427
n(NaOH) = n(邻苯二甲酸氢钾)
先计算出0.5225g的邻苯二甲酸氢钾的物质的量(即酸性氢离子的物质的量)n = m|M = 0.5225g | 204.44g|mol
假设氢氧化钠溶液的浓度为c(NaOH),则:
c(NaOH) * 22.50ml = 0.5225g | 204.44g|mol
解出 c(NaOH) = 1.136 * 10^-4 mol|ml
绛旓細姘╁師瀛愮數瀛愭帓甯冿紝2 8 8 涓庡叾鐩稿悓鐨勯槼绂诲瓙鏄鍥涘懆鏈熺殑鍏冪礌褰㈡垚鐨勯槼绂诲瓙锛屽嵆 K Ca K 鏈澶栧眰涓涓數瀛 鏄撳け鐢靛瓙 澶卞幓涓涓數瀛愯揪鍒2 8 8绋冲畾缁撴瀯灏辨槸K+ Ca2+鍚岀悊 涓庡叾鐩稿悓鐨勯槾绂诲瓙鏄涓夊懆鏈熺殑鍏冪礌褰㈡垚鐨勯槾绂诲瓙锛屽嵆 Cl S 浠ュ強閰告牴绂诲瓙HS- Cl 鏈澶栧眰涓冧釜鐢靛瓙 璧㈠緱鐢靛瓙 寰楀埌涓涓數瀛愯揪鍒2 8 ...
绛旓細1銆侊紙1锛塈2鍜孒2O 鑹叉暎鍔涖佽瀵煎姏 锛2锛塈2鍜孋Cl4 鑹叉暎鍔 锛3锛塇Cl鍜孒2O 鑹叉暎鍔涖佸彇鍚戝姏銆佽瀵煎姏 锛4锛塇2O鍜孨H3 鑹叉暎鍔涖佸彇鍚戝姏銆佽瀵煎姏銆佹阿閿 锛5锛塐2鍜孒2O 鑹叉暎鍔涖佽瀵煎姏 2.璇曠敤鍒嗗瓙闂村姏璇存槑涓嬪垪浜嬪疄锛氾紙1锛夊父娓╀笅姘燂紝姘崟璐ㄦ槸姘斾綋锛屾捍鏄恫浣擄紝纰樻槸鍥轰綋锛氬垎瀛愮粨鏋勭浉浼硷紝鐩稿...
绛旓細閭昏嫰浜岀敳閰告阿閽惧睘鏈夋満閰稿紡鐩愶紝鏄敱閭昏嫰浜岀敳閰镐笌灏戦噺鐨勬阿姘у寲閽惧弽搴斿緱鍒帮紙濡傛灉姘㈡哀鍖栭捑杩囬噺鐨勮瘽浼氭妸閭昏嫰浜岀敳閰镐腑鐨勪袱涓阿閮戒腑鍜屾帀鍙樻垚閭昏嫰浜岀敳閰搁捑灏卞睘浜庢湁鏈烘鐩愩傚叾瀹炲彲浠ョ被姣斾簬纰抽吀鍜屾阿姘у寲閽惧弽搴旓紝濡傛灉姘㈡哀鍖栭捑灏戦噺灏卞彧鑳界敓鎴愮⒊閰告阿閽撅紝杩囬噺鍒欑敓鎴愮⒊閰搁捑锛岄偦鑻簩鐢查吀姘㈤捑涔熷彲绫绘瘮涓虹⒊閰告阿閽撅紝鍙...
绛旓細杩3 鐗╄川娣峰悎婧舵恫灏辨槸 SO42- K + 鍜孉l3+ 鐨勬贩鍚堟憾娑 璁 K+鏄 x mol Al3+ 鏄 y mol 璁句綋绉氨鏄1 L锛孨aOH 涔熸槸1L 閭d箞 x +3y ==0.2 *2 鐢佃嵎瀹堟亽 鎭板ソ婧惰В鍒 Al3+ ~~~4OH- 1 4 y 0.2 y==0.05 甯﹀叆x +3y ==0.2 *2 姹傚嚭 x==0.25 鍗矺+ 鏈 0.25 mol 鑰孠OH ...
绛旓細涓 鍒嗘瀽锛氫互KCl銆並2SO4銆乑nCl2鍜1LH2O涓哄師鏂欓厤寰楃浉鍚岀粍鎴愮殑钀ュ吇娑诧紝瑕佽绠楁墍闇KCl銆並2SO4銆乑nCl2鐗╄川鐨勯噺锛屽簲浠庣瀛愮殑鐗╄川鐨勯噺鐨勭浉绛夌殑瑙掑害杩涜璁$畻锛瑙g瓟锛氳В锛0.3molKCl銆0.2molK2SO4銆0.1molZnSO4涓細n锛圞+锛=0.3mol+0.2mol脳2=0.7mol锛沶锛圸n2+锛=0.1mol锛沶锛圕l-锛=0.3mol锛沶...
绛旓細瑙o細鍙80鎽勬皬搴︾閰搁捑楗卞拰婧舵恫269鍏嬮檷娓╁埌60鎽勬皬搴︼紝姹傛瀽鍑虹殑婧惰川璐ㄩ噺銆傦紙娉80鎽勬皬搴︾閰搁捑楗卞拰婧舵恫婧惰В搴︿负169鍏嬶紝60鎽勬皬搴︾閰搁捑楗卞拰婧舵恫婧惰В搴︿负110鍏嬶級80鎽勬皬搴︾閰搁捑楗卞拰婧舵恫269鍏嬶紝璇存槑婧舵恫涓湁100鍏嬫按锛169鍏嬬閰搁捑銆傞檷娓╁埌60鎽勬皬搴,100鍏嬫按涓嶅彉锛屼絾婧惰В搴﹀彉灏忥紝鍙兘婧惰В110鍏嬬閰搁捑锛屾瀽鍑...
绛旓細1銆丯a2CO3鍜孒2SO4鐨勭墿璐ㄧ殑閲忓叧绯绘槸2锛1锛屽弽搴斾负锛2Na2CO3 + H2SO4 == Na2SO4 + 2NaHCO3 绂诲瓙鏂圭▼锛2CO32- + 2H+ == 2HCO3- 鎵浠ユ病鏈塁O2浜х敓 2銆丆a(OH)2 + CO2 == CaCO3鈫 + H2O锛圕O2涓嶈冻锛塁a(OH)2 + 2CO2 == 2CaHCO3鈫擄紙CO2杩囬噺锛...
绛旓細鈶 绛旀B銆傝冨療姘у寲杩樺師椤哄簭瑙勫垯锛 姘у寲鎬ч『搴忕敱寮哄埌寮辩殑椤哄簭 Ag+ Fe3+锛堣杩樺師涓篎e2+锛 Cu2+ 锛團e2+ Zn2+ 浜岃呬笉涓嶧e鍙嶅簲锛堿g+浼樺厛涓嶧e鍙嶅簲锛孉g+瀹屽叏娑堣楀畬锛屽墿涓嬬殑Fe鍐嶄笌Fe3+鍙嶅簲锛屽急Fe杩樻湁鍓╀綑鍐嶄笌Cu2+鍙嶅簲 鈶 绛旀B銆備笁姘寲閾佹憾娑蹭腑鐢变簬Fe3+姘磋В鏄鹃吀鎬э紝褰撳姞鍏ラ晛绮夋椂锛岄晛...
绛旓細A 瑙:2CO+O2=2CO2 2CO2+2Na2O2=2Na2CO3+O2 涓や釜鏂圭▼寮忓悎骞跺緱鍒癈O+Na2O2=Na2CO3 锛堢浉褰撲簬Na2O2鍙惛鏀朵簡CO姘斾綋锛夊悓鐞嗗緱鍒帮細H2+Na2O2=2NaOH 鎵浠O鍜孒2鐕冪儳鍚庨氳繃杩囨哀鍖栭挔鎭板ソ瀹屽叏鍚告敹,澧炲姞鐨勮川閲忓氨鏄疌O鍜孒2鐨勮川閲 鎵浠ュ浐浣撹川閲忓鍔犱负ag銆傚笇鏈涢噰绾充负鏈浣崇瓟妗~璋㈣阿 鍙傝冭祫鏂欙細澶ц剳 鍐欑殑濂界疮 ...
绛旓細2銆乧 3銆乧 4銆佽嵂閲慫nCO3=(楂樻俯)ZnO+CO2鈫 2ZnO+C=(楂樻俯)2Zn+CO2鈫 2Cu2O+C=(楂樻俯)4Cu+CO2鈫 5銆侀摐鍦ㄧ█纭吀涓氬叆姘ф皵鍙互鍙戠敓涓嬪垪鍙嶅簲锛2 Cu + O2 + 2 H2SO4 == 2CuSO4 + 2 H2O