(2009?北塘区二模)如图(甲)所示是某生产流水线上的产品输送及计数装置示意图.其中S为一激光源,R1为 如图甲所示是某生产流水线上的产品输送及计数装置示意图.已知计...

\uff082012?\u6f84\u6d77\u533a\u6a21\u62df\uff09\u5982\u56fe\u7532\u6240\u793a\u662f\u67d0\u751f\u4ea7\u6d41\u6c34\u7ebf\u4e0a\u7684\u4ea7\u54c1\u8f93\u9001\u53ca\u8ba1\u6570\u88c5\u7f6e\u793a\u610f\u56fe\uff0e\u5176\u4e2dS\u4e3a\u4e00\u6fc0\u5149\u6e90\uff0cR1\u4e3a\u5149\u654f

\uff081\uff09\u7531\u7532\u56fe\u53ef\u77e5\uff1aR1\u3001R2\u4e32\u8054\uff0c\u7531\u5149\u654f\u7535\u963b\u65e0\u5149\u7167\u5c04\u65f6\u963b\u503c\u8f83\u5927\u53ef\u77e5\uff0c\u5f53\u5149\u88ab\u4ea7\u54c1\u6321\u4f4f\u65f6\uff0cR1\u7684\u963b\u503c\u53d8\u5927\uff0c\u7535\u8def\u7684\u603b\u7535\u963b\u53d8\u5927\uff1b\u6839\u636eI=UR\u53ef\u77e5\uff0c\u7535\u8def\u4e2d\u7684\u7535\u6d41\u53d8\u5c0f\uff1b\u6839\u636eU=IR\u53ef\u77e5\uff0cR2\u4e24\u7aef\u7684\u7535\u538b\u53d8\u5c0f\uff1b\u6839\u636e\u4e32\u8054\u7535\u8def\u603b\u7535\u538b\u7b49\u4e8e\u5404\u5206\u7535\u538b\u4e4b\u548c\u53ef\u77e5\uff0cR1\u4e24\u7aef\u7684\u7535\u538b\u53d8\u5927\uff0c\u5373R1\u4e24\u7aef\u7684\u7535\u538b\u8f83\u9ad8\uff0e\uff082\uff09\u4ea7\u54c1\u5bf9\u4f20\u9001\u5e26\u7684\u538b\u529b\uff1aF=mg=0.6kg\u00d710N/kg=6N\uff0c\u53d7\u529b\u9762\u79ef\uff1as=L2=\uff080.1m\uff092=0.01m2\uff0c\u4ea7\u54c1\u5bf9\u4f20\u9001\u5e26\u7684\u538b\u5f3a\uff1ap=Fs=6N0.01m2=600Pa\uff0e\uff083\uff09\u7531\u56fe\u4e59\u53ef\u77e5\uff0c\u4e00\u4e2a\u4ea7\u54c1\u7ecf\u8fc7\u6fc0\u5149\u7684\u65f6\u95f4\u662f0.2s\uff0c\u4e00\u4e2a\u4ea7\u54c1\u7ecf\u8fc7\u6fc0\u5149\u7684\u901f\u5ea6\uff1av=st=0.1m0.2s=0.5m/s\uff0c\u2235\u6c34\u5e73\u4f20\u9001\u5e26\u5300\u901f\u524d\u8fdb\uff0c\u2234\u4f20\u52a8\u5e26\u7684\u8fd0\u52a8\u901f\u5ea6\u4e3a0.5m/s\uff0e\uff084\uff09\u7531\uff081\uff09\u548c\u56fe\u4e59\u53ef\u77e5\uff0c\u65e0\u5149\u7167\u65f6U1=4V\uff0c\u5219U2=U-U1=6V-4V=2V\uff0c\u7535\u8def\u4e2d\u7684\u7535\u6d41\uff1aI=U2R2=2V40\u03a9=0.05A\uff0c\u5149\u654f\u7535\u963b\u7684\u963b\u503c\uff1aR1=U1I=4V0.05A=80\u03a9\uff0e\u7b54\uff1a\uff081\uff09\u5149\u88ab\u4ea7\u54c1\u6321\u4f4f\u65f6\uff0cR1\u4e24\u7aef\u7684\u7535\u538b\u8f83\u9ad8\uff1b\uff082\uff09\u4ea7\u54c1\u5bf9\u4f20\u9001\u5e26\u7684\u538b\u5f3a\u4e3a600Pa\uff1b\uff083\uff09\u4f20\u52a8\u5e26\u7684\u8fd0\u52a8\u901f\u5ea6\u662f0.5m/s\uff1b\uff084\uff09\u65e0\u5149\u7167\u5c04\u65f6\u5149\u654f\u7535\u963b\u7684\u963b\u503c\u4e3a80\u03a9\uff0e

\uff081\uff09\u7531\u56fe\u4e59\u6240\u793a\u56fe\u8c61\u53ef\u77e5\uff0c\u4ea7\u54c1\u6321\u5149\u65f6\u95f4\uff1at=0.6s-0.4s=0.2s\uff0c\u6b63\u65b9\u5f62\u4ea7\u54c1\u968f\u4f20\u9001\u5e26\u8fd0\u52a8\u7684\u901f\u5ea6\uff1av=st=0.1m0.2s=0.5m/s\uff1b\uff082\uff09\u7531\u56fe\u8c61\u53ef\u77e5\uff0c\u6709\u5149\u7167\u5c04\u65f6\uff0c\u5149\u654f\u7535\u963b\u4e24\u7aef\u7535\u538bU1=2V\uff0c\u6b64\u65f6R2\u4e24\u7aef\u7535\u538bU2=U-U1=6V-2V=4V\uff0c\u7535\u8def\u7535\u6d41I=I2=U2R2=4V20\u03a9=0.2A\uff0c\u2235I=UR\uff0c\u2234\u6b64\u65f6\u5149\u654f\u7535\u963b\u963b\u503c\uff1aR1=U1I=2V0.2A=10\u03a9\uff1b\uff083\uff09\u6709\u5149\u7167\u5c04\u65f6\uff0c\u7535\u8def\u7535\u6d41\uff1aI=0.2A\uff0c\u6ca1\u6709\u5149\u7167\u5c04\u65f6\uff0c\u7535\u8def\u7535\u6d41I\u2032=U2\u2032R2=U?U1R2=6V?4V20\u03a9=0.1A\uff0c\u7531\u56fe\u4e59\u6240\u793a\u56fe\u8c61\u53ef\u77e5\uff0c\u4e00\u4e2a\u5468\u671f\u5185\uff0c\u6709\u5149\u7167\u5c04\u7684\u65f6\u95f4\u4e3a0.4s\uff0c\u65e0\u5149\u7167\u5c04\u7684\u65f6\u95f4\u662f0.2s\uff0c\u4e00\u4e2a\u5468\u671f0.6s\u5185\uff0c\u7535\u8def\u6d88\u8017\u7684\u7535\u80fd\uff1aW=UIt+UI\u2032t\u2032=6V\u00d70.2A\u00d70.4s+6V\u00d70.1A\u00d70.2s=0.6J\uff0c1h\u6d88\u8017\u7684\u7535\u80fdW\u603b=0.6J\u00d73600s0.6s=3600J\uff1b\u7b54\uff1a\uff081\uff09\u6b63\u65b9\u5f62\u4ea7\u54c1\u968f\u4f20\u9001\u5e26\u8fd0\u52a8\u7684\u901f\u5ea6\u662f0.5m/s\uff1b\uff082\uff09\u5149\u654f\u7535\u963b\u5728\u6709\u5149\u7167\u72b6\u6001\u4e0b\u7684\u7535\u963b\u662f10\u03a9\uff1b\uff083\uff09\u6574\u4e2a\u7535\u8def\u5de5\u4f5c1h\u6d88\u8017\u7684\u7535\u80fd\u662f3600J\uff0e

(1)因R1与R2串联,所以有光照射时(没有产品从传送带上通过S与R1之间),光敏电阻R1的阻值较小,结合乙图可知分压较小为2V.
(2)由题意结合乙图可知,当光敏电阻在无光照射时,光敏电阻两端的电压U1=4V,
所以R2两端的电压为U2=U-U1=6V-4V=2V;
电路中的电流I=
U2
R2
=
2V
40Ω
=0.05A,
光敏电阻的阻值R=
U1
I
=
4V
0.05A
=80Ω.
故答案为:(1)2;(2)80.

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