这里为什么直接等于1/2×π/2 为什么是π/4×2=π/2
\u9ad8\u4e00\u6570\u5b66\uff0c\u4f8b2\u4e3a\u4ec0\u4e48\u662f10\u00d71/2\u03c0 \uff0b\u03c0/5\uff1f\u76f4\u63a52\u03c0+2\u03c0+\u03c0\uff0b\u03c0/5\u7b49\u4e8e\u03c0\uff0b\u03c0/5\u4e0d\u5c31\u884c\u4e86\uff1f\u4e24\u79cd\u65b9\u6cd5\u90fd\u5bf9,\u4f46\u4f60\u7684\u4e0d\u662f\u6700\u7ec8\u7b54\u6848\u3002
\u4f8b3.
\u5230 pi/2, F(x) \u5df2\u7ecf\u5b8c\u6210\u4e86\u5bf9 f(x) \u7684\u5168\u90e8\u79ef\u5206. \u6240\u4ee5, F(pi/2) = 1.
\u4f8b6.
F(\u6b63\u65e0\u7a77)=1--> (1/2)(1+karctang(\u6b63\u65e0\u7a77)) = (1/2)(1+k(pi/2) = 1 --> k=2/(pi).
\u4f8b7.
\u4e00\u822c\u5730 F(x) \u662f\u975e\u51cf\u51fd\u6570.\u5728x=1\u65f6, kx^2\u4e0d\u80fd\u5927\u4e8e1. \u5373: kx^2 = k(1)^2 =< 1
\u6240\u4ee5, k=1\u662f\u4e00\u89e3,\u4f46\u4e0d\u662f\u552f\u4e00\u89e3.\u4f46\u662f,\u6b64\u9898\u6709\u9644\u52a0\u6761\u4ef6: X \u662f\u8fde\u7eed\u53d8\u91cf. F(x) \u4e5f\u5c31\u53ea\u80fd\u8fde\u7eed\u4e86. \u5f97: k=1.
积出来1/2（t一1/2sin2t）代入上下限
就得出1/2X丌/2
华里士公式，也叫点火公式
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