设4个int型变量a1,a2,a3,a4的初值均已设置为0，以下选项中正确的赋值语句是（ ）。A：a1=15%2.5; B:a2=038 已知a1，a2，a3，a4是四维非0列向量， 记A=（a1，...
\u8bbe4\u7ea7LFSR\u7684\u53cd\u9988\u51fd\u6570f(a1\uff0ca2\uff0ca3\uff0ca4)=a1 a4\uff0c\u5f53\u8f93\u5165\u7684\u521d\u59cb\u72b6\u6001\u4e3a(a1\uff0ca2\uff0ca3\uff0ca4)=(1001)\u65f6\uff0c\u7ed9\u51fa\u8f93\u51faLOG2\u3014f\uff08a1\uff09\u7684\uff08a2\uff09\u7684.. \uff08a10\u7684\uff09]
= LOG2\u3014f\uff08a1\uff09\u7684+ log2f\uff08a2\uff09\u7684+\u3002 log2f\uff08a10\u7684\uff09
= LOG2\uff082 ^ a1\uff09\u7684+ LOG2 *\uff082 ^ a2\uff09\u7684+ ... LOG2\uff082 ^ a10\u7684\uff09
=\u03b11+\u03b12+ ... A10
\u7b49\u5dee\u6570\u5217{an}\u7684\u516c\u5dee\u4e3a2;
A2-2 = A1
A4-2 = A3;
.. /> a10\u7684-2 = A9;
A2 + A4 + A6 + A8 + A10-10 = A 1 + A + a5\u7684+ A7 + A9;
A1 + A2 + A3 + ... A10 = 2\uff08A2 + A4 + A6 + A8 + A10\uff09-10;
\uff08A2 + A4 + A6 + A8 + A10\uff09= 4
A2 + A4 + A6 + A8 + A10 = 2 /> LOG2\u3014f\uff08a1\uff09\u7684\uff08a2\uff09\u7684\uff08\uff09A3 ...... F\uff08A10\uff09]\u503c= 2 * 2-10 = -6
D\u3001a2\uff0ca3\uff0ca4\u3002
\u5177\u4f53\u8fc7\u7a0b\u5982\u56fe\uff1a
\u4e00\u822c\u7ed3\u8bba\u662fA\uff0c\u4f46B\u4e2d\u5411\u91cf\u4e5f\u662fa1\uff0ca2\uff0ca3\u7684\u4e00\u4e2a\u7b49\u4ef7\u5411\u91cf\u7ec4\u3002
\u6269\u5c55\u8d44\u6599\uff1a
\u4e3b\u5bf9\u89d2\u5143\u7d20\u662f\u5c06\u539f\u77e9\u9635\u8be5\u5143\u7d20\u6240\u5728\u884c\u5217\u53bb\u6389\u518d\u6c42\u884c\u5217\u5f0f\uff0c\u975e\u4e3b\u5bf9\u89d2\u5143\u7d20\u662f\u539f\u77e9\u9635\u8be5\u5143\u7d20\u7684\u5171\u8f6d\u4f4d\u7f6e\u7684\u5143\u7d20\u53bb\u6389\u6240\u5728\u884c\u5217\u6c42\u884c\u5217\u5f0f\u3002
\u5f53\u77e9\u9635\u7684\u9636\u6570\u7b49\u4e8e\u4e00\u9636\u65f6\uff0c\u4f34\u968f\u77e9\u9635\u4e3a\u4e00\u9636\u5355\u4f4d\u65b9\u9635\u3002\u4e8c\u9636\u77e9\u9635\u7684\u6c42\u6cd5\u53e3\u8bc0\uff1a\u4e3b\u5bf9\u89d2\u7ebf\u5143\u7d20\u4e92\u6362\uff0c\u526f\u5bf9\u89d2\u7ebf\u5143\u7d20\u53d8\u53f7\u3002
A:%运算要求运算符两边均为整数
B:以0开头的是八进制，八进制由0-7数字组成，因为不能出现8
C：赋值运算符从右到左进行运算，首先计算a1+a2=39，只能给变量赋值，而不能给表达式赋值，而a1+a2是一个表达式
D：0x开头的是16进制数，由0-7,a-f组成，故合法~~~
D是对的
a1=15%2.5; // %右边必须是整形
a2=038; // 以起始0是8进制，8进制每位最大是7
a3=a1+a2=39; // =是赋值，=左边必须是变量
a4=0xa2; // 0x指16进制，0xa2=162，正确
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