计算R2的电流
\u7528\u6234\u7ef4\u5b81\u5b9a\u7406\u8ba1\u7b97\u56fe\u4e2dR2\u4e2d\u7684\u7535\u6d41\u5c06R2\u65ad\u5f00\uff0c\u6709\uff1a
\u5f00\u8def\u7535\u538bUoc\uff1d10\uff0d10x4\uff1d\uff0d30V\uff0c
\u7b49\u6548\u7535\u963bReq\uff1d4\u6b27\uff0c
\u6545R2\u7684\u7535\u6d41I2\uff1d\uff0d30/(4\uff0b1)\uff1d\uff0d6A\u3002
\uff081\uff09\u8fd0\u653eA1\u548cR1\u3001R3\u3001R4\u6784\u6210\u5355\u7aef\u8f93\u5165\u7684\u53cd\u76f8\u653e\u5927\u7535\u8def\uff0c\u8fd0\u653eA2\u548cR6\u3001R7\u6784\u6210\u5355\u7aef\u8f93\u5165\u7684\u540c\u76f8\u653e\u5927\u7535\u8def\u3002R2\u548cR5\u4e0d\u8d77\u4f5c\u7528\u3002
\uff082\uff09Uo=Uo1\u00d7\uff08R6+R7\uff09/R6\uff0cUo1=-Ui\u00d7R3/R1\uff0c\u628aUo1\u7684\u8868\u8fbe\u5f0f\u4ee3\u5165\u540e\uff0c\u5f97
Uo==-Ui\u00d7R3/R1\u00d7\uff08R6+R7\uff09/R6=-Ui\u00d7R3\uff08R6+R7\uff09/R1R6
\u603b\u589e\u76caAuf=-R3\uff08R6+R7\uff09/R1R6
2、20A电流源作用；I2″=20÷﹙5+5+10//10﹚×5÷2=3.33A
叠加后，R2电阻上的电流I2=I2′+I2″=1+3.33=4.33A
图中数据有错吧
绛旓細锛1锛鐢甸樆R2涓殑鐢垫祦I= U2 R2 =1A 锛2锛夊鐢甸樆R=R2+ R1R3 R1+R3 =15惟 鎵浠ヨ矾绔數鍘嬩负锛歎=RI=15脳1=15V 锛3锛夋牴鎹棴鍚堢數璺濮嗗畾寰婭= E R+r 寰 E=I锛圧+r锛変唬鍏ユ暟鎹В寰桬=20V 锛4锛塖1闂悎鑰孲2鏂紑锛岀數璺腑鐨勬荤數娴 I鈥= E R1+R2+r = 20 20+5 A=0.8A 鐢靛帇琛ㄧず鏁癠鈥=...
绛旓細瑙ｇ瓟锛氾紙1锛夊綋寮鍏冲叏闂悎鏃讹紝R1琚煭璺紝R2鍜孯3骞惰仈鍦ㄧ數璺袱绔紝鍒欑敱娆у瀹氬緥鍙緱锛氱數婧愮數鍘婾=IR3=0.6A脳30惟=18V R2涓ょ鐨勭數娴両2=U/R2=18/20A=0.9A 锛2锛夊綋寮鍏冲叏鏂紑鏃讹紝R1涓嶳3涓茶繛鎺ュ叆鐢佃矾锛屽垯鐢佃矾涓殑鐢垫祦锛欼=U/(R1+R3)=18/(6+30)=0.5A t=1min=60s锛涘垯1鍒嗛挓鍐匯1涓婁骇鐢熺殑鐑噺...
绛旓細R3涓ょ鐢靛帇涓猴細U3锛3锛0.004x250锛4V锛屾晠R3鐨勭數娴佷负I3锛4/400锛10mA 鏁呮湁锛歎3锛18锛嶏紙0.004锛0.01锛塕2 瑙ｅ緱锛R2锛1000娆銆
绛旓細鎵浠ラ氳繃R2鐨勭數娴佹槸 I=6浼忕壒/锛2+2锛夊崈娆=1.5姣畨銆
绛旓細R2鈭3鐨勭數鍘嬩负锛歎=I1'脳锛圧2鈭3锛=4脳锛2鈭2锛=4锛圴锛夈傛墍浠ワ細I2'=I3'=U/R2=4/2=2锛圓锛夈2銆乁s2鍗曠嫭浣滅敤鏃讹紝Us1鐭矾銆傛樉鐒鐢垫祦瑕佷粠Us2鐨勬鏋佹祦鍑猴紝鍥犳I2"瀹為檯鐢垫祦鏂瑰悜涓哄悜涓婄殑銆傚悓鏍稩1"瀹為檯鏂瑰悜涔熸槸鍚戜笅鐨勩傚鐢佃矾鐢甸樆涓猴細R=R2+R1鈭3=2+2鈭2=3锛埼╋級銆侷2"=-Us2/R=-...
绛旓細1銆30V鐢垫簮浣滅敤锛汭2鈥=30梅锕10+锕5+5锕//10锕溍2=1A 2銆20A鐢垫祦婧愪綔鐢紱I2鈥=20梅锕5+5+10//10锕毭5梅2=3.33A 鍙犲姞鍚庯紝R2鐢甸樆涓鐨勭數娴I2=I2鈥+I2鈥=1+3.33=4.33A
绛旓細绗竴姝ワ細R2涓嶳4涓茶仈 绛夋晥鐢甸樆R24=R2+R4=35惟 绗簩姝ワ細R24涓嶳3骞惰仈 绛夋晥鐢甸樆R234=锛圧24脳R3锛壝凤紙R24+R3锛=140/11惟 绗笁姝ワ細R234涓嶳1涓茶仈 绛夋晥鐢甸樆R1234=R234+R1=305/11惟 绗洓姝ワ細R1234涓嶳5骞惰仈 绛夋晥鐢甸樆R12345=锛圧1234脳R5锛壝凤紙R1234+R5锛=61/127惟 娴佽繃R5鐨勭數娴 ...
绛旓細3) R2骞禦3=8k骞2k=8x2/(8+2)=1.6k锛孷a=5x1.6k/(1k+1.6k)=3.08v銆R2鐢垫祦=Va/R2=0.38mA 5) 鐐1=3.3v锛岀偣2,3=3.3v锛岀偣4=0v銆傘
绛旓細璁惧乏銆佷腑銆佸彸璺殑鐢垫祦澶у皬鍒嗗埆涓篒1銆両2銆両3锛屾柟鍚戦兘鏄敱涓婂線涓嬨傚熀灏旈湇澶畾寰嬶細I1+I2+I3=0 锛圧1+R2锛塈1+E1-R3I2=0 R4I3+E2-R3I2=0 瑙ｅ緱锛欼1=-1A锛孖2=1A锛孖3=0A 娴佽繃R2鐨勭數娴涓1A鏂瑰悜浠庡乏鍒板彸锛屾祦杩嘡3鐨勭數娴佷负1A鏂瑰悜浠庝笂鍒颁笅 ...
绛旓細瑙ｏ細灏R2=6惟浠庣數璺腑鏂紑銆侷1=E/锛圧1+R3锛=12/锛20+20锛=0.3锛圓锛夈傛墍浠ワ細Uam=-I1R1+E=-0.3脳20+12=6锛圴锛夈傛垨鑰匲am=I1脳R2=0.3脳20=6V銆俇mb=Is脳锛圧4+R5锛=2脳锛10+30锛=80锛圴锛夈傛墍浠ワ細Uoc=Uab=Uam+Umb=6+80=86锛圴锛夈傚皢鐢靛帇婧愮煭璺鐢垫祦婧愬紑璺紝寰楀埌锛歊eq=Rab=...
