一台电动机的额定功率是10KV额定电流是109A额定功率因数是0.85求额定功率和计算公式 电压10kV电机功率是1400kW的额定电流怎样计算。
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\u7b54\u6848\u662f85.09A\u3002\u4ee5\u4e0b\u662f\u8ba1\u7b97\u65b9\u5f0f\uff1aI\uff1dP\uff0fUe\uff0f\u221a3\uff0fcos\u03c6\uff0f\u03b7I\u2192\u7535\u52a8\u673a\u989d\u5b9a\u7535\u6d41\uff1bP\u2192\u7535\u52a8\u673a\u989d\u5b9a\u529f\u7387\uff1bUe\u2192\u7535\u52a8\u673a\u989d\u5b9a\u7535\u538b\uff1b\u221a3\u2192\u7ea6\u7b49\u4e8e1.732\uff1bcos\u03c6\u2192\u7535\u52a8\u673a\u529f\u7387\u56e0\u6570\uff0c\u7ea6\u7b49\u4e8e0.8-0.9;\u03b7\u2192\u7535\u52a8\u673a\u6548\u7387\uff0c\u7ea6\u7b49\u4e8e0.9\uff1b\u6839\u636e\u516c\u5f0f\u6c42\u6240\u6307\u7535\u52a8\u673a\u7684\u989d\u5b9a\u7535\u6d41\uff1a14000000\uff08W\uff09\uff0f10000\uff08V\uff09\uff0f1.732\uff0f0.85\uff0f0.9\u224885.09(A)
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2\u3001\u4f20\u7edf\u7684\u4fdd\u62a4\u88c5\u7f6e\u4fdd\u62a4\u6548\u679c\u4e0d\u751a\u7406\u60f3\uff1a\u4f20\u7edf\u7684\u7535\u673a\u4fdd\u62a4\u88c5\u7f6e\u4ee5\u70ed\u7ee7\u7535\u5668\u4e3a\u4e3b\uff0c\u4f46\u70ed\u7ee7\u7535\u5668\u7075\u654f\u5ea6\u4f4e\u3001\u8bef\u5dee\u5927\u3001\u7a33\u5b9a\u6027\u5dee\uff0c\u4fdd\u62a4\u4e0d\u53ef\u9760\u3002\u4e8b\u5b9e\u4e5f\u662f\u8fd9\u6837\uff0c\u5c3d\u7ba1\u8bb8\u591a\u8bbe\u5907\u5b89\u88c5\u4e86\u70ed\u7ee7\u7535\u5668\uff0c\u4f46\u7535\u673a\u635f\u574f\u800c\u5f71\u54cd\u6b63\u5e38\u751f\u4ea7\u7684\u73b0\u8c61\u4ecd\u666e\u904d\u5b58\u5728\u3002
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P=1.732*10*109*0.85=1604.698KW
算这问题之前，得先弄清楚，什么是额定功率？额定电压与额定电流的乘积就是电器的额定功率，是用电设备的有功功率，那么很显然额定电流是怎么定义的了。所以这里计算额定功率和功率因数无关。三相电机的额定功率=√3*U*I=1.732*10*109=1887.88KW
是额定电压10KV吧？
P=√3Ucosφ=1.732*10*109*0.85=1605KW
绛旓細涓鍙扮數鍔ㄦ満鐨勯瀹氱數鍘嬫槸10KV锛岄瀹氱數娴佹槸109A锛屽姛鐜囧洜鏁版槸0.85锛棰濆畾鍔熺巼锛歅=1.732*10*109*0.85=1604.698KW
绛旓細鐢靛帇10kV鐢垫満鍔熺巼鏄1400kW鐨勯瀹氱數娴佹槸85.09A銆傝绠楀涓嬶細鍥犱负P=鈭3脳U脳I脳COS蠁锛屾墍浠=P梅锕欌垰3脳U脳COS蠁锕氬叾涓紝I鈫掔數鍔ㄦ満棰濆畾鐢垫祦锛汸鈫掔數鍔ㄦ満棰濆畾鍔熺巼銆傛牴鎹叕寮忔眰鎵鎸囩數鍔ㄦ満鐨勯瀹氱數娴侊細14000000锛圵锛夛紡10000锛圴锛夛紡1.732锛0.85锛0.9鈮85.09(A)...
绛旓細1500kw梅10kv梅0.8=187.5(瀹)
绛旓細1.纭畾璁＄畻鍔熺巼Px锛24灏忔椂杩愯鍔犵郴鏁1.3锛孭x=1.3P=13KW銆2纭畾鐨甫鍨嬪彿锛欱鍨嬪甫锛屼緷鎹浆閫1450R/MIN锛屽姛鐜囩‘瀹氥3纭畾灏忓甫杞洿寰勶細140銆備緷鎹瓸鍨嬪甫鏈灏忕洿寰勮冭檻锛4纭畾澶ц疆鐩村緞锛汥2=D1锛圢1/N2锛*畏=140*锛1450/400锛*0.98=497锛屽洯鏁达細500銆備互涓嬭繕鏈夋牎甯﹂燂紝璁＄畻鑳跺甫闀垮害锛歀=2a+蟺/2锛圖1...
绛旓細10kv鐢垫満宸ヤ綔1灏忔椂鑰楃數閲忔槸10000W锛岀┖杞戒笉鑰楄垂鐢甸噺 W=Pt=鈭3UIcos蠁畏tU 棰濆畾鐢靛帇I锛屽疄闄呰繍琛岀數娴乧os蠁锛鐢垫満鐨勫姛鐜鍥犳暟 锛屛 鐢靛姩鏈虹殑鏁堢巼锛宼 杩愯鏃堕棿銆傜粨鏋滄槸鏈夊姛鐢佃,鍥犱负瀹為檯杩愯鏃剁數鏈哄線寰杈句笉鍒版渶楂樻晥鐜,鎵浠ュ疄闄呮秷鑰楀簲绋嶅ぇ涓浜.
绛旓細鐢垫満鑲畾娌℃湁杈惧埌棰濆畾鍔熺巼锛屼綘鏄庝箞鐭ラ亾杩愯鍔熺巼320KW鐨勶紵鏄惁灏鏄10,42x18.2x1.732=320KW?鐢垫満鐨杈撳叆鍔熺巼杩樺簲涔樹笂鍔熺巼鍥犵礌锛歅=鈭3 x U X I X cos蠁=1.732x10.42x18.2x0.85=279KW锛岃繖杩樺彧鏄數鏈虹殑杈撳叆鍔熺巼锛岃緭鍑哄姛鐜囪繕搴斾箻涓婃晥鐜囷紝P(杈撳嚭)=P锛堣緭鍏ワ級x 畏 =279 x 0.9=251KW锛涚...
绛旓細P(鐢垫満鍔熺巼)=1.732脳U锕欓瀹氱數鍘嬶箽脳I锕欓瀹氱數娴侊箽脳Cos蠁锕欏姛鐜囧洜鏁帮箽脳畏锕欐晥鐜囷箽鐢垫満鍔熺巼鏄鎸囧湪棰濆畾鐢靛帇锛岄瀹氶鐜囦笅婊¤浇杩愯鏃剁數鏈鸿酱涓婅緭鍑虹殑鏈烘鍔熺巼锛屽嵆棰濆畾鍔熺巼銆
绛旓細鐢靛姏绯荤粺鍚勫厓浠剁殑棰濆畾鐢靛帇鐨勭‘瀹氭柟娉曪細鐢靛姩鏈虹殑棰濆畾鐢靛帇鍙栧喅浜鍔熺巼锛屽ぇ鍔熺巼鐨勭敤楂樺帇6KV,10KV銆傚皬鍔熺巼鐨勭敤浣庡帇380V銆傚彂鐢垫満鐨勯瀹氱數鍘嬩篃鍙栧喅浜庡姛鐜囷紝澶ф満缁勯噰鐢ㄩ珮鐢靛帇銆傜數缃戠殑棰濆畾鐢靛帇鍙栧喅浜庤緭閫佽窛绂诲拰鍔熺巼锛岀洰鍓嶄富骞茬綉缁滀负220KV鍜500KV銆
绛旓細瀵逛簬10kV楂樺帇鐢靛姩鏈虹殑鏃犲姛琛ュ伩锛岄氬父閲囩敤鐢靛琛ュ伩鐨勬柟娉曘傚熀鏈師鐞嗘槸灏嗙數瀹瑰櫒骞惰仈鍦ㄧ數鍔ㄦ満鍓嶇锛岄氳繃鐢靛鍣ㄧ殑瀹规姉鏉ヨˉ鍋跨數鍔ㄦ満鐨勬棤鍔熷姛鐜囷紝鎻愰珮鍔熺巼鍥犳暟銆傚叿浣撶殑鎿嶄綔姝ラ濡備笅锛氱‘瀹氶渶瑕佽ˉ鍋跨殑瀹归噺銆傛牴鎹鐢靛姩鏈虹殑棰濆畾鍔熺巼銆侀瀹氱數鍘嬪拰棰濆畾鐢垫祦锛屽彲浠ヨ绠楀嚭鐢靛姩鏈虹殑棰濆畾瑙嗗湪鍔熺巼鍜岄瀹氭棤鍔熷姛鐜囥傝ˉ鍋垮閲忓簲涓洪瀹...
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