求3个数的平均值用c语言编程 3个数的平均值用c语言编程是什么?

\u7528C\u8bed\u8a00\u8bbe\u8ba1\u4e00\u4e2a\u6c42\u4e09\u4e2a\u6570\u5e73\u5747\u503c\u7684\u7a0b\u5e8f

#include
int main()
{
int a,b,c,average;
printf("a=");
scanf("%d",&a);
printf("b=");
scanf("%d",&b);
printf("c=");
scanf("%d",&c);
average=(a+b+c)/3;
printf("a,b,c3\u4e2a\u6570\u5b57\u7684\u5e73\u5747\u503c\uff1a%d",average);
}

#include <stdio.h>
int main()
{
int a,b,c,average;
printf("a=");
scanf("%d",&a);
printf("b=");
scanf("%d",&b);
printf("c=");
scanf("%d",&c);
average=(a+b+c)/3;
printf("a,b,c3个数字的平均值:%d",average);
}

看你应该是初学者 ,我就写了一个不能再简单的程序

//求3个数的平均值用c语言编程
#include<stdio.h>
void main()
{
float x=0,y=0,z=0,j=0;
printf("请输入数字x的值 ");
scanf("%f",&x);
printf("请输入数字y的值 ");
scanf("%f",&y);
printf("请输入数字z的值 ");
scanf("%f",&z);
j=(x+y+z)/3;
printf("%f\n",j);
}

#include <stdio.h>

int main()

{

int a,b,c,average;

printf("a=");

scanf("%d",&a);

printf("b=");

scanf("%d",&b);

printf("c=");

scanf("%d",&c);

average=(a+b+c)/3;

printf("a,b,c3个数字的平均值:%d",average);

}



include "stdio.h"

void main()
{
int i, j,k;
double aver;
scanf("%d%d%d",&i,&j,&k);
aver=(i+j+k)/3

printf("%f",aver);

}

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