2X的平方-5X-3怎么因式分解
2x^2-5x-3=2x^2-6x+x-3
=2x(x-3)+(x-3)
=(x-3)(2x+1)
绛旓細2x²-5x-3=(2x+1)(x-3)2x 1 1x -3
绛旓細鍘熷紡=锛X-3)(2X+1锛
绛旓細鍗佸瓧鐩镐箻娉曪紝寰楋紙x-3锛(2x+1)
绛旓細2x" - 5x - 3 = 2x鈥 - x + 6x - 3 = x( 2x - 1 ) + 3( 2x - 1 )= ( x + 3 )( 2x - 1 )鎴栬 = 2x鈥 + 6x - x - 3 = 2x( x + 3 ) - ( x + 3 )= ( x + 3 )( 2x - 1 )
绛旓細2 1 1 -3 2x²-5x-3=(2x+1)(x-3),11,锛圶-3锛夛紙2X+3锛,2,(2x+1)(x-3),1,1 -3 脳 2 1 2脳锛-3锛+1脳1=-5 鈭村垎瑙鍥犲紡鐨勭粨鏋滀负锛2x²-5x-3=锛坸-3锛夛紙2x+1锛,1,鍗佸瓧鐩镐箻娉曞垎瑙ｅ洜寮 2x²-5x-3 ...
绛旓細绛旀涓(2x+1)(x-3)
绛旓細2x鐨勫钩鏂-5x-3鐢ㄥ崄瀛楃浉涔樻硶鍥犲紡鍒嗚В 瑙ｏ細2 1 脳 1 -3 鎵浠 鍘熷紡=(2x+1)(x-3)
绛旓細鍙互鐢ㄥ崄瀛楃浉涔樻硶鍒嗚В鍥犲紡銆傝В:2x²鈥5x鈥3=0 (2x+1)(x鈥3)=0 2x+1=0鎴杧鈥3=0锛岀敱2x+1=0 寰 x=鈥1/2锛岀敱x鈥3=0 寰 x=3锛屾墍浠ワ紝鍘熸柟绋嬬殑瑙ｆ槸 x=鈥1/2鍜寈=3銆
绛旓細棰樼洰搴旇鏄2x²-5x-3鍚 鍒嗚В涓猴紙2x+1锛夛紙x-3锛
绛旓細2x²-5x-3=0 寰椼2x+1銆戙恱-3銆=0 x=-1/2鎴3 婊℃剰璇烽噰绾崇瓟妗堚濄
