编辑程序实现,将1~100存放在数组中,并求100之内的素数并输出,C语言? 编写一段程序,程序要实现如下功能:把1到100之内的所有素数...

\u7528c\u8bed\u8a00\u7f16\u5199\u7a0b\u5e8f\u8f93\u51fa1-100\u5185\u7684\u7d20\u6570

\u7528\u5e38\u89c4\u7684\u5224\u7d20\u6027\u65b9\u6cd5\u53ef\u5982\u4e0b\u5b9e\u73b0
#include "stdio.h"
#include "math.h"
bool IsPrime(int x)
{
int i, s;
s = sqrt(x + 1);
for(i = 2; i <= s; i++)
if(x % i == 0) return false;
return true;
}
void main( )
{
int i;
for(i = 2; i < 100; i++)
if(IsPrime(i))
printf("%d ", i);
}
\u4e5f\u53ef\u91c7\u7528\u7b5b\u9009\u6cd5\uff0c\u7b5b\u9009\u6cd5\u6548\u7387\u4f1a\u9ad8\u4e00\u4e9b\uff0c\u697c\u4e0a\u7684\u867d\u7136\u4e5f\u662f\u7b5b\u9009\u6cd5\uff0c\u4f46\u4ed6\u7684\u6548\u7387\u5374\u5e76\u4e0d\u9ad8\u3002\u7b5b\u9009\u6cd5\u7684\u601d\u8def\u662f\u5c06\u90a3\u4e9b\u975e\u7d20\u6570\u7b5b\u6389\uff0c\u7559\u4e0b\u90a3\u4e9b\u7d20\u6570\u3002\u547d\u9898\u201c\u5bf9\u4e8e1<x<100\u7684\u5408\u6570x, \u5fc5\u542b\u6709\u5c0f\u4e8e10\u7684\u8d28\u56e0\u5b50\u201d\u53ef\u4ee5\u8bc1\u660e\u662f\u771f\u547d\u9898\uff0c\u5b83\u7684\u9006\u53cd\u547d\u9898\u201c\u5bf9\u4e8e1<x<100\u7684\u6570\uff0c\u5982\u679c\u4e0d\u542b\u6709\u5c0f\u4e8e10\u7684\u8d28\u56e0\u5b50\uff0c\u5219\u5b83\u5fc5\u4e3a\u7d20\u6570\u3002\u201d\u5219\u4e5f\u662f\u771f\u547d\u9898\u3002\u56e0\u6b64\u7b5b\u9664\u65f6\uff0c\u53ea\u8981\u7b5b\u9664\u542b\u670910\u4ee5\u5185\u7684\u8d28\u56e0\u5b50\u7684\u6570\u5c31\u53ef\u4ee5\u4e86\u3002\u4e0b\u9762\u7ed9\u51fa\u7b5b\u9009\u6cd5\u7684\u4ee3\u7801\u3002
#include "stdio.h"
void main( )
{
bool isprime[100];
int i, j;
isprime[0] = false;
isprime[1] = false;
for(i = 2; i < 100; i++) /*\u5148\u521d\u59cb\u53162~100\u7684\u90fd\u662f\u7d20\u6570\uff0c\u7136\u540e\u5c06\u975e\u7d20\u6570\u7b5b\u9664\u6389*/
isprime[i] = true;
for(i = 2; i < 10; i++) /*\u5c06\u6240\u6709\u542b\u6709\u5c0f\u4e8e10\u7684\u8d28\u56e0\u5b50\u7684\u6570\u7b5b\u9664\u6389*/
{
if(isprime[i]) /*\u5982\u679ci\u662f\u7d20\u6570,\u5219\u5c06\u5b83\u7684\u500d\u6570\u5168\u90e8\u7b5b\u6389*/
for(j = i * i; j < 100; j += i) /*\u4ecei*i\u5f00\u59cb\u68c0\u6d4b\u662f\u56e0\u4e3a\u5c0f\u4e8ei*i\u7684\u5408\u6570\u90fd\u88ab\u5c0f\u4e8ei\u7684\u7d20\u6570\u7b5b\u9664\u4e86*/
isprime[j] = false;
}
for(i = 2; i < 100; i++)
if(isprime[i])
printf("%d ", i);
}

\u4f60\u4e00\u5f00\u59cb\u662f\u60f3\u7528m\u6765\u8868\u793a\u662f\u4e0d\u662f\u7d20\u6570\uff0c\u5230\u540e\u9762\u600e\u4e48\u8f93\u51fa\u7684\u662fi\u53d8\u91cf\u4e86\uff0c\u8fd8\u6709\u4ee3\u7801\u98ce\u683c\u6bd4\u8f83\u5dee\uff0c\uff0c\u867d\u7136\u6211\u4e5f\u662f\u65b0\u624b\u3002\u3002
# include

int main(void)
{
int n, i, flag ;

for( n = 2; n <= 100; n++ )
{
flag = 0;//\u6bcf\u4e00\u6b21\u90fd\u8981\u91cd\u65b0\u6539\u53d8
for( i = 2; i <= n/2; i++ )
{
if( n%i == 0 )
{
flag = 1;//\u6539\u53d8\u72b6\u6001
break;
}
}
if( !flag )
printf("%d\n", n);
}
return 0;
}

#include <stdio.h>
int main()

int i,j,a[100];
for(i=0;i<100;i++)
a[i]=i+1;
for(i=1;i<100;i++)
{
for(j=2;j<a[i];j++)
if(a[i]%j==0) break;
if(j>=a[i]) printf("%d ",a[i]);
}
return 0;
}


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