求高手帮帮忙啊，这两道N阶行列式怎么求。恳请回答啊，突击线代呀。
\u7ebf\u4ee3\u65b0\u624b\u9898\u3002\u3002\uff1a\u884c\u5217\u5f0fD\u600e\u4e48\u62c6\u5f00\u6210n\u4e2a\u884c\u5217\u5f0f\u7684\uff0c\u5229\u7528\u4e86\u884c\u5217\u5f0f\u7684\u54ea\u4e2a\u5b9a\u7406\uff1f\u3000\u3000\u8fd9\u91cc\u7528\u7684\u662f\u884c\u5217\u5f0f\u7684\u6027\u8d28\u4e4b\u4e00\uff1a\u82e5\u884c\u5217\u5f0f\u7684\u67d0\u884c\uff08\u5217\uff09\u7684\u5143\u7d20\u90fd\u662f\u4e24\u6570\u4e4b\u548c\uff0c\u5219\u8be5\u884c\u5217\u5f0f\u53ef\u5206\u89e3\u4e3a\u4e24\u4e2a\u884c\u5217\u5f0f\u4e4b\u548c\u3002
\u770b\u56fe\u8be6\u89e3\uff1a
~\u5982\u679c\u60a8\u8ba4\u53ef\u6211\u7684\u56de\u7b54\uff0c\u8bf7\u53ca\u65f6\u70b9\u51fb\u3010\u91c7\u7eb3\u4e3a\u6ee1\u610f\u56de\u7b54\u3011\u6309\u94ae~
~\u624b\u673a\u63d0\u95ee\u8005\u5728\u5ba2\u6237\u7aef\u4e0a\u8bc4\u4ef7\u70b9\u3010\u6ee1\u610f\u3011\u5373\u53ef~~
~\u60a8\u7684\u91c7\u7eb3\u662f\u6211\u524d\u8fdb\u7684\u52a8\u529b~~
~\u5982\u8fd8\u6709\u65b0\u7684\u95ee\u9898\uff0c\u8bf7\u53e6\u5916\u5411\u6211\u6c42\u52a9\uff0c\u7b54\u9898\u4e0d\u6613\uff0c\u656c\u8bf7\u8c05\u89e3~~
~\u795d\u5b66\u4e60\u8fdb\u6b65\uff0c\u66f4\u4e0a\u4e00\u5c42\u697c\uff01O(\u2229_\u2229)O~
第1行乘 -1 加到其余各行, 行列式化为上三角形式
主对角线上元素为 1,1,2,3,...,n-1
所以 D = (n-1)!
第二个需用展开定理及递归关系
D1 = 2*1^1
D2 = 3*2^2
D3 = 4*3^3
猜测 Dn = (n+1)* n^n
假设<n时成立, Dn时 按第1列展开得
Dn = 2nDn-1 - n^2Dn-2
= 2n * n*n^(n-1) - n^2 * (n-1) * n^(n-2)
= 2n*n^n - (n-1)n^n
= (n+1)n^n
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