A点距水准点1.976km,水准测量时中间折返16次,其允许误差是,如何计算？求公式 水准测量中，若水准基点离工地4000m远，中间转折了16次，...
A\u70b9\u8ddd\u6c34\u51c6\u70b91.976km,\u6c34\u51c6\u6d4b\u91cf\u65f6\u4e2d\u95f4\u8f6c\u629816\u6b21,\u5141\u8bb8\u7684\u8bef\u5dee\u662f\u8fd9\u4e2a\u662f\u8981\u770b\u4f60\u7684\u5730\u5f62\u4e86 \u5982\u679c\u662f\u5c71\u5730 \u90a3\u4e48\u5c31\u752812\u500d\u6839\u53f7n,\u5982\u679c\u662f\u5e73\u5766\u5730\u533a\u5c31\u8981\u752812\u500d\u6839\u53f7L
n\u4ee3\u8868\u6d4b\u7ad9\u6570 L\u4ee3\u8868\u8ddd\u79bb
\u600e\u4e48\u7b97\u7684\u6c42\u516c\u5f0f\uff0c\u4e0d\u77e5\u9053\u7b97
等外级的允许闭合差fh≤±40√L (mm);四等的允许闭合差fh≤±20√L (mm);三等的允许闭合差fh≤± 12√L (mm) ;二等的允许闭合差fh≤±4√L (mm) L为公里，误差fh单位为mm,所以二等测量允许误差结果为fn=4*√1.976=4*1.4057=5.6mm
绛旓細绛夊绾х殑鍏佽闂悎宸甪h鈮ぢ40鈭歀 (mm);鍥涚瓑鐨勫厑璁搁棴鍚堝樊fh鈮ぢ20鈭歀 (mm);涓夌瓑鐨勫厑璁搁棴鍚堝樊fh鈮ぢ 12鈭歀 (mm) ;浜岀瓑鐨勫厑璁搁棴鍚堝樊fh鈮ぢ4鈭歀 (mm) L涓哄叕閲岋紝璇樊fh鍗曚綅涓簃m,鎵浠ヤ簩绛夋祴閲忓厑璁歌宸粨鏋滀负fn=4*鈭1.976 =4*1.4057=5.6mm ...
绛旓細杩欎釜鏄鐪嬩綘鐨勫湴褰簡 濡傛灉鏄北鍦 閭ｄ箞灏辩敤12鍊嶆牴鍙穘,濡傛灉鏄钩鍧﹀湴鍖哄氨瑕佺敤12鍊嶆牴鍙稬 n浠ｈ〃娴嬬珯鏁 L浠ｈ〃璺濈
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