解下列方程:(1)x^2=36 (2)(2x-1)^2=25 (3)2x^2+7x=0 (4)x^2-6x=-9（5）（x+2)^2=(2x+1)^2 用适当方法解下列方程 1.（x+3）^2=5(3+x) 2....
\u89e3\u4e0b\u5217\u65b9\u7a0b\uff1a\uff081\uff096/x+4-3/x-1=0 \uff082\uff09x/2x-5-5/x-2x=1 \uff083\uff09x+1/x-2=x-3/x-4 \uff084\uff092/x+1+3/x-1=6/x^-1 \uff08\u89e3\u4e0b\u5217\u65b9\u7a0b\uff1a
\uff081\uff096/x+4-3/x-1=0
\u89e3\uff0c\u5f97\uff1a
6+4x-3-x=0
3x=-3
x=-1
\uff082\uff09x/2x-5-5/x-2x=1
\u89e3\uff0c\u5f97\uff1a
1/2-5-5/x-2x=1
x-10x-4x^2=2x
4x^2+2x-x+10x=0
4x^2+11x=0
x(4x+11)=0
x1=0
\u6216 x2=-11/4
\uff083\uff09x+1/x-2=x-3/x-4
\u89e3\uff0c\u5f97;
x^2+1-2x=x^2-3-4x
2x=-4
x=-2
\uff084\uff092/x+1+3/x-1=6/x^-1
\u89e3\uff0c\u5f97\uff1a
2/x+1+3/x-1=6x
2+x+3-x=6x^2
6x^2=5
x^2=5/6
x1=\u6839\u53f75/6
\u6216 x2=-\u6839\u53f75/6
1.\uff08x+3\uff09^2=5(3+x)
\uff08x+3)²-5(x+3)=0
(x+3)(x+3-5)=0
(x+3)(x-2)=0
x+3=0\u6216x-2=0
x=-3\u6216x=2
2. (2x-1)^2-4(2x-1)+4=0
\u6839\u636e\u5b8c\u5168\u5e73\u65b9\u516c\u5f0f\uff1a
\uff082x-1-2)^2=0
\u5373(2x-3)^2=0
\u22342x-3=0
\u2234x=3/2
(2))(2x-1)^2 - 25 = 0 [( 2x-1)-5 ] [(2x-1)+5 ]=0 ( 2x-1)-5 =0 ( 2x-1)+5 =0
x1=3 x2=-2
(3) x(2x+7)=0 x=0 2x+7=0 x1=0 x2= -7/2
(4) x^2-6x+9=0 (x - 3)^2 =0 x - 3 = 0 x1=x2 = 3
(5) （x+2)^2 -(2x+1)^2 = 0 [(x+2)-(2x+1)]*[(x+2)+(2x+1)]=0 (1-x)(3x+3)=0 1-x=0 3x+3 =0
x1=1 x2=-1
(6)9(x+3)^2 - (2x-5)^2=0 [3(x+3) - (2x - 5)][3(x+3) +(2x - 5)] =0 (x + 14)(5x + 4) = 0
x + 14 =0 5x + 4 =0
x1= -14 x2 = -4/5
（1）x=6or-6
（2）x=3 or x=-2
(3) x=0 or x=负二分之七
（4）x=3
(5)x=1 or x=-1
疯子啊这题谁会啊这是神马题呀
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