用C(α+β)推导公式cos(180°-α)=-cosα
cos\u03b1+cos(180-\u03b1)=?\u63a8\u5bfc\u8fc7\u7a0b\u53e3\u8bc0\u662f\u8fd9\u6837\u7684\uff1a90\u5ea6\u65f6\u53d8\u51fd\u6570\u7b26\u53f7\uff0c180\u5ea6\u65f6\u4e0d\u53d8\u51fd\u6570\u7b26\u53f7
\u03b1\u6c38\u8fdc\u5047\u5b9a\u7684\u8ba4\u4e3a\u662f\u5c0f\u4e8e90\u5ea6\u7684\uff0c\u770b\u5b83\u548c90,180\u76f8\u52a0\u51cf\u540e\u5728\u539f\u4e09\u89d2\u51fd\u6570\u4e2d\u7684\u7b26\u53f7\uff0c\u5b9a\u51fa\u7b26\u53f7\u3002
\u5982sin(\u03b1+90)=cos\u03b1,sin(90-\u03b1)=cos\u03b1
sin(180+\u03b1)=-sin\u03b1
\u539f\u9898:
cos\u03b1+cos(180-\u03b1)=cos\u03b1-cos\u03b1=0
\u8fd9\u4e2a\u53eb\u6b27\u62c9\u516c\u5f0f\uff0c\u5728\u9ad8\u7b49\u6570\u5b66\u4e2d\u7684\u7ea7\u6570\u90e8\u5206\uff0c\u4f1a\u8bb2\u5230\u3002\u5b83\u7684\u8bc1\u660e\u662f\u57fa\u4e8e\u6cf0\u52d2\u5c55\u5f00
\u5176\u4e2d
e^x=1+x+x^2/2!+\u2026\u2026+x^n/n!+\u2026\u2026
\u82e5\u628aix\u770b\u6210x\u5219
e^(ix)=1+ix-x^2/2!-ix^3/3!+x^4/4!+\u2026\u2026
\u800c
cosx=1-x^2/2++x^4/4!+\u2026\u2026+(-1)^n*x^(2n)/(2n)!+\u2026\u2026
sinx=x-x^3/3!+x^5/5!+\u2026\u2026+(-1)^(n-1)*x^(2n-1)/(2n-1)!+\u2026\u2026
\u6bd4\u8f83\u4e00\u4e0b
e^(ix)\u9a6c\u4e0a\u5c31\u6709e^(ix)=cos(x)+iSin(x)
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