已知弧长2000，拱高30，求帮忙算下半径多少，急用，谢谢！
\u5df2\u77e5\u5f27\u957f \u62f1\u9ad8 \u7b97\u534a\u5f84\u89e3\uff1a\u8bbe\u534a\u5f84\u4e3aR,\u6211\u7ed9\u56fe\u7ed9\u4f60\u3002\u5219\u534a\u5f27\u6240\u7684\u5bf9\u5e94\u7684\u5706\u5fc3\u89d2=1025/R.
\u6240\u4ee5cos\uff081025/R\uff09=\uff08R-500\uff09/R
\u4f60\u7528\u52fe\u80a1\u5b9a\u7406\u5217\u51fa\u6765\u7684\u65b9\u7a0b\u5316\u7b80\u540e\u4e5f\u662f\u8fd9\u4e2a\u65b9\u7a0b\u3002\u8fd9\u662f\u4e00\u4e2a\u8d85\u8d8a\u65b9\u7a0b\u3002\u4ee5\u9ad8\u4e2d\u7684\u6c34\u5e73\u65e0\u6cd5\u89e3
\u51fa\u6765\u3002
\u6211\u4e5f\u53ea\u80fd\u544a\u8bc9\u4f60\u65b9\u6cd5\uff0c\u6211\u81ea\u5df1\u4e5f\u89e3\u4e0d\u51fa\u6765\u3002\u5475\u5475\uff0c\u6211\u662f\u6b66\u6c49\u5927\u5b66\u6570\u5b66\u7cfb\u7684\u3002
\u6709\u95ee\u9898\u6765\u95ee\u6211\uff0c\u6211\u968f\u65f6\u5728\u7ebf\u00b7\u00b7\u00b7
\u5f27\u957f2050\uff0c\u62f1\u9ad8500\uff0c\u7b97\u534a\u5f84\uff0c\u6700\u597d\u8bf4\u4e0b\u600e\u4e48\u7b97\u7684
\u89e3\uff1a\u5df2\u77e5\u5f27\u957fL\uff1d2050\uff0c\u5f13\u5f62\u9ad8h=500\uff0c\u6c42\u534a\u5f84R.
\u8bbe\u56ed\u5fc3\u89d2\u4e3a\u03b8\uff0c\u5219R\u03b8=2050\uff0c\u03b8\uff1d2050/R
\u5f26\u957fb=2Rsin(\u03b8/2)=2Rsin(1025/R)
R=(b²+4h²)/8h=[4R²sin²(1025/R)+1000000]/4000
4R²sin²(1025/R)-4000R+1000000=0
R=?\u89e31\u6b64\u8d85\u8d8a\u65b9\u7a0b\uff01
已知“弧长”和“拱高”忙算半径就难了！
1、按“弦长”＝2000，用列方程的方法算得：R＝16681.67；
2、按“弧长”＝2000，用EXCEL “单变量求解”的方法算得：R＝16661.67
【因为半径较大，所以按“弦长”≈ “弧长”，二者算出来的半径差不多】
已知弧长C=2000，拱高H=30，求帮忙算下半径R多少?
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=16000
R1=16611.14
R2=16661.36
R3=16661.66
R4=16661.66
R=16661.66
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绛旓細宸辩煡鐜勯暱 L=3100鎷遍珮H=900姹傚姬闀C锛熷姬鍗婂緞涓篟锛屽姬鎵瀵圭殑鍦嗗績瑙掍负A銆俁=H/2+L^2/(8*H)=900/2+3100^2/(8*900)=1784.722 A=2*ARC COS((R-H)/R)=2*ARC COS((1784.722-900)/1784.722)=120.566搴 C=蟺*R*A/180=蟺*1784.722*120.566/180=3755.53 ...
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