java截取字符串,重新组装新的字符串的问题 Java 怎么取出一个字符串中的数字 并加上一个数 再把原来...
java\u622a\u53d6\u6307\u5b9a\u5b57\u7b26\u4e32\u4e2d\u7684\u67d0\u6bb5\u5b57\u7b26\u5982\u4f55\u5b9e\u73b0\uff1f\u5982\u4e0b\u56fe\uff0c\u7ed9\u4f60\u8d34\u51fa\u4e86\u4ee3\u7801\u6bb5\u3002\u53ef\u4ee5\u5229\u7528\u5b57\u7b26\u4e32\u7684substring\u51fd\u6570\u6765\u8fdb\u884c\u622a\u53d6\u3002
\u5176\u4e2d\uff0csubstring\u51fd\u6570\u6709\u4e24\u4e2a\u53c2\u6570\uff1a
1\u3001\u7b2c\u4e00\u4e2a\u53c2\u6570\u662f\u5f00\u59cb\u622a\u53d6\u7684\u5b57\u7b26\u4f4d\u7f6e\u3002\uff08\u4ece0\u5f00\u59cb\uff09
2\u3001\u7b2c\u4e8c\u4e2a\u53c2\u6570\u662f\u7ed3\u675f\u5b57\u7b26\u7684\u4f4d\u7f6e+1\u3002\uff08\u4ece0\u5f00\u59cb\uff09
indexof\u51fd\u6570\u7684\u4f5c\u7528\u662f\u67e5\u627e\u8be5\u5b57\u7b26\u4e32\u4e2d\u7684\u67d0\u4e2a\u5b57\u7684\u4f4d\u7f6e\uff0c\u5e76\u4e14\u8fd4\u56de\u3002
\u6269\u5c55\u8d44\u6599\uff1a
substring\u8fd9\u4e2a\u51fd\u6570\u4e5f\u53ef\u4ee5\u53ea\u5199\u4e00\u4e2a\u53c2\u6570\uff0c\u5c31\u662f\u8d77\u59cb\u5b57\u7b26\u4f4d\u7f6e\u3002\u8fd9\u6837\u5c31\u4f1a\u81ea\u52a8\u622a\u53d6\u4ece\u5f00\u59cb\u5230\u6700\u540e\u3002
\u4f8b\u5982\uff1a
\u7ed3\u679c\u662f\uff1a456789\uff08\u6ce8\u610f\uff1a\u5305\u62ec4\u3002\uff09
\u793a\u4f8b\uff1a
"hamburger".substring(3,8) returns "burge"
"smiles".substring(0,5) returns "smile"
\u53c2\u8003\u8d44\u6599\uff1a\u767e\u5ea6\u767e\u79d1\u2014\u2014substring
\u5b9e\u73b0\u601d\u8def\u5c31\u662f\u5224\u65ad\u5b57\u7b26\u4e32\u4e2d\u7684\u6bcf\u4e00\u4e2a\u5b57\u7b26\u662f\u5426\u4e3a\u6570\u5b57\uff0c\u4e4b\u540e\u5faa\u73af\u5224\u65ad\u4e0b\u4e00\u4e2a\u662f\u4e0d\u662f\uff0c\u662f\u7684\u8bdd\u5c31\u62fc\u63a5\uff0c\u548c\u7ee7\u7eed\u7684\u4e00\u4e2a\u7ec4\u6210\u5b57\u7b26\u4e32\uff0c\u7ee7\u7eed\u5224\u65ad\uff0c\u76f4\u8fbe\u4e0d\u6ee1\u8db3\u6761\u4ef6\u8f93\u51fa,\u4e4b\u540e\u76f4\u63a5\u66ff\u6362\u6389\u4e4b\u524d\u7684\u503c\u5373\u53ef\u3002
String str = "this class 12 teachers";
String num = "";
for (int i = 0; i < str.length(); i++) {
String isNum = str.substring(i, i + 1);
int a = 0;
try {
a = Integer.parseInt(isNum);//\u5224\u65ad\u662f\u4e0d\u662f\u53ef\u4ee5\u8f6c\u6362\u4e3a\u6570\u7ec4
num = num + a;
} catch (Exception e) {
num =num;
}
}
int sum = Integer.parseInt(strNum)+32\uff1b//\u91cd\u65b0\u8d4b\u503c
str = str .replaceAll(num,sum+"");//\u66ff\u6362\u6389\u4e4b\u524d\u7684\u503c
import java.util.List;
public class CutString {
public static void main(String[] args){
String str = "1,2,3,4,5,6,7,8,9,10,21,2,3,4";
String t[] = str.split(",");
List<String> list = new ArrayList<String>();
String temp = "";
for(int i=0;i<t.length;i++){
temp = temp+ t[i]+",";
if((i+1)%3 == 0){
temp = temp.substring(0,temp.length()-1);
list.add(temp);
temp = "";
}
}
if(!"".equals(temp)){
list.add(temp.substring(0,temp.length()-1));
}
for(String s:list){
System.out.println(s);
}
}
}
------------运行----------------
1,2,3
4,5,6
7,8,9
10,21,2
3,4
都放在list之中显示，不知道可以不
-----------------或者这样-----------------
//但数字都为1位数的时候，不会出问题，
但如果到了10，11，12，就会有问题
public class CutString {
public static void main(String[] args){
String str = "1,2,3,4,5,6,7,8,9,10";
String s = CutString.cutString(str);
String t[] = s.split(":");
for(int i=0;i<t.length;i++)
System.out.println(t[i]);
}
public static String cutString(String s){
if(s.length()>5){
return (s.substring(0,5) +":"+cutString(s.substring(6)));
}else{
return s;
}
}
}
String b = a.subString(0,3);
注意:subString(int1,int2)方法截取字符串时,int1为起始位置(包括该位置的字符),int2为结束位置(不包括该位置的字符),即[int1,int2)..
如:"abcd".subString(0,2);结果为"ab".....
public class StrText1 {
public static void main(String[] asd){
String s="asd,sdfr,fd,dert,fdesa,dfghjkiu,dsf";//未被分割的字符串
String[] str=new String[s.length()];//存放分割后的子字符串
String s1=s;//每次分割后剩余的字符串
int j=0;
for(int i = 0;i<s.length();i++){
j=s1.indexOf(',');//第一次出现','的位置
if(j==-1){
str[i]=s1;
break;
}
str[i]=s1.substring(0,j);
s1=s1.substring(j+1);
}
for(int i=0;i<str.length;i++){
if(str[i]!=null&&str[i]!=""){
System.out.print(" "+str[i]);
}
}
}
}
楼上的对，用subString()函数
String b = a.subString(0,3);
String c = a.subString(3,6);
String d = a.subString(6,9);
String f = a.subString(9);
绛旓細import java.util.ArrayList;import java.util.List;public class CutString { public static void main(String[] args){ String str = "1,2,3,4,5,6,7,8,9,10,21,2,3,4";String t[] = str.split(",");List<String> list = new ArrayList<String>();String temp = "";for(int ...
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