数学老师在线解答？ 数学老师在线解答
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第一问第二空，通过前面可得当角ABC+角α＝180度时，前一问结论成立，所以角ABC应等于60度
第二问拓展提升，因为角ABC等于α，又从题目得角AEB＝角BDC＝α，构成一线三等角，通过已知条件易证两个三角形仍然全等，由全等得边相等，得出等式DE＝BE+BD＝DC+AE，所以结果为DE＝AE+DC
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