老师发本子给若干名同学,如果每人发3本还剩8本,若每人发5本,有一名同学不满5本,问一共有几名同学? 问: 老师把若干本练习本分给几个学生,若每人分得3本,则多余...

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\u4e00\u5171\u67095\u4e2a\u5b66\u751f\u62166\u4e2a\u5b66\u751f\u3002

\u8bbe\u6709X\u4e2a\u5b66\u751f\uff0cY\u672c\u7ec3\u4e60\u672c\u3002
3X+8=Y 5X>Y 5(X-1)<Y
\u89e3\u5f97 4<X<6.5
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设有X名同学、若每人发5本那个不满5本的同学有Y本
3x+8=5(x-1)+(5-Y)
3x+8=5x-5+(5-Y)
3x-5x+y=-8
-2x+y=-8
2x+y=8
假设那个不满5本的同学拿了2本
2X+2=8
x=3
验算:3*3+8=17(本)
3*5+2=17(本)所以一共有3名同学

同学为x人,则3x+8-5(x-1)<5,3x+8-5(x-1)>0
解出x>4且x<6.5
所以4<X<6.5
且取整数 所以x=5或6
答:有5名同学或6名同学。

设本子为y,同学为x,则y=3x+8<5x,解出x>4
设x=5,y=3×5+8=23本<5×5;
设x=6,y=3×6+8=26本<5×6;
所以最终结果是:x>4

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