某科学兴趣小组的同学在实验室发现一个有趣的电子元件R1 在线好加分
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P=UI=90V\u00d71.2A=108W\uff0e
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\u6545\u7b54\u6848\u4e3a\uff1a\uff081\uff0975\uff1b108
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\u2234U=U1\u2032+U0\u2032=U1\u2032+I0\u2032R0=U1\u2032+I1\u2032R0
\u5373U1\u2032+100\u03a9I1\u2032=220V\uff0cU1\u2032\u662f\u5173\u4e8eI1\u2032\u4e00\u6b21\u51fd\u6570\uff0c\u662f\u4e00\u6761\u76f4\u7ebf\uff0e
\u5f53U1\u2032=0V\uff0cI1\u2032=2.2A\uff1b\u5f53I1\u2032=0A\uff0cU1\u2032=\uff0c220V\uff1b
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U1\u2032=110V\uff0cI1\u2032=1.1A
\u2234P1\u2032=U1\u2032I1\u2032=110V\u00d71.1A=121W
\u5373\uff1aR1\u7684\u5b9e\u9645\u529f\u7387\u4e3a121W\uff0e
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因为R1阻值随电压而变化，所以把元件R1与阻值为100Ω的定值电阻R0串联后接到220V的电源上后，其实际工作电压要由甲图查出，曲线为R1，直线为R0，两者的交点即为实际工作点，由图可知，U=110V，I=1.1A，所以R1的实际功率P=IU=110VX1.1A=121W绛旓細姘㈡哀鍖栭挔璐ㄩ噺锛200 gx 8% =16g 姘寸殑璐ㄩ噺锛200g-16g=184g 姘寸殑瀵嗗害涓轰竴鍏嬫瘡绔嬫柟绫筹紝鎵浠ヤ綋绉负184mL
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