职高数学题 职高数学题！~~
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2n^-15n-50=0推出(n-10)(2n-5)=0得，n=10或n=5/2.
祝更上一层楼！
解：
50=[n²/2-n/2]x4-13n
50=2n²-15n
0=2n²-15n-50
0=(2n+5)（n-10）
n=-5/2或n=10
望采纳
50=-13n+2n²-2n
2n²-15n-50=0
(2n+5)(n-10)=0
n=-5/2,n=10
30km/h=(25/3)m/s 10秒走了(250/3)m 半径2km推得周长4πkm=4000πm (250/3)/4000π=（5/240）πm 所以转过的角度等于((5/240)/4000)π,
4
绛旓細浣犲ソ锛屽寲鎴愭渶绠寮忥紝-13n+2n^2-2n=50 2n^-15n-50=0鎺ㄥ嚭(n-10)(2n-5)=0寰楋紝n=10鎴杗=5/2.绁濇洿涓婁竴灞傛ゼ锛
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