Linux中使用awk输出一段字符中指定的内容 linux awk怎么单独取出某一行某一段字符
awk\u5982\u4f55\u83b7\u53d6\u7279\u5b9a\u5b57\u7b26\u4e32\u4e4b\u95f4\u7684\u4fe1\u606f\u4f60\u53ef\u4ee5\u4f7f\u7528linux cut \u9009\u53d6\u547d\u4ee4\u3002
\u65b9\u6cd5\uff1a
1. \u4f60\u628a\u4e0a\u9762\u4e09\u884c\u5199\u5165\u4e00\u4e2a\u6587\u4ef6\u4e2d vim file
2. \u6d4b\u8bd5cut\u547d\u4ee4 \u4f60\u7684shell\u8f93\u5165\uff1acut -d '=' -f 2 file
\u89e3\u91ca\uff1a\u4ee5=\u4e3a\u5206\u9694\u7b26\uff0c\u83b7\u53d6\u7b2c\u4e8c\u90e8\u5206\uff0c\u83b7\u53d6=\u540e\u9762\u7684\u90e8\u5206
3. \u719f\u6089cut\u547d\u4ee4\u540e\uff0c\u4f60\u5728shell\u8f93\u5165
cut -d '=' -f 2 file | cut -d '"' -f 1
\u89e3\u91ca\uff1a\u7b2c\u4e00\u6b21\u6267\u884c\u7684\u8f93\u51fa\u4f5c\u4e3a\u7ba1\u9053\u547d\u4ee4 | \u540e\u9762\u547d\u4ee4\u7684\u53c2\u6570\u3002
\u83b7\u53d6\u7b2c\u4e00\u4e2a = \u540e\u9762\u7684\u90e8\u5206\uff0c\u518d\u83b7\u53d6\u7b2c\u4e00\u4e2a " \u524d\u9762\u7684\u90e8\u5206\u3002
\u4f60\u53ef\u4ee5\u641c\u7d22linux cut\u547d\u4ee4
\u793a\u4f8b\uff1a\u6253\u5370install.log\u6587\u4ef6\u4e2d\u7b2c\u4e94\u884c\uff0c\u7b2c\u4e8c\u6bb5\uff08\u6309\u7167\u7a7a\u683c\u5206\u6bb5\uff09\u7684\u6587\u5b57\uff1a
2: eth0:mtu 1500 qdisc pfifo_fast state UP qlen 1000
link/ether fa:16:3e:85:5a:08 brd ff:ff:ff:ff:ff:ff
inet 192.168.0.18/24 brd 192.168.0.255 scope global dynamic eth0
valid_lft 83317sec preferred_lft 83317sec
inet6 fe80::f816:3eff:fe85:5a08/64 scope link
valid_lft forever preferred_lft forever
root@ubuntu:~# cat 1|awk -F"[ /]+" '/inet /{print $3}'
192.168.0.18
绛旓細root@ubuntu:~# cat 1|awk -F"[ /]+" '/inet /{print $3}'192.168.0.18
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