盐和碱反应的化学方程式 列举盐和碱的化学方程式
\u6c42\u76d0\u4e0e\u78b1\u53cd\u5e94\u7684\u5316\u5b66\u65b9\u7a0b\u5f0f\u78b1 + \u76d0
Ca(OH)2+Na2CO3=CaCO3\u2193+2NaOH
Ba(OH)2+K2CO3=BaCO3\u2193+2KOH
2NaOH + CuSO4 ==== Cu(OH)2\u2193 + Na2SO4
2KOH + CuCl2 ==== Cu(OH)2\u2193 + 2KCl
3NaOH + FeCl3 ==== Fe(OH)3\u2193 + 3NaCl
6NaOH + Fe2(SO4)3 ==== 2Fe(OH)3\u2193 + 3Na2SO4
2NaOH + MgCl2 ==== Mg(OH)2\u2193 + 2NaCl
2KOH + MgSO4 ==== Mg(OH)2\u2193 + K2SO4
6NaOH+Al2(SO4)3=2Al(OH)3\u2193+3Na2SO4
Ba(OH)2+ CuSO4 ==== Cu(OH)2\u2193 + BaSO4\u2193
Ba(OH)2+ MgSO4 ==== Mg(OH)2\u2193 + BaSO4\u2193
Ba(OH)2+K2CO3=BaCO3\u2193+2KOH
\u76d0 + \u76d0
NaCl + AgNO3 ==== AgCl\u2193 + NaNO3
Na2SO4 + BaCl2 ==== BaSO4\u2193 + 2NaCl
CaCl2+Na2CO3=CaCO3\u2193\uff0b2NaCl
BaCl2+Na2CO3=BaCO3\u2193\uff0b2NaCl
2AgNO3+Na2CO3=Ag2CO3\u2193\uff0b2NaNO3
BaCl2+K2CO3=BaCO3\u2193\uff0b2KCl
CaCl2+K2CO3=CaCO3\u2193\uff0b2KCl
2AgNO3+K2CO3=Ag2CO3\u2193\uff0b2KNO3
NaCl+AgNO3=AgCl\u2193+NaNO3
BaCl2+Na2SO4=BaSO4\u2193\uff0b2NaCl
BaCl2+K2SO4=BaSO4\u2193\uff0b2KCl
AgNO3+KCl=AgCl\u2193+KNO3
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2.Ba(OH)2+CuSO4=== Cu(OH)2↓+BaSO4↓
3.Ba(OH)2+(NH4)2SO4=== BaSO4↓+2NH3↑+2H2O
4.NaOH+NH4Cl=== NaCl+NH3↑+H2O.
Fe2(SO4)3+6NaOH===2Fe(OH)3↓+2Na(SO4)3
Ba(OH)2+CuSO4=BaSO4(沉淀)+Cu(OH)2(沉淀)
（NH4)2CO3+Ca(OH)----NH3(气体)+CaCO3(沉淀)+2H2O
2NH4Cl+Ca(OH)2=CaCl2+2NH3+2H2O
1.Fe2(SO4)3+6NaOH=2FeOH3↓+3Na2SO4
2.Fe2(SO4)3+3Ba(OH)2=2FeOH3↓+3BaSO4↓
3.(NH4)2CO3 + Ca(OH)2 = CaCO3↓ + 2 NH3 ↑ + 2 H2O
4.（NH4)2SO4+Ba(OH)2=BaSO4↓+2NH3·H2O
FeCl3+3NaOH==Fe(OH)3↓+3NaCl
Ba(OH)2 + CuSO4 = ＝BaSO4↓ + Cu(OH)2↓
（NH4)2CO3+Ca(OH)＝＝NH3↑+CaCO3↓+2H2O
NH4NO3＋NaOH＝＝NH3`H20＋NaNO3
1.FeCl3 +3NaOH = Fe(OH)3↓+ 3NaCl
Fe2(SO4)3+6NaOH===2Fe(OH)3↓+2Na(SO4)3
2.Ba(OH)2+CuSO4=BaSO4↓+Cu(OH)2↓
3.(NH4)2CO3+Ca(OH)----NH3↑+CaCO3↓+2H2O
4.2NH4Cl+Ca(OH)2=CaCl2+2NH3·H2O
绛旓細鐩愬拰纰卞弽搴旂殑鍖栧鏂圭▼寮忎妇渚嬪涓嬶細1銆丯aHCO3+NaOH=Na2CO3+H2O 2銆丆uSO4+2NaOH=Cu锛圤H锛2鈫+Na2SO4 3銆丯a2SO4+Ba锛圤H锛2=BaSO4鈫+2NaOH 4銆並HSO4+KOH=K2SO4+H2O 5銆丄lCl3+3KOH=Al锛圤H锛3鈫+3KCl
绛旓細4.NaOH+NH4Cl=== NaCl+NH3鈫+H2O.
绛旓細鐩愬姞纰辩敓鎴愭柊鐩愬姞鏂扮⒈鐨勫寲瀛︽柟绋嬪紡濡備笅锛1銆佺⒊閰搁挔锛圢a2CO3锛夊拰姘㈡哀鍖栭挋锛圕a(OH)2锛夌殑鍙嶅簲锛歂a2CO3锛堢洂锛+ Ca(OH)2锛堢⒈锛 鈫 CaCO3锛堟柊鐩愶級+ 2NaOH锛堟柊纰憋級銆傝繖涓弽搴斿湪宸ヤ笟涓婅骞挎硾浣跨敤锛屽洜涓虹敓鎴愮殑纰抽吀閽欐槸涓绉嶅父瑙佺殑寤虹瓚鏉愭枡锛岃屾阿姘у寲閽犲垯鏄竴绉嶅父瑙佺殑宸ヤ笟鍘熸枡銆2銆佺～閰搁摐锛圕uSO4锛夊拰姘...
绛旓細鐩愬拰纰卞弽搴旂敓鎴愬彟涓绉嶇洂鍜屽彟涓绉嶇⒈銆渚嬪姘㈡哀鍖栭挔涓庣～閰搁摐鍙嶅簲锛2NaOH+CuSO4===Cu(OH)2鈫+Na2SO4锛屾阿姘у寲閽犱笌姘寲閾佸弽搴旂殑鍖栧鏂圭▼寮忥細3NaOH+FeCl3===Fe(OH)3鈫+3NaCl銆傜⒈鍦ㄥ寲瀛︿笂绉拌兘鍦ㄦ按婧舵恫涓數绂昏岀敓鎴愭阿姘х瀛愶紙OH-锛夌殑鍖栧悎鐗╋紝濡傛阿姘у寲閽犵瓑銆傛憾娑插叿鏈夋订鍛筹紝鑳戒娇鐭宠晩璇曠焊鍙樿摑锛岃兘璺熼吀...
绛旓細鐩愬拰纰卞弽搴旂敓鎴愬彟涓绉嶇洂鍜屽彟涓绉嶇⒈銆渚嬪姘㈡哀鍖栭挔涓庣～閰搁摐鍙嶅簲锛2NaOH+CuSO4===Cu(OH)2鈫+Na2SO4锛屾阿姘у寲閽犱笌姘寲閾佸弽搴旂殑鍖栧鏂圭▼寮忥細3NaOH+FeCl3===Fe(OH)3鈫+3NaCl銆傚寲瀛︿笂绉拌兘鍦ㄦ按婧舵恫涓數绂昏岀敓鎴愭阿姘х瀛愶紙OH-锛夌殑鍖栧悎鐗╋紝濡傛阿姘у寲閽犵瓑銆傛憾娑插叿鏈夋订鍛筹紝鑳戒娇鐭宠晩璇曠焊鍙樿摑锛岃兘璺熼吀涓拰...
绛旓細2NaOH+SO2=NA2SO3(浜氱～閰搁挔)+H2O 纰锛堝彲婧讹級+鐩锛堝彲婧讹級=鏂扮⒈+鐩愶紙鏈夌敓鎴愭矇娣锛塁a锛圤H)2+Na2CO3=2NaOH+CaCO3鈫 閰+閲戝睘锛堥噾灞炴椿鍔ㄦф帓鍦℉鍓嶉潰锛=鐩+姘㈡皵 Hcl+Fe=FeCL2+H2鈫 閰+閲戝睘姘у寲鐗=鐩+姘 2HCL+CuO=CuCL2+H2O 閿屼笌绋纭吀Zn + H2SO4 = ZnSO4 + H2鈫 閾佸拰绋纭吀Fe + H2SO4...
绛旓細1.3NaOH+FeCl3=== Fe(OH)3鈫 + 3NaCl 2.Ba(OH)2+CuSO4=== Cu(OH)2鈫+BaSO4鈫 3.Ba(OH)2+(NH4)2SO4=== BaSO4鈫+2NH3鈫+2H2O 4.NaOH+NH4Cl=== NaCl+NH3鈫+H2O.
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绛旓細1銆丯aOH+NH₃Cl=NaCl+NH₃+H₂O 2銆2NaOH+CuCl₂=Cu(OH)₂鈫+2NaCl 3銆丆a(OH)₂ + Na₂CO₃ = CaCO₃鈫+ 2NaOH 鍙嶅簲鏉′欢鏄細纰卞拰鐩鍧囧彲婧讹紝甯歌涓寮虹⒈鍜屽急鐩愬弽搴鐢熸垚寮辩⒈鍜屽己鐩愩傚弽搴旂墿涓湁娌夋穩鎴栨槸姘斾綋浜х敓銆
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