C语言程序：题目：从键盘输入一个字符串，按照字符顺序从小到大进行排序，并要求删除重复的字符。答案如下 C语言。从键盘接收一个字符串，然后按照字符顺序从小到大进行排...
C\u8bed\u8a00\u7a0b\u5e8f\uff1a\u9898\u76ee\uff1a\u4ece\u952e\u76d8\u8f93\u5165\u4e00\u4e2a\u5b57\u7b26\u4e32\uff0c\u6309\u7167\u5b57\u7b26\u987a\u5e8f\u4ece\u5c0f\u5230\u5927\u8fdb\u884c\u6392\u5e8f\uff0c\u5e76\u8981\u6c42\u5220\u9664\u91cd\u590d\u7684\u5b57\u7b26\u3002\u7b54\u6848\u5982\u4e0b#include
#include"string.h"
int
main(void)
{
char
str1[500]={0},str2[256]={0};//\u5b9a\u4e49\u4e8c\u4e2a\u6570\u7ec4\uff0c\u5e76\u8d4b\u521d\u503c\u4e3a0
int
i;
gets(str1);//\u8bfb\u53d6\u4e00\u4e2a\u5b57\u7b26\u4e32
for(i=0;str1[i];i++)
{
str2[str1[i]]=1;//str1\u4e2d\u6bcf\u4e2a\u5b57\u7b26\u7684assic\u7801\u4f5c\u4e3astr2\u7684\u4e0b\u6807\u503c\uff0c\u5e76\u628a\u5bf9\u5e94\u4f4d\u7f6e\u586b\u5145\u4e3a1\uff0c\u540c\u4e00\u4e2a\u5b57\u7b26\u7684assci\u503c\u76f8\u540c\uff0c\u6240\u4ee5\u8fd9\u6837\u5c31\u53bb\u6389\u4e86\u91cd\u590d\u5b57\u7b26
}
for(i=0;i!=256;i++)
if(str2[i]==1)//\u5224\u65ad\u6570\u7ec4\u4e2d\u88abstr1\u586b\u5145\u7684\u4f4d\u7f6e\uff0c\u586b\u5145\u7684\u662f\u975e0\u503c\uff0c\u6ca1\u586b\u5145\u7684\u662f0\u503c
printf("%c",i);//\u8f93\u51fastr2\u7684\u4e0b\u6807\u503c\uff0c\u5bf9\u5e94str1\u4e2d\u7684\u5b57\u7b26\u503c
putchar('\n');
return
0;
}
1 A 2 B 3 D
\u4e0a\u673a\u8bd5\u8fc7\u7684
#include"string.h"
int main(void)
{
char str1[500]={0},str2[256]={0};//定义二个数组，并赋初值为0
int i;
gets(str1);//读取一个字符串
for(i=0;str1[i];i++)
{
str2[str1[i]]=1;//str1中每个字符的assic码作为str2的下标值，并把对应位置填充为1，同一个字符的assci值相同，所以这样就去掉了重复字符
}
for(i=0;i!=256;i++)
if(str2[i]==1)//判断数组中被str1填充的位置，填充的是非0值，没填充的是0值
printf("%c",i);//输出str2的下标值，对应str1中的字符值
putchar('\n');
return 0;
}
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