求高人！求代码！在java的字符串中如何替换指定位置的字符 java Sting 如何替换指定位置的 字符？
\u5728java\u7684\u5b57\u7b26\u4e32\u4e2d\u5982\u4f55\u66ff\u6362\u6307\u5b9a\u4f4d\u7f6e\u7684\u5b57\u7b26\uff1fString
s
=
"if
i
have
to
go,
go,go,do
you
remember
me?";
char[]
cs
=
s.toCharArray();
cs[12]
=
'A';
System.out.println(new
String(cs));
\u81f3\u4e8e\u66ff\u6362\u6307\u5b9a\u4f4d\u7f6e\u7684\u5b57\u7b26\u4e32\u5427,\u7528\u5207\u53d6\u5427
charAt()\u662f\u8fd4\u56de\u6307\u5b9a\u4e0b\u6807\u7684char\u600e\u4e48\u8fd8\u80fd\u7b26\u503c\u5462,\u9519\u662f\u5e94\u8be5\u7684
#include
#include
#include
\uff08\u6b64\u5904\u7a7a\u4e00\u884c\uff09
using namespace std;
int main()
{
string str="123/421657/abcd///456789";
\uff08\u6b64\u5904\u7a7a\u4e00\u884c\uff09
cout << str << endl;
replace(str.begin(),str.end(),'/',' ');
cout << str << endl;
return 0;
}
\u6ce8\uff1a\u4f7f\u7528StringBuilder\u6765\u6784\u5efa\u5b57\u7b26\u4e32\uff0c\u7136\u540e\u53ef\u4ee5\u4f7f\u7528strBuilder.setCharAt(1, '');\u6765\u4fee\u6539\u67d0\u4e00\u5b57\u7b26\uff0c\u5982\u679c\u8981\u5c06\u5b57\u7b26\u4e32\u7684\u6240\u6709\u7279\u5b9a\u5b57\u7b26\u5168\u90e8\u66ff\u6362\uff0cstring\u4e2d\u53ef\u4ee5\u4f7f\u7528replaceAll("","");\u65b9\u6cd5\u3002
\u6269\u5c55\u8d44\u6599\uff1aString\u5b57\u7b26\u4e32\u64cd\u4f5c
replace(oldChar, newChar)\u65b9\u6cd5\u53c2\u65701:\u8981\u88ab\u66ff\u6362\u7684\u5b57\u7b26,\u53c2\u65702:\u66ff\u6362\u8fdb\u53bb\u7684\u5b57\u7b26
\u8be5\u65b9\u6cd5\u7684\u4f5c\u7528\u662f\u66ff\u6362\u5b57\u7b26\u4e32\u4e2d\u6240\u6709\u6307\u5b9a\u7684\u5b57\u7b26\uff0c\u7136\u540e\u751f\u6210\u4e00\u4e2a\u65b0\u7684\u5b57\u7b26\u4e32\u3002\u7ecf\u8fc7\u8be5\u65b9\u6cd5\u8c03\u7528\u4ee5\u540e\uff0c\u539f\u6765\u7684\u5b57\u7b26\u4e32\u4e0d\u53d1\u751f\u6539\u53d8\u3002\u4f8b\u5982\uff1a
String s = "abcde8fghijk8lmn";
String a = s.replace('8', 'Q');
a\u7684\u503c\u4e3a"abcdeQfghijkQlmn"
char[] cs = s.toCharArray();
cs[12] = 'A';
System.out.println(new String(cs));
至于替换指定位置的字符串吧,用切取吧
charAt()是返回指定下标的char怎么还能符值呢,错是应该的
可以用 StringBuilder 这个类试试，里面有一个接口replace，如下
StringBuilder sb = new StringBuilder("sssaaa");
sb.replace(start, end, str);
你可以这样实现嘛！
String s="if i have to go, go,go,do you remember me?"
我想把第12个字符替换成'a'
s.replace(s.charAt(i),'a');
同理，
String x ="go";
s.replace(s.substring(s.charAt(s.indexof(x)),s.charAt(s.lastindexof(x))));
不过这样可能会出问题，需要仔细考虑，
String str = "13012345678";
System.out.println(str.replace(str.subSequence(3,9),"******"));
可以直接将字符串的第4位到倒数第三位全部替换成*
将4个1替换成4个3
String s = "001111222";
String s1 = s.replaceFirst("(?<=\\S{2}).{4}", "3333");
System.out.println(s1);
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